Deck 11: Analysis of Variance

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Question
Hartley's test measures the equality of the means for several groups.
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Question
Tukey's test is not needed if we have the overall F statistic for the ANOVA.
Question
Analysis of variance is a procedure intended to compare the means of c samples.
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In a two-factor ANOVA with three columns and four rows,there can be more than two interaction effects.
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One-factor ANOVA with two groups is equivalent to a two-tailed t-test.
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Hartley's test is the largest sample mean divided by the smallest sample mean.
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Three-factor ANOVA is required if we have three treatment groups (i.e. ,three data columns).
Question
One factor ANOVA stacked data for five groups will be arranged in five separate columns.
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Sample sizes must be equal in one-factor ANOVA.
Question
ANOVA assumes equal variances within each treatment group.
Question
Tukey's test compares pairs of treatment means in an ANOVA.
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Hartley's test is to check for unequal variances for c groups.
Question
ANOVA assumes normal populations.
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Interaction plots that show crossing lines indicate likely interactions.
Question
If you have four factors (call them A,B,C,and D)in an ANOVA experiment with replication,you could have a maximum of four different two-factor interactions.
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Interaction plots that show parallel lines would suggest interaction effects.
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One-factor ANOVA is a procedure intended to compare the variances of c samples.
Question
Comparison of c means in one-factor ANOVA can equivalently be done by using c individual t-tests on c pairs of means at the same α.
Question
In a 3×4 randomized block (two-factor unreplicated)ANOVA,we have 12 treatment groups.
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Tukey's test is similar to a two-sample t-test except that it pools the variances for all c samples.
Question
Which of the following is not a characteristic of the F distribution?

A) It is always right-skewed.
B) It describes the ratio of two variances.
C) It is a family based on two sets of degrees of freedom.
D) It is negative when s12 is smaller than s22.
Question
Analysis of variance is a technique used to test for:

A) equality of two or more variances.
B) equality of two or more means.
C) equality of a population mean and a given value.
D) equality of more than two variances.
Question
ANOVA is robust to violations of the equal-variance assumption as long as group sizes are equal.
Question
Tukey's test for five groups would require 10 comparisons of means.
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Tukey's test pools all the sample variances.
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It is desirable,but not necessary,that sample sizes be equal in a one-factor ANOVA.
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In an ANOVA,when would the F-test statistic be zero?

A) When there is no difference in the variances.
B) When the treatment means are the same.
C) When the observations are normally distributed.
D) The F-test statistic cannot ever be zero.
Question
Degrees of freedom for the between-group variation in a one-factor ANOVA with n1 = 8,n2 = 5,n3 = 7,n4 = 9 would be:

A) 28.
B) 3.
C) 29.
Question
Levene's test for homogeneity of variance is attractive because it does not depend on the assumption of normality.
Question
ANOVA is used to compare:

A) proportions of several groups.
B) variances of several groups.
C) means of several groups.
D) both means and variances.
Question
Which is not assumed in ANOVA?

A) Observations are independent.
B) Populations are normally distributed.
C) Variances of all treatment groups are the same.
D) Population variances are known.
Question
To test the null hypothesis H0: μ1 = μ2 = μ3 using samples from normal populations with unknown but equal variances,we:

A) cannot safely use ANOVA.
B) can safely employ ANOVA.
C) would prefer three separate t-tests.
D) would need three-factor ANOVA.
Question
In a one-factor ANOVA,the computed value of F will be negative:

A) when there is no difference in the treatment means.
B) when there is no difference within the treatments.
C) when the SST (total)is larger than SSE (error).
D) under no circumstances.
Question
Using one-factor ANOVA with 30 observations we find at α = .05 that we cannot reject the null hypothesis of equal means.We increase the sample size from 30 observations to 60 observations and obtain the same value for the sample F-test statistic.Which is correct?

