Find the product
-$\left(-2 x^{2}-10 y\right)\left(-4 x^{2}-12 y+z\right)$

A) $8 x^{4}+64 x^{2} y^{2}+120 y^{2}$
B) $8 x^{2}+64 x y-2 x^{2} z+120 y^{2}-10 z$
C) $8 x^{4}+64 x^{2} y+120 y^{4}-2 x^{2} y z$
D) $8 x^{4}+64 x^{2} y-2 x^{2} z+120 y^{2}-10 y z$

Question

Find the product
-$\left(-2 x^{2}-10 y\right)\left(-4 x^{2}-12 y+z\right)$

A) $8 x^{4}+64 x^{2} y^{2}+120 y^{2}$
B) $8 x^{2}+64 x y-2 x^{2} z+120 y^{2}-10 z$
C) $8 x^{4}+64 x^{2} y+120 y^{4}-2 x^{2} y z$
D) $8 x^{4}+64 x^{2} y-2 x^{2} z+120 y^{2}-10 y z$

Quizplus · Accepted Answer

To find the product, each term in the first parenthesis is multiplied by each term in the second parenthesis and then the products are added together: $(-2x^2)(-4x^2) = 8x^4$, $(-2x^2)(-12y) = 24x^2y$, $(-2x^2)(z) = -2x^2z$, $(-10y)(-4x^2) = 40x^2y$, $(-10y)(-12y) = 120y^2$, $(-10y)(z) = -10yz$. Adding these together gives $8x^4 + (24x^2y + 40x^2y) - 2x^2z + 120y^2 - 10yz = 8x^4 + 64x^2y - 2x^2z + 120y^2 - 10yz$.

Find the Product - (−2x2−10y)(−4x2−12y+z)\left(-2 x^{2}-10 y\right)\left(-4 x^{2}-12 y+z\right)(−2x2−10y)(−4x2−12y+z) A) 8x4+64x2y2+120y28 x^{4}+64 x^{2} y^{2}+120 y^{2}8x4+64x2y2+120y2

Find the Product
- $\left(-2 x^{2}-10 y\right)\left(-4 x^{2}-12 y+z\right)$ A) $8 x^{4}+64 x^{2} y^{2}+120 y^{2}$