Solve the equation
-$\sqrt [ 3 ] { 3 x - 1 } = \sqrt [ 3 ] { 4 x + 1 }$
A) x=-2
B) x=-$\frac { 2 } { 3 }$
C) x=0
D) x=2

Name: Solve the equation -$\sqrt [ 3 ] { 3 x - 1 } = \sqrt [ 3 ] { 4 x + 1 }$ A) x=-2 B) x=-$\frac { 2 } { 3 }$ C) x=0 D) x=2
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Question

Solve the equation
-$\sqrt [ 3 ] { 3 x - 1 } = \sqrt [ 3 ] { 4 x + 1 }$
A)  x=-2 
B)  x=-$\frac { 2 } { 3 }$
C)  x=0 
D)  x=2

Quizplus · Accepted Answer

Since both sides of the equation are cube roots, we can equate the expressions inside the cube roots and solve for x: $3x - 1 = 4x + 1$. Solving this gives $x = -2$.

Solve the Equation - 3x−13=4x+13\sqrt [ 3 ] { 3 x - 1 } = \sqrt [ 3 ] { 4 x + 1 }33x−1​=34x+1​

Solve the Equation
- $\sqrt [ 3 ] { 3 x - 1 } = \sqrt [ 3 ] { 4 x + 1 }$