Q 82

The heights (in cm)for a random sample of 60 males were measured.The sample mean is 166.55,the standard deviation is 12.57,the sample kurtosis is 0.12,and the sample skewness is −0.23.The following table shows the heights subdivided into non-overlapping intervals. For the goodness-of-fit test for normality,suppose the value of the test statistic is 7.71.Thep-value is _____________.
A) less than 0.01
B) between 0.01 and 0.05
C) between 0.05 and 0.10
D) greater than 0.10

Q 83

The heights (in cm)for a random sample of 60 males were measured.The sample mean is 166.55,the standard deviation is 12.57,the sample kurtosis is 0.12,and the sample skewness is −0.23.The following table shows the heights subdivided into non-overlapping intervals. Using the p-value approach and α = 0.05,the decision and conclusion are ___________________________________________________________________.
A) reject the null hypothesis;conclude that heights are normally distributed
B) reject the null hypothesis;conclude that heights are not normally distributed
C) do not reject the null hypothesis;conclude that heights are normally distributed
D) do not reject the null hypothesis;conclude that heights are not normally distributed

Q 84

The heights (in cm)for a random sample of 60 males were measured.The sample mean is 166.55,the standard deviation is 12.57,the sample kurtosis is 0.12,and the sample skewness is −0.23.The following table shows the heights subdivided into non-overlapping intervals. At the 5% significance level,the critical value is ______.
A) 4.605
B) 5.991
C) 7.378
D) 9.210