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Find the Limit (If It Exists) lim⁡x→55−xx2−25\lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 }

Question 153

Multiple Choice

Find the limit (if it exists) .Use a graphing utility to verify your result graphically. lim⁡x→55−xx2−25\lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 }


A) lim⁡x→55−xx2−25=−125\lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = - \frac { 1 } { 25 } Find the limit (if it exists) .Use a graphing utility to verify your result graphically. \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } A) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = - \frac { 1 } { 25 } B) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = \frac { 1 } { 10 } C) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = - \frac { 1 } { 10 } D) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = \frac { 1 } { 25 } E) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = - \frac { 1 } { 5 }
B) lim⁡x→55−xx2−25=110\lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = \frac { 1 } { 10 } Find the limit (if it exists) .Use a graphing utility to verify your result graphically. \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } A) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = - \frac { 1 } { 25 } B) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = \frac { 1 } { 10 } C) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = - \frac { 1 } { 10 } D) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = \frac { 1 } { 25 } E) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = - \frac { 1 } { 5 }
C) lim⁡x→55−xx2−25=−110\lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = - \frac { 1 } { 10 } Find the limit (if it exists) .Use a graphing utility to verify your result graphically. \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } A) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = - \frac { 1 } { 25 } B) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = \frac { 1 } { 10 } C) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = - \frac { 1 } { 10 } D) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = \frac { 1 } { 25 } E) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = - \frac { 1 } { 5 }
D) lim⁡x→55−xx2−25=125\lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = \frac { 1 } { 25 } Find the limit (if it exists) .Use a graphing utility to verify your result graphically. \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } A) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = - \frac { 1 } { 25 } B) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = \frac { 1 } { 10 } C) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = - \frac { 1 } { 10 } D) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = \frac { 1 } { 25 } E) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = - \frac { 1 } { 5 }
E) lim⁡x→55−xx2−25=−15\lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = - \frac { 1 } { 5 } Find the limit (if it exists) .Use a graphing utility to verify your result graphically. \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } A) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = - \frac { 1 } { 25 } B) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = \frac { 1 } { 10 } C) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = - \frac { 1 } { 10 } D) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = \frac { 1 } { 25 } E) \lim _ { x \rightarrow 5 } \frac { 5 - x } { x ^ { 2 } - 25 } = - \frac { 1 } { 5 }

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