expand icon
book Introductory Econometrics: A Modern Approach 6th Edition by Jeffrey M Wooldridge cover

Introductory Econometrics: A Modern Approach 6th Edition by Jeffrey M Wooldridge

Edition 6ISBN: 130527010X
book Introductory Econometrics: A Modern Approach 6th Edition by Jeffrey M Wooldridge cover

Introductory Econometrics: A Modern Approach 6th Edition by Jeffrey M Wooldridge

Edition 6ISBN: 130527010X
Exercise 5

Let Y denote a Bernoulli(?) random variable with 0<?<1. Suppose we are interested in estimating the odds ratio, ?= ?/(1- ?), which is the probability of success over the the probability of failure. Given a random sample {Y1, …, Yn}, we know that an unbiased and consistent estimator of ? is  Let Y denote a Bernoulli(?) random variable with 0<?<1. Suppose we are interested in estimating the odds ratio, ?= ?/(1- ?), which is the probability of success over the the probability of failure. Given a random sample {Y<span class=sub>1</span>, …, Y<span class=sub>n</span>}, we know that an unbiased and consistent estimator of ? is   , the proportion of successes in n trials. A natural estimator of ? is G = ?   /(1 -   ), the proportion of successes over the proportion of failures in the sample. <blockquote> (i) Why is G not an unbiased estimator of ? (ii) Use PLIM.2(iii) PLIM.2 If plim (<span class=italics>T</span><span class=italics>n</span>) = ?and plim (<span class=italics>U</span><span class=italics>n</span>) =?, then <blockquote> (i) plim(<span class=italics>T</span><span class=italics>n</span> _+<span class=italics>U</span><span class=italics>n</span>) = ?+ ?; (ii) plim(<span class=italics>T</span><span class=italics>n</span><span class=italics>U</span><span class=italics>n</span>) = ? ?; (iii) plim(<span class=italics>T</span><span class=italics>n</span> /<span class=italics>U</span><span class=italics>n</span>) = ?/?, provided ?<span class=italics>?</span> 0. </blockquote> to show that G is a consistent estimator of ?. </blockquote>   , the proportion of successes in n trials. A natural estimator of ? is G = ?  Let Y denote a Bernoulli(?) random variable with 0<?<1. Suppose we are interested in estimating the odds ratio, ?= ?/(1- ?), which is the probability of success over the the probability of failure. Given a random sample {Y<span class=sub>1</span>, …, Y<span class=sub>n</span>}, we know that an unbiased and consistent estimator of ? is   , the proportion of successes in n trials. A natural estimator of ? is G = ?   /(1 -   ), the proportion of successes over the proportion of failures in the sample. <blockquote> (i) Why is G not an unbiased estimator of ? (ii) Use PLIM.2(iii) PLIM.2 If plim (<span class=italics>T</span><span class=italics>n</span>) = ?and plim (<span class=italics>U</span><span class=italics>n</span>) =?, then <blockquote> (i) plim(<span class=italics>T</span><span class=italics>n</span> _+<span class=italics>U</span><span class=italics>n</span>) = ?+ ?; (ii) plim(<span class=italics>T</span><span class=italics>n</span><span class=italics>U</span><span class=italics>n</span>) = ? ?; (iii) plim(<span class=italics>T</span><span class=italics>n</span> /<span class=italics>U</span><span class=italics>n</span>) = ?/?, provided ?<span class=italics>?</span> 0. </blockquote> to show that G is a consistent estimator of ?. </blockquote>   /(1 - Let Y denote a Bernoulli(?) random variable with 0<?<1. Suppose we are interested in estimating the odds ratio, ?= ?/(1- ?), which is the probability of success over the the probability of failure. Given a random sample {Y<span class=sub>1</span>, …, Y<span class=sub>n</span>}, we know that an unbiased and consistent estimator of ? is   , the proportion of successes in n trials. A natural estimator of ? is G = ?   /(1 -   ), the proportion of successes over the proportion of failures in the sample. <blockquote> (i) Why is G not an unbiased estimator of ? (ii) Use PLIM.2(iii) PLIM.2 If plim (<span class=italics>T</span><span class=italics>n</span>) = ?and plim (<span class=italics>U</span><span class=italics>n</span>) =?, then <blockquote> (i) plim(<span class=italics>T</span><span class=italics>n</span> _+<span class=italics>U</span><span class=italics>n</span>) = ?+ ?; (ii) plim(<span class=italics>T</span><span class=italics>n</span><span class=italics>U</span><span class=italics>n</span>) = ? ?; (iii) plim(<span class=italics>T</span><span class=italics>n</span> /<span class=italics>U</span><span class=italics>n</span>) = ?/?, provided ?<span class=italics>?</span> 0. </blockquote> to show that G is a consistent estimator of ?. </blockquote>   ), the proportion of successes over the proportion of failures in the sample.

(i) Why is G not an unbiased estimator of ?

(ii) Use PLIM.2(iii)

PLIM.2 If plim (Tn) = ?and plim (Un) =?, then

(i) plim(Tn _+Un) = ?+ ?;

(ii) plim(TnUn) = ? ?;

(iii) plim(Tn /Un) = ?/?, provided ?? 0.

to show that G is a consistent estimator of ?.

Step-by-step solution
Verified
like image
like image

Step 1 of 3

It is given that a natural estimator of ? is G.

    <div class=answer> It is given that a natural estimator of <i> ? </i>is <i>G.</i> <i> </i> <i>   </i>


Step 2 of 3


Step 3 of 3

close menu
Introductory Econometrics: A Modern Approach 6th Edition by Jeffrey M Wooldridge
cross icon