A) We might now be able to reject the null hypothesis.
B) We surely must reject H0 for 60 observations.
C) We cannot reject H0 since we obtained the same F-value.
D) It is impossible to get the same F-value for n = 60 as for n = 30.
Question
Which is the Excel function to find the critical value of F for α = .05,df1 = 3,df2 = 25?

A) =F.DIST(.05,2,24)
B) =F.INV.RT(.05,3,25)
C) =F.DIST(.05,3,25)
D) =F.INV(.05,2,24)
Question
Tukey's test with seven groups would entail 21 comparisons of means.
Question
In an ANOVA,the SSE (error)sum of squares reflects:

A) the effect of the combined factor(s).
B) the overall variation in Y that is to be explained.
C) the variation that is not explained by the factors.
D) the combined effect of treatments and sample size.
Question
Which is not an assumption of ANOVA?

A) Normality of the treatment populations.
B) Homogeneous treatment variances.
C) Independent sample observations.
D) Equal population sizes for groups.
Question
Which Excel function gives the right-tail p-value for an ANOVA test with a test statistic Fcalc = 4.52,n = 29 observations,and c = 4 groups?

A) =F.DIST.RT(4.52,3,25)
B) =F.INV(4.52,4,28)
C) =F.DIST(4.52,4,28)
D) =F.INV(4.52,3,25)
Question
Variation "within" the ANOVA treatments represents:

A) random variation.
B) differences between group means.
C) differences between group variances.
D) the effect of sample size.
Question
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   The F-test statistic is:</strong> A) 2.84. B) 3.56. C) 2.80. D) 2.79. <div style=padding-top: 35px> The F-test statistic is:

A) 2.84.
B) 3.56.
C) 2.80.
D) 2.79.
Question
One-factor analysis of variance:

A) requires that the number of observations in each group be identical.
B) has less power when the number of observations per group is not identical.
C) is extremely sensitive to slight departures from normality.
D) is a generalization of the t-test for paired observations.
Question
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   The sample size is:</strong> A) 20. B) 23. C) 24. <div style=padding-top: 35px> The sample size is:

A) 20.
B) 23.
C) 24.
Question
In a one-factor ANOVA,the total sum of squares is equal to:

A) the sum of squares within groups plus the sum of squares between groups.
B) the sum of squares within groups times the sum of squares between groups.
C) the sum of squares within groups divided by the sum of squares between groups.
D) the means of all the groups squared.
Question
The within-treatment variation reflects:

A) variation among individuals of the same group.
B) variation between individuals in different groups.
C) variation explained by factors included in the ANOVA model.
D) variation that is not part of the ANOVA model.
Question
The Internal Revenue Service wishes to study the time required to process tax returns in three regional centers.A random sample of three tax returns is chosen from each of three centers.The time (in days)required to process each return is recorded as shown below. <strong>The Internal Revenue Service wishes to study the time required to process tax returns in three regional centers.A random sample of three tax returns is chosen from each of three centers.The time (in days)required to process each return is recorded as shown below.   The test to use to compare the means for all three groups would require:</strong> A) three-factor ANOVA. B) one-factor ANOVA. C) repeated two-sample test of means. D) two-factor ANOVA with replication. <div style=padding-top: 35px> The test to use to compare the means for all three groups would require:

A) three-factor ANOVA.
B) one-factor ANOVA.
C) repeated two-sample test of means.
D) two-factor ANOVA with replication.
Question
The Internal Revenue Service wishes to study the time required to process tax returns in three regional centers.A random sample of three tax returns is chosen from each of three centers.The time (in days)required to process each return is recorded as shown below. <strong>The Internal Revenue Service wishes to study the time required to process tax returns in three regional centers.A random sample of three tax returns is chosen from each of three centers.The time (in days)required to process each return is recorded as shown below.   Degrees of freedom for the between-groups sum of squares in the ANOVA would be:</strong> A) 11. B) 2. C) 4. <div style=padding-top: 35px> Degrees of freedom for the between-groups sum of squares in the ANOVA would be:

