Find the value.
-Let $ \mathrm{C}=\left[\begin{array}{r}6 \ -2 \ 12\end{array}\right] ; \frac{1}{2} \mathrm{C} $
A) $ \left[\begin{array}{r}3 \ -2 \ 12\end{array}\right] $
B) $ \left[\begin{array}{r}6 \ -1 \ 12\end{array}\right] $
C) $ \left[\begin{array}{r}3 \ -1 \ 6\end{array}\right] $
D) $ \left[\begin{array}{r}12 \ -4 \ 24\end{array}\right] $

Question

Quizplus · Accepted Answer

Multiplying the vector $ \mathrm{C}=\left[\begin{array}{r}6 \ -2 \ 12\end{array}\right] $ by $ \frac{1}{2} $ results in each element of the vector being halved, giving $ \left[\begin{array}{r}3 \ -1 \ 6\end{array}\right] $.

Find the Value C=[6−212];12C \mathrm{C}=\left[\begin{array}{r}6 \\ -2 \\ 12\end{array}\right] ; \frac{1}{2} \mathrm{C} C=​6−212​​;21​C

Find the Value $\mathrm{C}=\left[\begin{array}{r}6 \\ -2 \\ 12\end{array}\right] ; \frac{1}{2} \mathrm{C}$