Solve. Try factoring first. If factoring is not possible or is difficult, use the quadratic formula.
-$3 \mathrm{n}^{2}=-10 \mathrm{n}-2$
A) $\frac{-5 \pm \sqrt{19}}{6}$
B) $\frac{-10 \pm \sqrt{19}}{3}$
C) $\frac{-5 \pm \sqrt{19}}{3}$
D) $\frac{-5 \pm \sqrt{31}}{3}$

Question

Quizplus · Accepted Answer

Rearrange the equation to $3n^2 + 10n + 2 = 0$. Use the quadratic formula $n = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ with $a = 3$, $b = 10$, $c = 2$. This gives $n = \frac{-10 \pm \sqrt{100 - 24}}{6} = \frac{-10 \pm \sqrt{76}}{6} = \frac{-10 \pm \sqrt{4 \times 19}}{6} = \frac{-10 \pm 2\sqrt{19}}{6} = \frac{-5 \pm \sqrt{19}}{3}$.

Solve Try Factoring First 3n2=−10n−23 \mathrm{n}^{2}=-10 \mathrm{n}-23n2=−10n−2 A) −5±196\frac{-5 \pm \sqrt{19}}{6}6−5±19​​ B) −10±193\frac{-10 \pm \sqrt{19}}{3}3−10±19​​

Solve Try Factoring First $3 \mathrm{n}^{2}=-10 \mathrm{n}-2$ A) $\frac{-5 \pm \sqrt{19}}{6}$ B) $\frac{-10 \pm \sqrt{19}}{3}$