Factor.
-$$\frac { 1 } { 4 } - 49 z ^ { 2 }$$
A) $\left( \frac { 1 } { 2 } + 7 z \right) ^ { 2 }$
B) $\left( \frac { 1 } { 2 } + 7 \mathrm { z } \right) \left( \frac { 1 } { 2 } - 7 \mathrm { z } \right)$
C) $\left( \frac { 1 } { 2 } - 7 \mathrm { z } \right) ^ { 2 }$
D) prime polynomial

Question

Quizplus · Accepted Answer

The expression $\frac { 1 } { 4 } - 49 z ^ { 2 }$ is a difference of squares, which factors into $\left( \frac { 1 } { 2 } \right) ^ { 2 } - (7z) ^ { 2 }$, and thus can be factored as $\left( \frac { 1 } { 2 } + 7z \right) \left( \frac { 1 } { 2 } - 7z \right)$.

Factor - 14−49z2\frac { 1 } { 4 } - 49 z ^ { 2 }41​−49z2

Factor
- $\frac { 1 } { 4 } - 49 z ^ { 2 }$