Find the x-intercepts of the function.
-$f ( x ) = ( x + 1 ) ( x - 2 ) \left( x ^ { 2 } - 9 \right)$
A)x-intercept: (1, 0), x-intercept: (-2, 0)x-intercept: (3, 0), x-intercept: (-3, 0)
B)x-intercept: (-1, 0), x-intercept: (2, 0)x-intercept: (3, 0), x-intercept: (-3, 0)
C)x-intercept: (-1, 0), x-intercept: (2, 0), x-intercept: (3, 0)
D)x-intercept: (-1, 0), x-intercept: (2, 0), x-intercept: (-3, 0)

Question

Quizplus · Accepted Answer

The x-intercepts of a function are found by setting the function equal to zero and solving for x. For $f(x) = (x + 1)(x - 2)(x^2 - 9)$, setting $f(x) = 0$ gives the solutions $x = -1$, $x = 2$, and $x^2 - 9 = 0$ which further gives $x = 3$ and $x = -3$. Therefore, the x-intercepts are (-1, 0), (2, 0), (3, 0), and (-3, 0).

Find the X-Intercepts of the Function f(x)=(x+1)(x−2)(x2−9)f ( x ) = ( x + 1 ) ( x - 2 ) \left( x ^ { 2 } - 9 \right)f(x)=(x+1)(x−2)(x2−9)

Find the X-Intercepts of the Function $f ( x ) = ( x + 1 ) ( x - 2 ) \left( x ^ { 2 } - 9 \right)$