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Concepts of Genetics 11th Edition by William Klug,Michael Cummings,Charlotte Spencer,Michael Palladino
Edition 11ISBN: 9781292139456Concepts of Genetics 11th Edition by William Klug,Michael Cummings,Charlotte Spencer,Michael Palladino
Edition 11ISBN: 9781292139456 Exercise 31
Most of the techniques described in this chapter (blotting, cloning, PCR, etc.) are dependent on intermolecular attractions (annealing) between different populations of nucleic acids. Length of the strands, temperature, and percentage of GC nucleotides weigh considerably on intermolecular associations. Two other components commonly used in hybridization protocols are monovalent ions and formamide. A formula that takes monovalent ion (Na + ) and formamide concentrations into consideration to compute a T m (temperature of melting) is as follows:
▪m = 81.5 + 16.6(log M[Na + ]) + 0.41(%GC) - 0.72(%formamide)(a) For the following concentrations of Na + and formamide, calculate the T m. Assume 45% GC content.
![Most of the techniques described in this chapter (blotting, cloning, PCR, etc.) are dependent on intermolecular attractions (annealing) between different populations of nucleic acids. Length of the strands, temperature, and percentage of GC nucleotides weigh considerably on intermolecular associations. Two other components commonly used in hybridization protocols are monovalent ions and formamide. A formula that takes monovalent ion (Na + ) and formamide concentrations into consideration to compute a T m (temperature of melting) is as follows: ▪m = 81.5 + 16.6(log M[Na + ]) + 0.41(%GC) - 0.72(%formamide)(a) For the following concentrations of Na + and formamide, calculate the T m. Assume 45% GC content. (b) Given that formamide competes for hydrogen bond locations of nucleic acid bases and monovalent cations are attracted to the negative charges of nucleic acids, explain why the T m varies as described in part (a).](https://d2lvgg3v3hfg70.cloudfront.net/SM1220/11eb563d_4e4d_b08e_a8c8_a34db556a8b2_SM1220_00.jpg)
(b) Given that formamide competes for hydrogen bond locations of nucleic acid bases and monovalent cations are attracted to the negative charges of nucleic acids, explain why the T m varies as described in part (a).
▪m = 81.5 + 16.6(log M[Na + ]) + 0.41(%GC) - 0.72(%formamide)(a) For the following concentrations of Na + and formamide, calculate the T m. Assume 45% GC content.
(b) Given that formamide competes for hydrogen bond locations of nucleic acid bases and monovalent cations are attracted to the negative charges of nucleic acids, explain why the T m varies as described in part (a).Explanation
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(a)The equation for melting temperature ...
Concepts of Genetics 11th Edition by William Klug,Michael Cummings,Charlotte Spencer,Michael Palladino
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