Hooke's Law in physics states that if a spring at rest (equilibrium position ) has a weight attached to it, then the distance the spring stretches is directly proportional to the force (weight).
F = kx
Where F is the force in Newtons(N), x is the distance stretched in meters (m), and k is the spring constant (N/m).
A force of 364 N will stretch the spring 28 cm. How far will a force of 468 stretch the spring? Round to two decimal places.
A) 0.22 m
B) 21.78 m
C) 0.36 m
D) 36 m

Question

Quizplus · Accepted Answer

First, convert 28 cm to meters by dividing by 100, which gives 0.28 m. Using Hooke's Law, F = kx, we can find the spring constant k with the given force of 364 N: k = F/x = 364 N / 0.28 m = 1300 N/m. To find the new distance x for a force of 468 N, rearrange the formula to x = F/k = 468 N / 1300 N/m = 0.36 m.

Hooke's Law in Physics States That If a Spring at Rest