Solve.
-A certain rectangle's length is $3 \mathrm { ft }$ longer than its width. If the area of the rectangle is 180 square feet, find its dimensions.
A) $11 \mathrm { ft }$ by $16 \mathrm { ft }$
B) $11 \mathrm { ft }$ by $14 \mathrm { ft }$
C) $13 \mathrm { ft }$ by $16 \mathrm { ft }$
D) $12 \mathrm { ft }$ by $15 \mathrm { ft }$

Question

Quizplus · Accepted Answer

The dimensions of the rectangle can be found by setting up the equation $w(w + 3) = 180$, where $w$ is the width and $w + 3$ is the length. Solving this quadratic equation gives $w = 12$, so the length is $12 + 3 = 15$. Therefore, the dimensions are $12 \mathrm { ft }$ by $15 \mathrm { ft }$.

Solve -A Certain Rectangle's Length Is 3ft3 \mathrm { ft }3ft

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-A Certain Rectangle's Length Is $3 \mathrm { ft }$