Solve the equation by completing the square.
-$12 \mathrm{~d}^{2}+40 \mathrm{~d}+25=0$
A) $-\frac{6}{5},-\frac{5}{2}$
B) $-\frac{5}{6},-\frac{5}{2}$
C) $\frac{5}{6}, \frac{5}{2}$
D) $\frac{6}{5}, \frac{2}{5}$

Question

Quizplus · Accepted Answer

To complete the square, divide the equation by 12: $d^2 + \frac{10}{3}d + \frac{25}{12} = 0$. Then, rearrange and complete the square: $(d + \frac{5}{3})^2 = \frac{25}{36}$. Solving gives $d = -\frac{5}{6}$ and $d = -\frac{5}{2}$.

Solve the Equation by Completing the Square 12 d2+40 d+25=012 \mathrm{~d}^{2}+40 \mathrm{~d}+25=012 d2+40 d+25=0 A) −65,−52-\frac{6}{5},-\frac{5}{2}−56​,−25​

Solve the Equation by Completing the Square $12 \mathrm{~d}^{2}+40 \mathrm{~d}+25=0$ A) $-\frac{6}{5},-\frac{5}{2}$