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The Table Represents a Specific Substrate Concentrations for an Enzyme

Question 79

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The table represents a specific substrate concentrations for an enzyme that displays classical Michaelis-Menten kinetics. Two sets of inhibitor data are also included. Determine the Km and Vmax for the uninhibited enzyme.
 Without Vo(mM/s)[S](mM) Inhibitor  With Inhibitor A  With Inhibitor B 1.32.501.170.622.64.002.101.426.56.304.002.6513.07.605.703.1226.09.007.203.58\begin{array}{l} \quad\quad\quad\quad\quad\text { Without } \quad\quad\quad\quad\quad\quad\quad\quad {\mathrm{V}_{\mathrm{o}}(\mathrm{mM} / \mathrm{s})} \\\begin{array}{llcc} {[\mathrm{S}](\mathrm{mM})} & \text { Inhibitor } & \text { With Inhibitor A } & \text { With Inhibitor B } \\1.3 & 2.50 & 1.17 & 0.62 \\2.6 & 4.00 & 2.10 & 1.42 \\6.5 & 6.30 & 4.00 & 2.65 \\13.0 & 7.60 & 5.70 & 3.12 \\26.0 & 9.00 & 7.20 & 3.58\end{array}\end{array}

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Vmax = 10 μm/s Km = 5 μm
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