Suppose $g : \mathbf { R } \rightarrow \mathbf { R }$ where $g ( x ) = \left\lfloor \frac { x - 1 } { 2 } \right\rfloor$
(a) If $S = \{ x \mid 1 \leq x \leq 6 \}$
, find $g ( S )$ .
(b) If $T$={2} , find $g ^ { - 1 } ( T )$

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The Answer of Suppose $g : \mathbf { R } \rightarrow \mathbf { R }$ where $g ( x ) = \left\lfloor \frac { x - 1 } { 2 } \right\rfloor$
(a) If $S = \{ x \mid 1 \leq x \leq 6 \}$
, find $g ( S )$ .
(b) If $T$={2} , find $g ^ { - 1 } ( T )$

Suppose g:R→Rg : \mathbf { R } \rightarrow \mathbf { R }g:R→R

Suppose $g : \mathbf { R } \rightarrow \mathbf { R }$