Solve the problem.
-In a town whose population is 3000, a disease creates an epidemic. The number of people, N, infected t days after the disease has begun is given by the function $\mathrm { N } ( \mathrm { t } ) = \frac { 3000 } { 1 + 21.2 \mathrm { e } ^ { - 0.54 t } }$ Find the number of infected people after 10 days.
A) 142 people
B) 2000 people.
C) 1000 people
D) 2737 people

Question

Quizplus · Accepted Answer

To find the number of infected people after 10 days, substitute $t = 10$ into the given function: $N(10) = \frac{3000}{1 + 21.2e^{-0.54 \times 10}}$. Calculating this gives approximately 2737 people.

Solve the Problem N(t)=30001+21.2e−0.54t\mathrm { N } ( \mathrm { t } ) = \frac { 3000 } { 1 + 21.2 \mathrm { e } ^ { - 0.54 t } }N(t)=1+21.2e−0.54t3000​

Solve the Problem $\mathrm { N } ( \mathrm { t } ) = \frac { 3000 } { 1 + 21.2 \mathrm { e } ^ { - 0.54 t } }$