Use the Quadratic Formula to solve $0.09 s ^ { 2 } - 0.12 s + 0.04 = 0$ . Round your answer(s)to two decimal places.
A) $s = 0.67$
B) $s = 0.67 , s = - 0.67$
C) $s = 0.89$
D) $s = 0.78 , s = 2.00$
E)no solutions

Question

Quizplus · Accepted Answer

The quadratic formula is $s = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 0.09$, $b = -0.12$, and $c = 0.04$. Plugging these values in gives $s = \frac{0.12 \pm \sqrt{(-0.12)^2 - 4(0.09)(0.04)}}{2(0.09)}$, which simplifies to $s = 0.67$ after rounding to two decimal places. There is only one solution because the discriminant ($b^2 - 4ac$) equals zero, indicating a perfect square under the square root, leading to one real, repeated solution.

Use the Quadratic Formula to Solve 0.09s2−0.12s+0.04=00.09 s ^ { 2 } - 0.12 s + 0.04 = 00.09s2−0.12s+0.04=0

Use the Quadratic Formula to Solve $0.09 s ^ { 2 } - 0.12 s + 0.04 = 0$