Solve the equation
-$\sqrt { 2 x ^ { 2 } - 16 } - x = 0$
A) $x = \pm 4$
B) x=8
C) x=4
D) $x = \pm 5$

Question

Solve the equation
-$\sqrt { 2 x ^ { 2 } - 16 } - x = 0$
A) $x = \pm 4$
B)  x=8 
C)  x=4 
D) $x = \pm 5$

Quizplus · Accepted Answer

To solve the equation $\sqrt { 2 x ^ { 2 } - 16 } - x = 0$, we first isolate the square root on one side: $\sqrt { 2 x ^ { 2 } - 16 } = x$. Squaring both sides gives $2x^2 - 16 = x^2$, which simplifies to $x^2 = 16$. Taking the square root of both sides gives $x = \pm 4$. However, substituting $x = -4$ back into the original equation shows it does not satisfy the equation, leaving $x = 4$ as the correct solution.

Solve the Equation - 2x2−16−x=0\sqrt { 2 x ^ { 2 } - 16 } - x = 02x2−16​−x=0

Solve the Equation
- $\sqrt { 2 x ^ { 2 } - 16 } - x = 0$