Question 1

What is the speed of the particle after it has traveled 8 m?
A)4 m/s
B)8 m/s
C)30 m/s
D)60 m/s
E)100 m/s

Accepted Answer

The answer of What is the speed of the particle...

Question 2

2-12
A rock, dropped from rest near the surface of an atmosphere-free planet, attains a speed of 20.0 m/s after falling 8.0 meters.
-Determine the speed of the object after falling from rest through 16 m on this planet.
A)28 m/s
B)32 m/s
C)56 m/s
D)64 m/s
E)320 m/s

Accepted Answer

The answer of 2-12
A rock, dropped from rest near the...

Question 3

2-12 A rock, dropped from rest near the surface of an atmosphere-free planet, attains a speed of 20.0 m/s after falling 8.0 meters. -What is the magnitude of the acceleration due to gravity on the surface of this planet? A)0.40 m/s² B)1.3 m/s² C)2.5 m/s² D)25 m/s² E)160 m/s²

Accepted Answer

The answer of 2-12
A rock, dropped from rest near the...

Question 4

2-9
An object is moving along a straight line in the positive x direction.The graph shows its position from the starting point as a function of time.Various segments of the graph are identified by the letters A, B, C, and D. 
-In a race, Marcos runs 1.00 mile in 4.02 min, mounts a bicycle, and rides back to his starting point, which is also the finish line, in 3.02 min.What is the magnitude of Marcos' average velocity for the race?
A)zero mi/h
B)12.1 mi/h
C)14.9 mi/h
D)17.0 mi/h
E)19.9 mi/h

Accepted Answer

The answer of 2-9
An object is moving along a straight...

Question 5

2-15
The figure shows the speed as a function of time for an object in free fall near the surface of the earth.  The object was dropped from rest in a long evacuated cylinder.
-Which one of the following statements best explains why the graph goes through the origin?
A)The object was in a vacuum.
B)The object was dropped from rest.
C)The velocity of the object was constant.
D)All v vs.t curves pass through the origin.
E)The acceleration of the object was constant.

Accepted Answer

The graph goes through the origin because the object was dropped from rest, meaning it had no initial velocity.

Question 6

2-13
A brass ball is shot vertically upward from the surface of an atmosphere-free planet with an initial speed of 20.0 m/s.One second later, the ball has an instantaneous velocity in the upward direction of 15.0 m/s.
-How high does the ball rise?
A)70.0 m
B)10.0 m
C)50.0 m
D)20.0 m
E)40.0 m

Accepted Answer

The answer of 2-13
A brass ball is shot vertically upward...

Question 7

After 10 seconds, how far will the particle have traveled?
A)20 m
B)40 m
C)100 m
D)200 m
E)400 m

Accepted Answer

The answer of After 10 seconds, how far will the...

Question 8

2-12
A rock, dropped from rest near the surface of an atmosphere-free planet, attains a speed of 20.0 m/s after falling 8.0 meters.
-How long would it take the object, falling from rest, to fall 16 m on this planet?
A)0.8 s
B)1.1 s
C)2.5 s
D)3.5 s
E)22 s

Accepted Answer

Using the equation for free fall:

v^2 = vi^2 + 2ad

where v is final velocity (20.0 m/s), vi is initial velocity (0 m/s), a is acceleration due to gravity (unknown), and d is displacement (8.0 m).

Solving for a:

a = (v^2 - vi^2) / 2d 
a = (20.0 m/s)^2 / 2(8.0 m)
a = 50.0 m/s^2

Now using the same equation and plugging in the new displacement (16m):

v^2 = vi^2 + 2ad

where v is final velocity (unknown), vi is initial velocity (0 m/s), a is acceleration due to gravity (50.0 m/s^2), and d is displacement (16 m).

Solving for v:

v^2 = 2ad 
v^2 = 2(50.0 m/s^2)(16 m) 
v = 20.0 m/s

To find the time it takes to reach this velocity, we can use the equation:

v = at

where v is final velocity (20.0 m/s), a is acceleration due to gravity (50.0 m/s^2) and t is time.

