Find the product
-$(x-2)(3 x-1)$

A) $3 x^{2}-7 x-7$
B) $3 x^{2}-7 x+2$
C) $3 x^{2}+2 x-7$
D) $3 x^{2}-9 x+2$

Name: Find the product -$(x-2)(3 x-1)$ A) $3 x^{2}-7 x-7$ B) $3 x^{2}-7 x+2$ C) $3 x^{2}+2 x-7$ D) $3 x^{2}-9 x+2$
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Question

Find the product
-$(x-2)(3 x-1)$

A) $3 x^{2}-7 x-7$
B) $3 x^{2}-7 x+2$
C) $3 x^{2}+2 x-7$
D) $3 x^{2}-9 x+2$

Quizplus · Accepted Answer

To find the product $(x-2)(3x-1)$, we distribute each term in the first parenthesis by each term in the second parenthesis: $x \cdot 3x + x \cdot (-1) + (-2) \cdot 3x + (-2) \cdot (-1)$. Simplifying this gives $3x^2 - x - 6x + 2$, which simplifies further to $3x^2 - 7x + 2$.

Find the Product - (x−2)(3x−1)(x-2)(3 x-1)(x−2)(3x−1) A) 3x2−7x−73 x^{2}-7 x-73x2−7x−7 B) 3x2−7x+23 x^{2}-7 x+23x2−7x+2

Find the Product
- $(x-2)(3 x-1)$ A) $3 x^{2}-7 x-7$ B) $3 x^{2}-7 x+2$