Identify the vertex of the parabola.
-Identify the vertex of the parabola
$y = 3 x ^ { 2 } - 6 x + 0$
A) (-1,3)
B) (3,-1)
C) (-3,1)
D) (1,-3)

Question

Identify the vertex of the parabola.
-Identify the vertex of the parabola
$y = 3 x ^ { 2 } - 6 x + 0$
A)  (-1,3) 
B)  (3,-1) 
C)  (-3,1) 
D)  (1,-3)

Quizplus · Accepted Answer

The vertex of a parabola in the form $y = ax^2 + bx + c$ can be found using the formula $(-b/2a, f(-b/2a))$. For $y = 3x^2 - 6x + 0$, $a = 3$ and $b = -6$, so the x-coordinate of the vertex is $-(-6)/(2*3) = 1$. Plugging $x = 1$ back into the equation gives $y = 3(1)^2 - 6(1) + 0 = -3$. Therefore, the vertex is $(1, -3)$.

Identify the Vertex of the Parabola y=3x2−6x+0y = 3 x ^ { 2 } - 6 x + 0y=3x2−6x+0

Identify the Vertex of the Parabola $y = 3 x ^ { 2 } - 6 x + 0$