A) 11.
B) 2.
C) 4.
Question
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   Degrees of freedom for the F-test are:</strong> A) 5,22. B) 4,21. C) 3,20. D) impossible to determine. <div style=padding-top: 35px> Degrees of freedom for the F-test are:

A) 5,22.
B) 4,21.
C) 3,20.
D) impossible to determine.
Question
Systolic blood pressure of randomly selected HMO patients was recorded on a particular Wednesday,with the results shown here: <strong>Systolic blood pressure of randomly selected HMO patients was recorded on a particular Wednesday,with the results shown here:   The appropriate hypothesis test is:</strong> A) one-factor ANOVA. B) two-factor ANOVA. C) three-factor ANOVA. D) four-factor ANOVA. <div style=padding-top: 35px> The appropriate hypothesis test is:

A) one-factor ANOVA.
B) two-factor ANOVA.
C) three-factor ANOVA.
D) four-factor ANOVA.
Question
Prof.Gristmill sampled exam scores for five randomly chosen students from each of his two sections of ACC 200.His sample results are shown. <strong>Prof.Gristmill sampled exam scores for five randomly chosen students from each of his two sections of ACC 200.His sample results are shown.   He could test the population means for equality using:</strong> A) a t-test for two means from independent samples. B) a t-test for two means from paired (related)samples. C) a one-factor ANOVA. D) either a one-factor ANOVA or a two-tailed t-test. <div style=padding-top: 35px> He could test the population means for equality using:

A) a t-test for two means from independent samples.
B) a t-test for two means from paired (related)samples.
C) a one-factor ANOVA.
D) either a one-factor ANOVA or a two-tailed t-test.
Question
For this one-factor ANOVA (some information is missing),what is the F-test statistic? <strong>For this one-factor ANOVA (some information is missing),what is the F-test statistic?  </strong> A) 0.159 B) 2.833 C) 1.703 D) Cannot be determined <div style=padding-top: 35px>

A) 0.159
B) 2.833
C) 1.703
D) Cannot be determined
Question
Identify the degrees of freedom for the treatment and error in this one-factor ANOVA (blanks indicate missing information). <strong>Identify the degrees of freedom for the treatment and error in this one-factor ANOVA (blanks indicate missing information).  </strong> A) 4,24 B) 3,20 C) 5,23 <div style=padding-top: 35px>

A) 4,24
B) 3,20
C) 5,23
Question
For this one-factor ANOVA (some information is missing),how many treatment groups were there? <strong>For this one-factor ANOVA (some information is missing),how many treatment groups were there?  </strong> A) Cannot be determined B) 3 C) 4 D) 2 <div style=padding-top: 35px>

A) Cannot be determined
B) 3
C) 4
D) 2
Question
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   Degrees of freedom for between groups variation are:</strong> A) 3. B) 4. C) 5. D) Can't tell from given information. <div style=padding-top: 35px> Degrees of freedom for between groups variation are:

A) 3.
B) 4.
C) 5.
D) Can't tell from given information.
Question
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   At α = 0.05,the difference between group means is:</strong> A) highly significant. B) barely significant. C) not quite significant. D) clearly insignificant. <div style=padding-top: 35px> At α = 0.05,the difference between group means is:

A) highly significant.
B) barely significant.
C) not quite significant.
D) clearly insignificant.
Question
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   SS for between groups variation will be:</strong> A) 129.99. B) 630.83. C) 1233.4. D) Can't tell. <div style=padding-top: 35px> SS for between groups variation will be:

A) 129.99.
B) 630.83.
C) 1233.4.
D) Can't tell.
Question
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   The critical value of F at α = 0.05 is:</strong> A) 1.645. B) 2.84. C) 3.10. D) 4.28. <div style=padding-top: 35px> The critical value of F at α = 0.05 is:

