In this problem, we are asked to use a graphical representation to find the maximum reaction velocity ( V max ) and the Michaelis constant ( K M ).
We can calculate these values by plotting data for the initial reaction velocity ( v 0 ) versus the concentration of the substrate that gave us the resulting v 0 ( [S] ).
From raw date, when we plot v 0 versus v 0 / [S], we will get back a straight line. On this line, the v 0 -intercept will be V max , and the v 0 / [S]-intercept is V max / K M. In this way, we can find both terms from the graph.
Our data is as follows: We first derive v 0 / [S] - our data table changes as follows: We then graph v 0 versus v 0 / [S], receiving the following graph: Thus, our V max will be 140, and our K M will be 4.0x10 -5
In this problem, we are asked to pick which wavelength in a pair has the higher energy:
A) 1 nm (X-ray) or 10,000 nm (IR)B) 280 nm (UV) or 360 nm (VIS)C) 200,000 nm (microwave) or 800 nm (VIS)As a rule, the smaller the wavelength, the higher the energy of the wave in question.
a)The x-ray is higher energy, as it has the smaller wavelength.
b)The UV wave is higher energy, as it has the smaller wavelength.
c)The visible light has higher energy, as it has a smaller wavelength.
In this problem, we are asked to explain why a cuvette with four translucent sides must be used for fluorescence measurements.
The fluorescing light is measured at a right angle from the excitation light, therefore all sides of the cuvette must be translucent so recording can occur.
There is no answer for this question