$\text { Find the derivative of the function } f ( x ) = \frac { 2 } { \sqrt [ 3 ] { x } } + 3 \cos x \text {. }$
A) $f ^ { t } ( x ) = \frac { 2 } { 3 x ^ { 4 / 3 } } - 3 \sin x$
B) $f ^ {t} ( x ) = - \frac { 2 } { 3 x ^ { 4 / 3 } } - 3 \sin x$
C) $f ^ { t} ( x ) = - \frac { 2 } { 3 x ^ { 4 / 3 } } + 3 \sin x$
D) $f ^ { t } ( x ) = - \frac { 2 } { 3 x ^ { 3 / 4 } } - 3 \sin x$
E) $f ^ { t } ( x ) = - \frac { 2 } { 3 x ^ { 3 / 4 } } + 3 \sin x$

Question

$\text { Find the derivative of the function } f ( x ) = \frac { 2 } { \sqrt [ 3 ] { x } } + 3 \cos x \text {. }$ 
A) $f ^ { t } ( x ) = \frac { 2 } { 3 x ^ { 4 / 3 } } - 3 \sin x$
B) $f ^ {t} ( x ) = - \frac { 2 } { 3 x ^ { 4 / 3 } } - 3 \sin x$
C) $f ^ { t} ( x ) = - \frac { 2 } { 3 x ^ { 4 / 3 } } + 3 \sin x$
D) $f ^ { t } ( x ) = - \frac { 2 } { 3 x ^ { 3 / 4 } } - 3 \sin x$
E) $f ^ { t } ( x ) = - \frac { 2 } { 3 x ^ { 3 / 4 } } + 3 \sin x$

Quizplus · Accepted Answer

The Answer of $\text { Find the derivative of the function } f ( x ) = \frac { 2 } { \sqrt [ 3 ] { x } } + 3 \cos x \text {. }$ 
A) $f ^ { t } ( x ) = \frac { 2 } { 3 x ^ { 4 / 3 } } - 3 \sin x$
B) $f ^ {t} ( x ) = - \frac { 2 } { 3 x ^ { 4 / 3 } } - 3 \sin x$
C) $f ^ { t} ( x ) = - \frac { 2 } { 3 x ^ { 4 / 3 } } + 3 \sin x$
D) $f ^ { t } ( x ) = - \frac { 2 } { 3 x ^ { 3 / 4 } } - 3 \sin x$
E) $f ^ { t } ( x ) = - \frac { 2 } { 3 x ^ { 3 / 4 } } + 3 \sin x$

Find the derivative of the function f(x)=2x3+3cos⁡x. \text { Find the derivative of the function } f ( x ) = \frac { 2 } { \sqrt [ 3 ] { x } } + 3 \cos x \text {. } Find the derivative of the function f(x)=3x​2​+3cosx.

$\text { Find the derivative of the function } f ( x ) = \frac { 2 } { \sqrt [ 3 ] { x } } + 3 \cos x \text {. }$