Convert the rectangular coordinates to polar coordinates with $r 0 \text { and } 0 \leq \theta

Question

Convert the rectangular coordinates to polar coordinates with $r > 0 \text { and } 0 \leq \theta < 2 \pi$ $( 0 , - \sqrt { 2 } )$
A) $( 4 , \pi / 2 )$
B) $( \sqrt { 2 } , 3 \pi / 2 )$
C) $( 4,3 \pi / 2 )$
D) $( \sqrt { 2 } , \pi )$
E) $( 4 , \pi )$

Quizplus · Accepted Answer

The polar coordinates are found using $r = \sqrt{x^2 + y^2}$ and $\theta = \tan^{-1}\left(\frac{y}{x}\right)$. For the point $(0, -\sqrt{2})$, $r = \sqrt{0^2 + (-\sqrt{2})^2} = \sqrt{2}$ and $\theta$ is $3\pi/2$ because the point is directly below the origin on the negative y-axis.

Convert the Rectangular Coordinates to Polar Coordinates With r>0 and 0≤θ<2πr > 0 \text { and } 0 \leq \theta < 2 \pir>0 and 0≤θ<2π

Convert the Rectangular Coordinates to Polar Coordinates With $r > 0 \text { and } 0 \leq \theta < 2 \pi$