Find the real zeros of the function, state their multiplicities if it is a number other than 1.
-$f ( x ) = \left( x + \frac { 1 } { 3 } \right) ^ { 2 } ( x - 2 ) ^ { 3 }$
A) $x = - \frac { 1 } { 3 }$, multiplicity: 2
$x = 2$, multiplicity: 3
B) $x = \frac { 1 } { 3 }$, multiplicity: 2
$x = - 2$, multiplicity: 3
C) $x = - \frac { 1 } { 3 }$, multiplicity: 2
$x = 2$, multiplicity: 2
D) $x = \frac { 1 } { 3 }$, multiplicity: 2
$x = 2$, multiplicity: 3

Question

Quizplus · Accepted Answer

The real zeros of the function are found by setting each factor equal to zero. For $\left( x + \frac { 1 } { 3 } \right) ^ { 2 }$, the zero is $x = - \frac { 1 } { 3 }$ with multiplicity 2. For $( x - 2 ) ^ { 3 }$, the zero is $x = 2$ with multiplicity 3.

Find the Real Zeros of the Function, State Their Multiplicities f(x)=(x+13)2(x−2)3f ( x ) = \left( x + \frac { 1 } { 3 } \right) ^ { 2 } ( x - 2 ) ^ { 3 }f(x)=(x+31​)2(x−2)3

Find the Real Zeros of the Function, State Their Multiplicities $f ( x ) = \left( x + \frac { 1 } { 3 } \right) ^ { 2 } ( x - 2 ) ^ { 3 }$