A) 1.645.
B) 2.84.
C) 3.10.
D) 4.28.
Question
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   The number of treatment groups is:</strong> A) 4. B) 3. C) 2. D) <div style=padding-top: 35px> The number of treatment groups is:

A) 4.
B) 3.
C) 2.
D)
Question
Given the following ANOVA table (some information is missing),find the critical value of F.05. <strong>Given the following ANOVA table (some information is missing),find the critical value of F<sub>.05</sub>.  </strong> A) 3.06 B) 2.90 C) 2.36 D) 3.41 <div style=padding-top: 35px>

A) 3.06
B) 2.90
C) 2.36
D) 3.41
Question
Given the following ANOVA table (some information is missing),find the F statistic. <strong>Given the following ANOVA table (some information is missing),find the F statistic.  </strong> A) 3.71 B) 0.99 C) 0.497 D) 4.02 <div style=padding-top: 35px>

A) 3.71
B) 0.99
C) 0.497
D) 4.02
Question
Refer to the following partial ANOVA results from Excel (some information is missing). ANOVA Table <strong>Refer to the following partial ANOVA results from Excel (some information is missing). ANOVA Table   The number of treatment groups is:</strong> A) 5. B) 4. C) 3. D) impossible to ascertain from given. <div style=padding-top: 35px> The number of treatment groups is:

A) 5.
B) 4.
C) 3.
D) impossible to ascertain from given.
Question
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   The number of observations in the entire sample is:</strong> A) 20. B) 19. C) <div style=padding-top: 35px> The number of observations in the entire sample is:

A) 20.
B) 19.
C)
Question
Systolic blood pressure of randomly selected HMO patients was recorded on a particular Wednesday,with the results shown here.An ANOVA test was performed using these data. <strong>Systolic blood pressure of randomly selected HMO patients was recorded on a particular Wednesday,with the results shown here.An ANOVA test was performed using these data.   What are the degrees of freedom for the error sum of squares?</strong> A) 3 B) 19 C) 16 D) It depends on α. <div style=padding-top: 35px> What are the degrees of freedom for the error sum of squares?

A) 3
B) 19
C) 16
D) It depends on α.
Question
Refer to the following partial ANOVA results from Excel (some information is missing). ANOVA Table <strong>Refer to the following partial ANOVA results from Excel (some information is missing). ANOVA Table   The number of observations in the original sample was:</strong> A) 59. B) 60. C) 58. <div style=padding-top: 35px> The number of observations in the original sample was:

A) 59.
B) 60.
C) 58.
Question
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   The MS (mean square)for the treatments is:</strong> A) 239.13. B) 106.88. C) 1,130.8. D) impossible to ascertain from the information given. <div style=padding-top: 35px> The MS (mean square)for the treatments is:

A) 239.13.
B) 106.88.
C) 1,130.8.
D) impossible to ascertain from the information given.
Question
To compare the cost of three shipping methods,a random sample of four shipments is taken for each of three firms.The cost per shipment is shown below. <strong>To compare the cost of three shipping methods,a random sample of four shipments is taken for each of three firms.The cost per shipment is shown below.   In a one-factor ANOVA,degrees of freedom for the between-groups sum of squares will be:</strong> A) 11. B) 3. C) 2. <div style=padding-top: 35px> In a one-factor ANOVA,degrees of freedom for the between-groups sum of squares will be:

A) 11.
B) 3.
C) 2.
Question
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   Our decision about the hypothesis of equal treatment means is that the null hypothesis:</strong> A) cannot be rejected at α = .05. B) can be rejected at α = .05. C) can be rejected for any typical value of α. D) cannot be assessed from the given information. <div style=padding-top: 35px> Our decision about the hypothesis of equal treatment means is that the null hypothesis:

A) cannot be rejected at α = .05.
B) can be rejected at α = .05.
C) can be rejected for any typical value of α.
D) cannot be assessed from the given information.
Question
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   The F statistic is:</strong> A) 4.87. B) 3.38. C) 5.93. D) 6.91. <div style=padding-top: 35px> The F statistic is:

