The numbers of successes and the sample sizes are given for independent simple random samples from two populations.Use the two-proportions z-interval procedure to obtain the specified confidence interval.
-$\mathrm { x } _ { 1 } = 44 , \mathrm { n } _ { 1 } = 67 , \mathrm { x } _ { 2 } = 50 , \mathrm { n } _ { 2 } = 79 ; 95 \%$ confidence interval
A)$0.471$ to $0.842$
B) $- 0.161$ to $0.842$
C) $0.501$ to $0.813$
D) $- 0.132$ to $0.179$

Question

The numbers of successes and the sample sizes are given for independent simple random samples from two populations.Use the two-proportions z-interval procedure to obtain the specified confidence interval.
-$\mathrm { x } _ { 1 } = 44 , \mathrm { n } _ { 1 } = 67 , \mathrm { x } _ { 2 } = 50 , \mathrm { n } _ { 2 } = 79 ; 95 \%$ confidence interval  
A)$0.471$ to $0.842$
B) $- 0.161$ to $0.842$
C) $0.501$ to $0.813$
D) $- 0.132$ to $0.179$

Quizplus · Accepted Answer

The two-proportions z-interval procedure calculates the confidence interval for the difference between two population proportions. Using the given data, the 95% confidence interval for the difference between the proportions is $-0.132$ to $0.179$.

The Numbers of Successes and the Sample Sizes Are Given x1=44,n1=67,x2=50,n2=79;95%\mathrm { x } _ { 1 } = 44 , \mathrm { n } _ { 1 } = 67 , \mathrm { x } _ { 2 } = 50 , \mathrm { n } _ { 2 } = 79 ; 95 \%x1​=44,n1​=67,x2​=50,n2​=79;95%

The Numbers of Successes and the Sample Sizes Are Given $\mathrm { x } _ { 1 } = 44 , \mathrm { n } _ { 1 } = 67 , \mathrm { x } _ { 2 } = 50 , \mathrm { n } _ { 2 } = 79 ; 95 \%$