Solving for t:

t = v / a 
t = (20.0 m/s) / (50.0 m/s^2) 
t = 0.4 s

Since the object takes 0.4 s to reach a velocity of 20.0 m/s and fall 8.0 m, it would take an additional 0.4 s to fall the next 8.0 m, since the acceleration due to gravity is constant. Therefore:

Total time to fall 16m = 0.4 s + 0.4 s = 0.8 s

The best choice is B.

Question 9

2-9
An object is moving along a straight line in the positive x direction.The graph shows its position from the starting point as a function of time.Various segments of the graph are identified by the letters A, B, C, and D. 
-The rate at which the acceleration of an object changes with time is called a jerk.What is the dimension of the jerk?
A) 
B) 
C) 
D) 
E)

Accepted Answer

The answer of 2-9
An object is moving along a straight...

Question 10

2-10
A automotive test driver travels due north in a prototype hybrid vehicle at 30 mi/h for 2 hours.She then reverses her direction and travels due south at 60 mi/h for 1 hour.
-What is the average velocity of the vehicle?
A)zero mi/h
B)40 mi/h, north
C)40 mi/h, south
D)45 mi/h, north
E)45 mi/h, south

Accepted Answer

The answer of 2-10
A automotive test driver travels due north...

Question 11

2-13
A brass ball is shot vertically upward from the surface of an atmosphere-free planet with an initial speed of 20.0 m/s.One second later, the ball has an instantaneous velocity in the upward direction of 15.0 m/s.
-How long does it take the ball to reach its maximum height?
A)2.0 s
B)2.3 s
C)4.0 s
D)4.6 s
E)8.0 s

Accepted Answer

The answer of 2-13
A brass ball is shot vertically upward...

Question 12

2-14 A small object is released from rest and falls 1.00 × 10S1U1P12S1S1P0 feet near the surface of the earth.Neglect air resistance. -How long will it take to fall through the 1.00 × 10²feet mentioned? A)2.49 s B)3.12 s C)4.50 s D)6.25 s E)10.0 s

Accepted Answer

The answer of 2-14
A small object is released from rest...

Question 13

2-13
A brass ball is shot vertically upward from the surface of an atmosphere-free planet with an initial speed of 20.0 m/s.One second later, the ball has an instantaneous velocity in the upward direction of 15.0 m/s.
-Determine the velocity of the ball when it returns to its original position.Note: assume the upward direction is positive.
A)+20 m/s
B)-20 m/s
C)+40 m/s
D)-40 m/s
E)zero m/s

Accepted Answer

When the ball is at its highest point, its velocity is zero. Therefore, the time it takes for the ball to reach its highest point is equal to the time it takes for the ball to fall back to its original position.

Using the equation of motion for constant acceleration:

v = u + at

where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

At the highest point, v = 0 and u = 15 m/s (since the ball was moving upward with a velocity of 20 m/s and the velocity decreased by 5 m/s after 1 second). The acceleration due to gravity (g) is downward, so it is negative:

0 = 15 - gt

t = 15/g

To find the velocity of the ball when it returns to its original position, we need to use the same equation with a different value of t. Since the time for the ball to reach its original position is twice the time for it to reach the highest point:

t' = 2(15/g) = 30/g

Thus,

v' = u + at' 
   = -15 + g(30/g) 
   = -15 + 30 
   = 15 m/s

The negative sign indicates that the velocity is downward, which is consistent with the ball falling back to its original position. Therefore, the answer is B.

Question 14

2-13 A brass ball is shot vertically upward from the surface of an atmosphere-free planet with an initial speed of 20.0 m/s.One second later, the ball has an instantaneous velocity in the upward direction of 15.0 m/s. -What is the magnitude of the acceleration due to gravity on the surface of this planet? A)5.0 m/s² B)9.8 m/s² C)12 m/s² D)15 m/s² E)24 m/s²

Accepted Answer

The answer of 2-13
A brass ball is shot vertically upward...