A) 4.87.
B) 3.38.
C) 5.93.
D) 6.91.
Question
Systolic blood pressure of randomly selected HMO patients was recorded on a particular Wednesday,with the results shown here.An ANOVA test was performed using these data. <strong>Systolic blood pressure of randomly selected HMO patients was recorded on a particular Wednesday,with the results shown here.An ANOVA test was performed using these data.   Degrees of freedom for the between-treatments sum of squares would be:</strong> A) 3. B) 19. C) 17. D) depends on α. <div style=padding-top: 35px> Degrees of freedom for the between-treatments sum of squares would be:

A) 3.
B) 19.
C) 17.
D) depends on α.
Question
To compare the cost of three shipping methods,a random sample of four shipments is taken for each of three firms.The cost per shipment is shown below. <strong>To compare the cost of three shipping methods,a random sample of four shipments is taken for each of three firms.The cost per shipment is shown below.   In a one-factor ANOVA,degrees of freedom for the within-groups sum of squares will be:</strong> A) 11. B) 3. C) 9. <div style=padding-top: 35px> In a one-factor ANOVA,degrees of freedom for the within-groups sum of squares will be:

A) 11.
B) 3.
C) 9.
Question
Refer to the following partial ANOVA results from Excel (some information is missing). ANOVA Table <strong>Refer to the following partial ANOVA results from Excel (some information is missing). ANOVA Table   The F statistic is:</strong> A) 2.88. B) 4.87. C) 5.93. D) 6.91. <div style=padding-top: 35px> The F statistic is:

A) 2.88.
B) 4.87.
C) 5.93.
D) 6.91.
Question
What is the .05 critical value of Tukey's test statistic for a one-factor ANOVA with n1 = 6,n2 = 6,n3 = 6? Note: This question requires access to a Tukey table.

A) 3.67
B) 2.60
C) 3.58
D) 2.75
Question
Refer to the following MegaStat output (some information is missing).The sample size was n = 65 in a one-factor ANOVA. <strong>Refer to the following MegaStat output (some information is missing).The sample size was n = 65 in a one-factor ANOVA.   At α = .05,which is the critical value of the test statistic for a two-tailed test for a significant difference in means that are to be compared simultaneously? Note: This question requires a Tukey table.</strong> A) 2.81 B) 2.54 C) 2.33 D) 1.96 <div style=padding-top: 35px> At α = .05,which is the critical value of the test statistic for a two-tailed test for a significant difference in means that are to be compared simultaneously? Note: This question requires a Tukey table.

A) 2.81
B) 2.54
C) 2.33
D) 1.96
Question
Refer to the following MegaStat output (some information is missing).The sample size was n = 24 in a one-factor ANOVA. <strong>Refer to the following MegaStat output (some information is missing).The sample size was n = 24 in a one-factor ANOVA.   At α = .05,what is the critical value of the Tukey test statistic for a two-tailed test for a significant difference in means that are to be compared simultaneously? Note: This question requires access to a Tukey table.</strong> A) 2.07 B) 2.80 C) 2.76 D) 1.96 <div style=padding-top: 35px> At α = .05,what is the critical value of the Tukey test statistic for a two-tailed test for a significant difference in means that are to be compared simultaneously? Note: This question requires access to a Tukey table.

A) 2.07
B) 2.80
C) 2.76
D) 1.96
Question
Refer to the following MegaStat output (some information is missing).The sample size was n = 65 in a one-factor ANOVA. <strong>Refer to the following MegaStat output (some information is missing).The sample size was n = 65 in a one-factor ANOVA.   Which pairs of days differ significantly? Note: This question requires access to a Tukey table.</strong> A) (Mon,Thu)and (Mon,Wed)only. B) (Mon,Wed)only. C) (Mon,Thu)only. D) (Mon,Thu)and (Mon,Wed)and (Mon,Fri)and (Mon,Tue). <div style=padding-top: 35px> Which pairs of days differ significantly? Note: This question requires access to a Tukey table.

