Use the Product Rule to differentiate. $f ( t ) = t ^ { - 3 } \cos t$
A) $f ( t ) = - t ^ { - 3 } \sin t + 3 t ^ { - 4 } \cos t$
B) $f ^ { t } ( t ) = 3 t ^ { - 2 } \cos t - t ^ { - 3 } \sin t$
C) $f ^ { t } ( t ) = t ^ { - 3 } \sin t - 3 t ^ { - 4 } \cos t$
D) $f ^ {t } ( t ) = - t ^ { - 3 } \sin t - 3 t ^ { - 4 } \cos t$
E) $f ^ { t } ( t ) = - t ^ { - 3 } \sin t + 3 t ^ { - 4 } \sin t$

Question

Quizplus · Accepted Answer

The Answer of Use the Product Rule to differentiate. $f ( t ) = t ^ { - 3 } \cos t$
A) $f ( t ) = - t ^ { - 3 } \sin t + 3 t ^ { - 4 } \cos t$
B) $f ^ { t } ( t ) = 3 t ^ { - 2 } \cos t - t ^ { - 3 } \sin t$
C) $f ^ { t } ( t ) = t ^ { - 3 } \sin t - 3 t ^ { - 4 } \cos t$
D) $f ^ {t } ( t ) = - t ^ { - 3 } \sin t - 3 t ^ { - 4 } \cos t$
E) $f ^ { t } ( t ) = - t ^ { - 3 } \sin t + 3 t ^ { - 4 } \sin t$

Use the Product Rule to Differentiate f(t)=t−3cos⁡tf ( t ) = t ^ { - 3 } \cos tf(t)=t−3cost

Use the Product Rule to Differentiate $f ( t ) = t ^ { - 3 } \cos t$