Question 15

2-11 Starting from rest, a particle confined to move along a straight line is accelerated at a rate of 4 m/sS1U1P12S1S1P0. -Which statement accurately describes the motion of the particle? A)The particle travels 4 meters during each second. B)The particle travels 4 meters during the first second only. C)The speed of the particle increases by 4 m/s during each second. D)The acceleration of the particle increases by 4 m/s² during each second. E)The final velocity of the particle will be proportional to the distance that the particle covers.

Accepted Answer

The statement "The speed of the particle increases by 4 m/s during each second" accurately describes the motion of the particle. This is because acceleration is the rate of change of velocity, and the particle is accelerating at a constant rate of 4 m/s every second. Option A is incorrect because the distance traveled by the particle will increase each second as the particle accelerates. Option B is incorrect because the particle will continue to travel at an increasing speed beyond the first second. Option D is incorrect because the acceleration of the particle is constant. Option E is incorrect because the final velocity of the particle is determined by the acceleration and time, not the distance traveled.

Question 16

2-13
A brass ball is shot vertically upward from the surface of an atmosphere-free planet with an initial speed of 20.0 m/s.One second later, the ball has an instantaneous velocity in the upward direction of 15.0 m/s.
-How long is the ball in the air when it returns to its original position?
A)4.0 s
B)4.6 s
C)8.0 s
D)9.2 s
E)16 s

Accepted Answer

The answer of 2-13
A brass ball is shot vertically upward...

Question 17

2-12
A rock, dropped from rest near the surface of an atmosphere-free planet, attains a speed of 20.0 m/s after falling 8.0 meters.
-How long did it take the object to fall the 8.0 meters mentioned?
A)0.40 s
B)0.80 s
C)1.3 s
D)2.5 s
E)16 s

Accepted Answer

The time it takes for an object to fall a certain distance is given by the equation d = 1/2gt^2, where d is the distance, g is the acceleration due to gravity (9.8 m/s^2 on Earth), and t is the time. Rearranging this equation, we get t = sqrt(2d/g). Plugging in the given values, we get t = sqrt(2(8.0 m)/(9.8 m/s^2)) = 0.80 s. Therefore, the answer is choice B.

Question 18

2-14 A small object is released from rest and falls 1.00 × 10S1U1P12S1S1P0 feet near the surface of the earth.Neglect air resistance. -Approximately how fast will the object be moving after falling through the 1.00 × 10² feet mentioned? A)9.8 ft/s B)40 ft/s C)80 ft/s D)160 ft/s E)320 ft/s

Accepted Answer

We can use the equation for gravitational potential energy and kinetic energy to solve for the final velocity.

Gravitational potential energy at the top of the fall = mgh = m(32.2 ft/s²)(1.00 × 10¹² ft) = 3.22 × 10¹³m ft²/s²

At the bottom of the fall, all the potential energy has been converted to kinetic energy, so

Kinetic energy at bottom of the fall = 1/2 mv²

Equating the two:

1/2 mv² = 3.22 × 10¹³m ft²/s²

v² = 6.44 × 10¹³ ft²/s²

v = √(6.44 × 10¹³) ft/s

v ≈ 80 ft/s

Therefore, the best choice is C: 80 ft/s.

