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Find the Limit (If It Exists) lim⁡x→8x−8x2−64\lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 }

Question 156

Multiple Choice

Find the limit (if it exists) .Use a graphing utility to verify your result graphically. lim⁡x→8x−8x2−64\lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 }


A) lim⁡x→8x−8x2−64=116\lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 16 } Find the limit (if it exists) .Use a graphing utility to verify your result graphically. \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } A) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 16 } B) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 8 } C) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 64 } D) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 64 } E) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 16 }
B) lim⁡x→8x−8x2−64=18\lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 8 } Find the limit (if it exists) .Use a graphing utility to verify your result graphically. \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } A) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 16 } B) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 8 } C) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 64 } D) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 64 } E) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 16 }
C) lim⁡x→8x−8x2−64=164\lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 64 } Find the limit (if it exists) .Use a graphing utility to verify your result graphically. \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } A) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 16 } B) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 8 } C) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 64 } D) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 64 } E) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 16 }
D) lim⁡x→8x−8x2−64=164\lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 64 } Find the limit (if it exists) .Use a graphing utility to verify your result graphically. \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } A) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 16 } B) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 8 } C) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 64 } D) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 64 } E) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 16 }
E) lim⁡x→8x−8x2−64=116\lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 16 } Find the limit (if it exists) .Use a graphing utility to verify your result graphically. \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } A) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 16 } B) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 8 } C) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 64 } D) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 64 } E) \lim _ { x \rightarrow 8 } \frac { x - 8 } { x ^ { 2 } - 64 } = \frac { 1 } { 16 }

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