A) (Mon,Thu)and (Mon,Wed)only.
B) (Mon,Wed)only.
C) (Mon,Thu)only.
D) (Mon,Thu)and (Mon,Wed)and (Mon,Fri)and (Mon,Tue).
Question
What is the .05 critical value of Hartley's test statistic for a one-factor ANOVA with n1 = 5,n2 = 8,n3 = 7,n4 = 8,n5 = 6,n6 = 8? Note: This question requires access to a Hartley table.

A) 10.8
B) 11.8
C) 13.7
D) 15.0
Question
Sound levels are measured at random moments under typical driving conditions for various full-size truck models.The ANOVA results are shown below. <strong>Sound levels are measured at random moments under typical driving conditions for various full-size truck models.The ANOVA results are shown below.   The test statistic for Hartley's test for homogeneity of variance is:</strong> A) 2.25. B) 5.04. C) 4.61. D) 4.45. <div style=padding-top: 35px> The test statistic for Hartley's test for homogeneity of variance is:

A) 2.25.
B) 5.04.
C) 4.61.
D) 4.45.
Question
Refer to the following MegaStat output (some information is missing).The sample size was n = 24 in a one-factor ANOVA. <strong>Refer to the following MegaStat output (some information is missing).The sample size was n = 24 in a one-factor ANOVA.   Which pairs of meds differ at α = .05? Note: This question requires access to a Tukey table.</strong> A) Med 1,Med 2 B) Med 2,Med 4 C) Med 3,Med 4 D) None of them. <div style=padding-top: 35px> Which pairs of meds differ at α = .05? Note: This question requires access to a Tukey table.

A) Med 1,Med 2
B) Med 2,Med 4
C) Med 3,Med 4
D) None of them.
Question
Sound levels are measured at random moments under typical driving conditions for various full-size truck models.The Excel ANOVA results are shown below. <strong>Sound levels are measured at random moments under typical driving conditions for various full-size truck models.The Excel ANOVA results are shown below.   The test statistic to compare the five means simultaneously is:</strong> A) 2.96. B) 15.8. C) 5.56. D) 4.45. <div style=padding-top: 35px> The test statistic to compare the five means simultaneously is:

A) 2.96.
B) 15.8.
C) 5.56.
D) 4.45.
Question
To compare the cost of three shipping methods,a random sample of four shipments is taken for each of three firms.The cost per shipment is shown below. <strong>To compare the cost of three shipping methods,a random sample of four shipments is taken for each of three firms.The cost per shipment is shown below.   Degrees of freedom for the total sum of squares in a one-factor ANOVA would be:</strong> A) 11. B) 8. C) 2. <div style=padding-top: 35px> Degrees of freedom for the total sum of squares in a one-factor ANOVA would be:

A) 11.
B) 8.
C) 2.
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Deck 11: Analysis of Variance
1
Hartley's test measures the equality of the means for several groups.
False
2
Tukey's test is not needed if we have the overall F statistic for the ANOVA.
False
3
Analysis of variance is a procedure intended to compare the means of c samples.
True
4
In a two-factor ANOVA with three columns and four rows,there can be more than two interaction effects.
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5
One-factor ANOVA with two groups is equivalent to a two-tailed t-test.
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6
Hartley's test is the largest sample mean divided by the smallest sample mean.
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7
Three-factor ANOVA is required if we have three treatment groups (i.e. ,three data columns).
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8
One factor ANOVA stacked data for five groups will be arranged in five separate columns.
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9
Sample sizes must be equal in one-factor ANOVA.
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10
ANOVA assumes equal variances within each treatment group.
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11
Tukey's test compares pairs of treatment means in an ANOVA.
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12
Hartley's test is to check for unequal variances for c groups.
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13
ANOVA assumes normal populations.
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14
Interaction plots that show crossing lines indicate likely interactions.
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15
If you have four factors (call them A,B,C,and D)in an ANOVA experiment with replication,you could have a maximum of four different two-factor interactions.
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16
Interaction plots that show parallel lines would suggest interaction effects.
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17
One-factor ANOVA is a procedure intended to compare the variances of c samples.
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18
Comparison of c means in one-factor ANOVA can equivalently be done by using c individual t-tests on c pairs of means at the same α.
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19
In a 3×4 randomized block (two-factor unreplicated)ANOVA,we have 12 treatment groups.
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20
Tukey's test is similar to a two-sample t-test except that it pools the variances for all c samples.
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21
Which of the following is not a characteristic of the F distribution?

