Solve.
-An object is thrown upward from the top of a 160-foot building with an initial velocity of 48 feet per second. After $t$ seconds, the height $h ( t )$ of the object is given by the function $h ( t ) = - 16 t ^ { 2 } + 48 t + 160$. Find how long it takes the object to hit the ground.
A) $5 \mathrm { sec }$
B) $10 \mathrm { sec }$
C) $160 \mathrm { sec }$
D) $2 \mathrm { sec }$

Question

Quizplus · Accepted Answer

To find when the object hits the ground, set $h(t) = 0$ and solve for $t$: $-16t^2 + 48t + 160 = 0$. Factoring or using the quadratic formula gives $t = 5$ seconds as the time it takes for the object to hit the ground.

Solve -An Object Is Thrown Upward from the Top of a 160-Foot

Solve
-An Object Is Thrown Upward from the Top of a 160-Foot