Suppose $g : \mathbf { R } \rightarrow \mathbf { R }$ where $g ( x ) = \left\lfloor \frac { x - 1 } { 2 } \right\rfloor$
(a) Draw the graph of g .
(b) Is g 1-1?
(c) Is g onto R ?

Question

Suppose $g : \mathbf { R } \rightarrow \mathbf { R }$ where $g ( x ) = \left\lfloor \frac { x - 1 } { 2 } \right\rfloor$
(a) Draw the graph of  g .
(b) Is  g  1-1?
(c) Is  g  onto  R ?

Quizplus · Accepted Answer

The Answer of Suppose $g : \mathbf { R } \rightarrow \mathbf { R }$ where $g ( x ) = \left\lfloor \frac { x - 1 } { 2 } \right\rfloor$
(a) Draw the graph of  g .
(b) Is  g  1-1?
(c) Is  g  onto  R ?

Suppose g:R→Rg : \mathbf { R } \rightarrow \mathbf { R }g:R→R

Suppose $g : \mathbf { R } \rightarrow \mathbf { R }$