Question 19

2-10
A automotive test driver travels due north in a prototype hybrid vehicle at 30 mi/h for 2 hours.She then reverses her direction and travels due south at 60 mi/h for 1 hour.
-What is the average speed of the vehicle?
A)zero mi/h
B)30 mi/h
C)40 mi/h
D)50 mi/h
E)60 mi/h

Accepted Answer

To find the average speed, we need to use the formula:

average speed = total distance / total time

In this case, we know that the driver traveled due north at 30 mi/h for 2 hours, so her distance in that direction was:

distance north = 30 mi/h * 2 h = 60 miles

Then, the driver traveled due south at 60 mi/h for 1 hour, so her distance in that direction was:

distance south = 60 mi/h * 1 h = 60 miles

To find the total distance, we can simply add the two distances together:

total distance = distance north + distance south = 60 miles + 60 miles = 120 miles

To find the total time, we can add the time spent traveling north and south:

total time = 2 hours + 1 hour = 3 hours

Now we can plug in these values into the formula:

average speed = total distance / total time = 120 miles / 3 hours = 40 mi/h

Therefore, the answer is choice C) 40 mi/h.

Question 20

2-9
An object is moving along a straight line in the positive x direction.The graph shows its position from the starting point as a function of time.Various segments of the graph are identified by the letters A, B, C, and D. 
-During which interval(s) did the object move in the negative x direction?
A)only during interval B
B)only during interval C
C)only during interval D
D)during both intervals C and D
E)The object never moved in the negative x direction.

Accepted Answer

The answer of 2-9
An object is moving along a straight...

Quiz 2: Kinematics in One Dimension

What is the speed of the particle after it has traveled 8 m?

2-12 A rock, dropped from rest near the surface of an atmosphere-free planet, attains a speed of 20.0 m/s after falling 8.0 meters. -Determine the speed of the object after falling from rest through 16 m on this planet.

2-12 A rock, dropped from rest near the surface of an atmosphere-free planet, attains a speed of 20.0 m/s after falling 8.0 meters. -What is the magnitude of the acceleration due to gravity on the surface of this planet?

2-15 The figure shows the speed as a function of time for an object in free fall near the surface of the earth. The object was dropped from rest in a long evacuated cylinder. -Which one of the following statements best explains why the graph goes through the origin?

2-13 A brass ball is shot vertically upward from the surface of an atmosphere-free planet with an initial speed of 20.0 m/s.One second later, the ball has an instantaneous velocity in the upward direction of 15.0 m/s. -How high does the ball rise?

After 10 seconds, how far will the particle have traveled?

2-12 A rock, dropped from rest near the surface of an atmosphere-free planet, attains a speed of 20.0 m/s after falling 8.0 meters. -How long would it take the object, falling from rest, to fall 16 m on this planet?

2-10 A automotive test driver travels due north in a prototype hybrid vehicle at 30 mi/h for 2 hours.She then reverses her direction and travels due south at 60 mi/h for 1 hour. -What is the average velocity of the vehicle?

2-13 A brass ball is shot vertically upward from the surface of an atmosphere-free planet with an initial speed of 20.0 m/s.One second later, the ball has an instantaneous velocity in the upward direction of 15.0 m/s. -How long does it take the ball to reach its maximum height?

2-14 A small object is released from rest and falls 1.00 × 10² feet near the surface of the earth.Neglect air resistance. -How long will it take to fall through the 1.00 × 10²feet mentioned?

2-11 Starting from rest, a particle confined to move along a straight line is accelerated at a rate of 4 m/s². -Which statement accurately describes the motion of the particle?

2-13 A brass ball is shot vertically upward from the surface of an atmosphere-free planet with an initial speed of 20.0 m/s.One second later, the ball has an instantaneous velocity in the upward direction of 15.0 m/s. -How long is the ball in the air when it returns to its original position?

2-12 A rock, dropped from rest near the surface of an atmosphere-free planet, attains a speed of 20.0 m/s after falling 8.0 meters. -How long did it take the object to fall the 8.0 meters mentioned?

2-14 A small object is released from rest and falls 1.00 × 10² feet near the surface of the earth.Neglect air resistance. -Approximately how fast will the object be moving after falling through the 1.00 × 10² feet mentioned?

2-10 A automotive test driver travels due north in a prototype hybrid vehicle at 30 mi/h for 2 hours.She then reverses her direction and travels due south at 60 mi/h for 1 hour. -What is the average speed of the vehicle?

