Use any method to evaluate the integral.
-$$\int \frac { \cos x } { \sin ^ { 2 } x } d x$$
A) sec x + C
B) csc x + C
C) -csc x + C
D) -sec x + C

Name: Use any method to evaluate the integral. -\[\int \frac { \cos x } { \sin ^ { 2 } x } d x\] A) sec x + C B) csc x + C C) -csc x + C D) -sec x + C
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Question

Quizplus · Accepted Answer

We can use the substitution $u = \sin x$ and $du = \cos x dx$ to rewrite the integral as $\int \frac { 1 } { u ^ { 2 } } d u = -\frac{1}{u} + C$. Then substituting back in for $u$ yields $-\csc x + C$.

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Use Any Method to Evaluate the Integral $\int \frac { \cos x } { \sin ^ { 2 } x } d x$