Solve the Problem $\mathrm { D }$ Be the Region That Is Bounded Below by the Cone

Solve the problem.
-Let $\mathrm { D }$ be the region that is bounded below by the cone $\varphi = \frac { \pi } { 4 }$ and above by the sphere $\varrho = 6$ . Set up the triple integral for the volume of $\mathrm { D }$ in cylindrical coordinates.

A) $\int _ { 0 } ^ { 2 \pi } \int _ { 0 } ^ { 6 } \int _ { r } ^ { \sqrt { 36 - r ^ { 2 } } } r d z d r d \theta$
B) $\int _ { 0 } ^ { 2 \pi } \int _ { 0 } ^ { 6 / \sqrt { 2 } } \int _ { 0 } ^ { \sqrt { 36 - r ^ { 2 } } } r d z d r d \theta$
C) $\int _ { 0 } ^ { 2 \pi } \int _ { 0 } ^ { 6 } \int _ { 0 } ^ { \sqrt { 36 - r ^ { 2 } } } r d z d r d \theta$
D) $\int _ { 0 } ^ { 2 \pi } \int _ { 0 } ^ { 6 / \sqrt { 2 } } \int _ { r } ^ { \sqrt { 36 - r ^ { 2 } } } r d z d r d \theta$