A) It is always right-skewed.
B) It describes the ratio of two variances.
C) It is a family based on two sets of degrees of freedom.
D) It is negative when s12 is smaller than s22.
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22
Analysis of variance is a technique used to test for:

A) equality of two or more variances.
B) equality of two or more means.
C) equality of a population mean and a given value.
D) equality of more than two variances.
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23
ANOVA is robust to violations of the equal-variance assumption as long as group sizes are equal.
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24
Tukey's test for five groups would require 10 comparisons of means.
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25
Tukey's test pools all the sample variances.
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26
It is desirable,but not necessary,that sample sizes be equal in a one-factor ANOVA.
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27
In an ANOVA,when would the F-test statistic be zero?

A) When there is no difference in the variances.
B) When the treatment means are the same.
C) When the observations are normally distributed.
D) The F-test statistic cannot ever be zero.
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28
Degrees of freedom for the between-group variation in a one-factor ANOVA with n1 = 8,n2 = 5,n3 = 7,n4 = 9 would be:

A) 28.
B) 3.
C) 29.
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29
Levene's test for homogeneity of variance is attractive because it does not depend on the assumption of normality.
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30
ANOVA is used to compare:

A) proportions of several groups.
B) variances of several groups.
C) means of several groups.
D) both means and variances.
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31
Which is not assumed in ANOVA?

A) Observations are independent.
B) Populations are normally distributed.
C) Variances of all treatment groups are the same.
D) Population variances are known.
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32
To test the null hypothesis H0: μ1 = μ2 = μ3 using samples from normal populations with unknown but equal variances,we:

A) cannot safely use ANOVA.
B) can safely employ ANOVA.
C) would prefer three separate t-tests.
D) would need three-factor ANOVA.
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33
In a one-factor ANOVA,the computed value of F will be negative:

A) when there is no difference in the treatment means.
B) when there is no difference within the treatments.
C) when the SST (total)is larger than SSE (error).
D) under no circumstances.
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34
Using one-factor ANOVA with 30 observations we find at α = .05 that we cannot reject the null hypothesis of equal means.We increase the sample size from 30 observations to 60 observations and obtain the same value for the sample F-test statistic.Which is correct?

A) We might now be able to reject the null hypothesis.
B) We surely must reject H0 for 60 observations.
C) We cannot reject H0 since we obtained the same F-value.
D) It is impossible to get the same F-value for n = 60 as for n = 30.
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35
Which is the Excel function to find the critical value of F for α = .05,df1 = 3,df2 = 25?

A) =F.DIST(.05,2,24)
B) =F.INV.RT(.05,3,25)
C) =F.DIST(.05,3,25)
D) =F.INV(.05,2,24)
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36
Tukey's test with seven groups would entail 21 comparisons of means.
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37
In an ANOVA,the SSE (error)sum of squares reflects:

A) the effect of the combined factor(s).
B) the overall variation in Y that is to be explained.
C) the variation that is not explained by the factors.
D) the combined effect of treatments and sample size.
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38
Which is not an assumption of ANOVA?

A) