Solve the problem.
-In 1992, the population of a country was estimated at 5 million. For any subsequent year, the population, P(t) (in
millions), can be modeled using the equation $\mathrm { P } ( \mathrm { t } ) = \frac { 250 } { 5 + 44.99 \mathrm { e } ^ { - 0.0208 \mathrm { t } } }$ , where t is the number of years since
1992. Determine the year when the population will be 39 million.

Question

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The Answer of Solve the problem.
-In 1992, the population of a country was estimated at 5 million. For any subsequent year, the population, P(t) (in
millions), can be modeled using the equation $\mathrm { P } ( \mathrm { t } ) = \frac { 250 } { 5 + 44.99 \mathrm { e } ^ { - 0.0208 \mathrm { t } } }$ , where t is the number of years since
1992. Determine the year when the population will be 39 million.

Solve the Problem P(t)=2505+44.99e−0.0208t\mathrm { P } ( \mathrm { t } ) = \frac { 250 } { 5 + 44.99 \mathrm { e } ^ { - 0.0208 \mathrm { t } } }P(t)=5+44.99e−0.0208t250​

Solve the Problem $\mathrm { P } ( \mathrm { t } ) = \frac { 250 } { 5 + 44.99 \mathrm { e } ^ { - 0.0208 \mathrm { t } } }$