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Note: the Solutions to Most of the Multiple Choice Questions α 1\begin{array} { |l| } \hline \alpha\\ \hline \text { 1}\\ \hline \text {0 }\\\hline\end{array}

Question 64

Multiple Choice

Note: the solutions to most of the multiple choice questions in these sections use what call the standard assignment of truth values to atomic propositions. The standard assignment of truth values assigns the values given here to the variables in the wffs in the exercises, when read left to right. So, the first variable in the formula read left to right gets the α assignment; the second variable in the formula read left to right (if any) gets the β assignment; the third variable in the formula read left to right (if any) gets the γ assignment; and the fourth variable in the formula read left to right (if any) gets the δ assignment.
For exercises with only one propositional variable, the standard assignment is:
α 1\begin{array} { |l| } \hline \alpha\\ \hline \text { 1}\\ \hline \text {0 }\\\hline\end{array}

For exercises with two propositional variables, the standard assignment is:
αβ11100100\begin{array} { | c | c | } \hline \alpha& \boldsymbol { \beta } \\\hline 1 & 1 \\\hline 1 & 0 \\\hline 0 & 1 \\\hline0& 0\\\hline\end{array}
For exercises with three propositional variables, the standard assignment is:
αβγ111110101100e011010001000\begin{array} { | c | c | c | } \hline \alpha & \beta & \gamma \\\hline 1 & 1 & 1 \\\hline 1 & 1 & 0 \\\hline 1 & 0 & 1 \\\hline 1 & 0& 0e \\\hline 0 & 1 & 1 \\\hline 0 & 1 & 0 \\\hline 0 &0& 1 \\\hline 0 & 0& 0 \\\hline\end{array}
For exercises with four propositional variables, the standard assignment is:
αβγδ 1111111011011100101110101001100001110110\begin{array} { | l | l | l | l | } \hline \alpha & \boldsymbol { \beta } &\gamma& \delta\ \\\hline 1 & 1 & 1 & 1 \\\hline 1 & 1 & 1 & 0 \\\hline 1 & 1 & 0 & 1 \\\hline 1 & 1 & 0 & 0 \\\hline 1 & 0 & 1 & 1 \\\hline 1 & 0 & 1 & 0\\\hline 1 & 0 & 0 & 1 \\\hline 1 & 0& 0 & 0 \\\hline 0 & 1 & 1 & 1 \\\hline 0 & 1 & 1 &0 \\\hline\end{array}
010101000011001000010000\begin{array} { | c | c | c | c | } \hline 0 & 1 & 0 & 1 \\\hline 0 & 1 & 0 & 0 \\\hline 0& 0 & 1 & 1 \\\hline 0 & 0 & 1 & 0 \\\hline 0 & 0 & 0 & 1 \\\hline 0 & 0 & 0 & 0 \\\hline\end{array}
0101\begin{array} { |l | l | l | l |} \hline 0 & 1 & 0 & 1 \\\hline\end{array}
For each of the given propositions, determine which of the given sequences properly describes the column under the main operator, given the standard assignment of truth values to atomic propositions.
-(S ? ?T) ? {[V ? (?S • T) ] \lor [V ? (?T • S) ]}


A) 0011 1111
B) 0011 0000
C) 0101 1101
D) 1111 0101
E) 1111 1101

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