Find the condition on the non-negative constants a and b for p(x, y)to be a joint density function, where $p ( x , y ) = \left\{ \begin{array} { c l }
a x + b y , & 0 \leq x \leq 8,0 \leq y \leq 8 \
0 & \text { otherwise }
\end{array} \right.$
A) $a + b = \frac { 1 } { 256 }$
B) $a + b = \frac { 1 } { 32 }$
C) $a + b

Question

Find the condition on the non-negative constants a and b for p(x, y)to be a joint density function, where $p ( x , y ) = \left\{ \begin{array} { c l } 
a x + b y , & 0 \leq x \leq 8,0 \leq y \leq 8 \
0 & \text { otherwise }
\end{array} \right.$
A) $a + b = \frac { 1 } { 256 }$
B) $a + b = \frac { 1 } { 32 }$
C) $a + b < \frac { 1 } { 256 }$
D)a=b
E) $a + b = \frac { 1 } { 512 }$

Quizplus · Accepted Answer

The Answer of Find the condition on the non-negative constants a and b for p(x, y)to be a joint density function, where $p ( x , y ) = \left\{ \begin{array} { c l } 
a x + b y , & 0 \leq x \leq 8,0 \leq y \leq 8 \
0 & \text { otherwise }
\end{array} \right.$
A) $a + b = \frac { 1 } { 256 }$
B) $a + b = \frac { 1 } { 32 }$
C) $a + b < \frac { 1 } { 256 }$
D)a=b
E) $a + b = \frac { 1 } { 512 }$

Find the Condition on the Non-Negative Constants a and B p(x,y)={ax+by,0≤x≤8,0≤y≤80 otherwise p ( x , y ) = \left\{ \begin{array} { c l } a x + b y , & 0 \leq x \leq 8,0 \leq y \leq 8 \\0 & \text { otherwise }\end{array} \right.p(x,y)={ax+by,0​0≤x≤8,0≤y≤8 otherwise ​

Find the Condition on the Non-Negative Constants a and B $p ( x , y ) = \left\{ \begin{array} { c l } a x + b y , & 0 \leq x \leq 8,0 \leq y \leq 8 \\0 & \text { otherwise }\end{array} \right.$