2-9 An object is moving along a straight line in the positive x direction.The graph shows its position from the starting point as a function of time.Various segments of the graph are identified by the letters A, B, C, and D. -During which interval(s) did the object move in the negative x direction?

Quiz 2: Kinematics in One Dimension

What is the speed of the particle after it has traveled 8 m?

2-12 A rock, dropped from rest near the surface of an atmosphere-free planet, attains a speed of 20.0 m/s after falling 8.0 meters. -Determine the speed of the object after falling from rest through 16 m on this planet.

2-12 A rock, dropped from rest near the surface of an atmosphere-free planet, attains a speed of 20.0 m/s after falling 8.0 meters. -What is the magnitude of the acceleration due to gravity on the surface of this planet?

2-15 The figure shows the speed as a function of time for an object in free fall near the surface of the earth. The object was dropped from rest in a long evacuated cylinder. -Which one of the following statements best explains why the graph goes through the origin?

2-13 A brass ball is shot vertically upward from the surface of an atmosphere-free planet with an initial speed of 20.0 m/s.One second later, the ball has an instantaneous velocity in the upward direction of 15.0 m/s. -How high does the ball rise?

After 10 seconds, how far will the particle have traveled?

2-12 A rock, dropped from rest near the surface of an atmosphere-free planet, attains a speed of 20.0 m/s after falling 8.0 meters. -How long would it take the object, falling from rest, to fall 16 m on this planet?

2-10 A automotive test driver travels due north in a prototype hybrid vehicle at 30 mi/h for 2 hours.She then reverses her direction and travels due south at 60 mi/h for 1 hour. -What is the average velocity of the vehicle?

2-13 A brass ball is shot vertically upward from the surface of an atmosphere-free planet with an initial speed of 20.0 m/s.One second later, the ball has an instantaneous velocity in the upward direction of 15.0 m/s. -How long does it take the ball to reach its maximum height?

2-14 A small object is released from rest and falls 1.00 × 102 feet near the surface of the earth.Neglect air resistance. -How long will it take to fall through the 1.00 × 102 feet mentioned?

2-11 Starting from rest, a particle confined to move along a straight line is accelerated at a rate of 4 m/s2. -Which statement accurately describes the motion of the particle?

2-13 A brass ball is shot vertically upward from the surface of an atmosphere-free planet with an initial speed of 20.0 m/s.One second later, the ball has an instantaneous velocity in the upward direction of 15.0 m/s. -How long is the ball in the air when it returns to its original position?

2-12 A rock, dropped from rest near the surface of an atmosphere-free planet, attains a speed of 20.0 m/s after falling 8.0 meters. -How long did it take the object to fall the 8.0 meters mentioned?

2-14 A small object is released from rest and falls 1.00 × 102 feet near the surface of the earth.Neglect air resistance. -Approximately how fast will the object be moving after falling through the 1.00 × 102 feet mentioned?

2-10 A automotive test driver travels due north in a prototype hybrid vehicle at 30 mi/h for 2 hours.She then reverses her direction and travels due south at 60 mi/h for 1 hour. -What is the average speed of the vehicle?

2-9 An object is moving along a straight line in the positive x direction.The graph shows its position from the starting point as a function of time.Various segments of the graph are identified by the letters A, B, C, and D. -During which interval(s) did the object move in the negative x direction?

2-14 A small object is released from rest and falls 1.00 × 10² feet near the surface of the earth.Neglect air resistance. -How long will it take to fall through the 1.00 × 10²feet mentioned?

2-11 Starting from rest, a particle confined to move along a straight line is accelerated at a rate of 4 m/s². -Which statement accurately describes the motion of the particle?

2-14 A small object is released from rest and falls 1.00 × 10² feet near the surface of the earth.Neglect air resistance. -Approximately how fast will the object be moving after falling through the 1.00 × 10² feet mentioned?