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Question 38
Find the reciprocal.- x2+64−x\frac{x^{2}+6}{4-x}4−xx2+6
A) 4−xx2+6\frac{4-x}{x^{2}+6}x2+64−x B) 6−xx2+4\frac{6-x}{x^{2}+4}x2+46−x C) x2+6x−4\frac{x^{2}+6}{x-4}x−4x2+6 D) x2+46−x\frac{x^{2}+4}{6-x}6−xx2+4
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