Identify the vertex of the parabola.
-Identify the vertex of the parabola.
$y = 3 x ^ { 2 } - 6 x - 2$
A) (1,-5)
B) (-1,5)
C) (-5,1)
D) (5,-1)

Question

Identify the vertex of the parabola.
-Identify the vertex of the parabola.
$y = 3 x ^ { 2 } - 6 x - 2$
A)  (1,-5) 
B)  (-1,5) 
C)  (-5,1) 
D)  (5,-1)

Quizplus · Accepted Answer

The vertex of a parabola in the form $y = ax^2 + bx + c$ can be found using the formula $x = -\frac{b}{2a}$. For the given equation $y = 3x^2 - 6x - 2$, $a = 3$ and $b = -6$, so $x = -\frac{-6}{2*3} = 1$. Plugging $x = 1$ back into the equation gives $y = 3(1)^2 - 6(1) - 2 = 3 - 6 - 2 = -5$. Therefore, the vertex is at (1, -5).

Identify the Vertex of the Parabola y=3x2−6x−2y = 3 x ^ { 2 } - 6 x - 2y=3x2−6x−2

Identify the Vertex of the Parabola $y = 3 x ^ { 2 } - 6 x - 2$