Use the Quadratic Formula to solve $12 x ^ { 2 } - 12 x + 3 = 0$ .
A) $x = \frac { 1 } { 2 }$
B) $x = \frac { 1 } { 2 } \pm 12 \sqrt { 2 }$
C) $x = 12 \sqrt { 2 }$
D) $x = - \frac { 1 } { 2 }$
E)no solutions

Question

Quizplus · Accepted Answer

The quadratic formula is $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 12$, $b = -12$, and $c = 3$. Plugging these values in, we get $x = \frac{12 \pm \sqrt{(-12)^2 - 4(12)(3)}}{2(12)} = \frac{12 \pm \sqrt{144 - 144}}{24} = \frac{12 \pm 0}{24} = \frac{1}{2}$.

Use the Quadratic Formula to Solve 12x2−12x+3=012 x ^ { 2 } - 12 x + 3 = 012x2−12x+3=0

Use the Quadratic Formula to Solve $12 x ^ { 2 } - 12 x + 3 = 0$