Jane and Mary will meet outside the library at noon.Jane's arrival time is x and Mary's arrival time is y, where x and y are measured in minutes after noon.The probability density function for the variation in x and y is $p ( x , y ) = \frac { 1 } { 180 } e ^ { - x / 12 } e ^ { - y / 15 }$ After Jane arrives, she will wait up to 15 minutes for Mary, but Mary won't wait for Jane.Find the probability that they meet.

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The Answer of Jane and Mary will meet outside the library at noon.Jane's arrival time is x and Mary's arrival time is y, where x and y are measured in minutes after noon.The probability density function for the variation in x and y is $p ( x , y ) = \frac { 1 } { 180 } e ^ { - x / 12 } e ^ { - y / 15 }$ After Jane arrives, she will wait up to 15 minutes for Mary, but Mary won't wait for Jane.Find the probability that they meet.

Jane and Mary Will Meet Outside the Library at Noon p(x,y)=1180e−x/12e−y/15p ( x , y ) = \frac { 1 } { 180 } e ^ { - x / 12 } e ^ { - y / 15 }p(x,y)=1801​e−x/12e−y/15

Jane and Mary Will Meet Outside the Library at Noon $p ( x , y ) = \frac { 1 } { 180 } e ^ { - x / 12 } e ^ { - y / 15 }$