Use the echelon method to solve the system of two equations in two unknowns.
-$$
\begin{array}{l}
4 x-2 y=9 \
20 x-10 y=27
\end{array}
$$
A) $ \left(\frac{1}{2} y+\frac{9}{4}, y\right) $
B) $ \left(1,-\frac{5}{2}\right) $
C) $ (1,0) $
D) No solution

Question

Quizplus · Accepted Answer

The second equation is a multiple of the first (each term in the second equation is 5 times the corresponding term in the first equation), but the constants on the right side of the equations (9 and 27) do not have the same ratio (27 is not 5 times 9). This inconsistency means the system of equations has no solution.

Use the Echelon Method to Solve the System of Two 4x−2y=920x−10y=27\begin{array}{l}4 x-2 y=9 \\20 x-10 y=27\end{array}4x−2y=920x−10y=27​

Use the Echelon Method to Solve the System of Two $\begin{array}{l}4 x-2 y=9 \\20 x-10 y=27\end{array}$