Find the limit (if it exists). $\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x }$
A) $\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x } = - 16$
B) $\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x } = - 4$
C) $\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x } = 20$
D) $\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x } = 16$
E) $\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x } = 4$

Question

Find the limit (if it exists).   $\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x }$  
A) $\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x } = - 16$
B) $\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x } = - 4$  
C) $\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x } = 20$
D) $\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x } = 16$
E) $\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x } = 4$

Quizplus · Accepted Answer

The Answer of Find the limit (if it exists).   $\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x }$  
A) $\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x } = - 16$
B) $\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x } = - 4$  
C) $\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x } = 20$
D) $\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x } = 16$
E) $\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x } = 4$

Find the Limit (If It Exists) lim⁡x→π/24(cos⁡x−1)sin⁡x\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x }limx→π/2​sinx4(cosx−1)​

Find the Limit (If It Exists) $\lim _ { x \rightarrow \pi / 2 } \frac { 4 ( \cos x - 1 ) } { \sin x }$