Factor the polynomial completely.
-$$( x + 1 ) ^ { 2 } + 16 ( x + 1 ) + 64$$
A) $( x - 9 ) ^ { 2 }$
B) $( x + 9 ) ^ { 2 }$
C) $( x + 9 ) ( x - 9 )$
D) $2 ( x + 9 ) ( x - 9 )$

Question

Quizplus · Accepted Answer

The given polynomial can be rewritten as $(x + 1 + 8)^2$ by recognizing it as a perfect square trinomial, where $a = x + 1$ and $b = 8$. Simplifying gives $(x + 9)^2$.

Factor the Polynomial Completely (x+1)2+16(x+1)+64( x + 1 ) ^ { 2 } + 16 ( x + 1 ) + 64(x+1)2+16(x+1)+64

Factor the Polynomial Completely $( x + 1 ) ^ { 2 } + 16 ( x + 1 ) + 64$