In the coordination compound [Cr(NH₃)₂(en)Cl₂]Br₂, the coordination number (C.N.) and oxidation number (O.N.) of the metal atom, respectively, are A) C.N. = 6; O.N. = +4. B) C.N. = 6; O.N. = +3. C) C.N. = 5; O.N. = +2. D) C.N. = 5; O.N. = +4. E) C.N. = 4; O.N. = +3.

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Quizplus · Accepted Answer

The coordination number of the metal atom is the number of ligands bonded to it. In this case, the metal atom is Cr, and it is bonded to two NH3 ligands, one en ligand, and two Cl ligands. Therefore, the coordination number of the metal atom is 6.The oxidation number of the metal atom is the charge it would have if all of the ligands were removed. In this case, the ligands are NH3, en, Cl, and Br. NH3 is a neutral ligand, en is a neutral ligand, Cl is a -1 ligand, and Br is a -1 ligand. Therefore, the oxidation number of the metal atom is +4.

In the Coordination Compound [Cr(NH3)2(en)Cl2]Br2, the Coordination Number (C

In the Coordination Compound [Cr(NH₃)₂(en)Cl₂]Br₂, the Coordination Number (C