In the complex ion [Cr(C₂O₄)₂(H₂O)₂]^-, what is the oxidation number of Cr? A) +1 B) +2 C) +3 D) -2 E) -1

Question

Quizplus · Accepted Answer

The oxidation number of S is -2 and that of O is -2. There are a total of six S atoms and one O atom. Therefore, the total charge due to S and O is -14. The overall charge of the complex ion is -1. Therefore, the oxidation state of Cr can be calculated as follows:

Charge on Cr + (-14) = -1
Charge on Cr = +13

The oxidation state of Cr is +3.

In the Complex Ion [Cr(C2O4)2(H2O)2]-, What Is the Oxidation Number

In the Complex Ion [Cr(C₂O₄)₂(H₂O)₂]^-, What Is the Oxidation Number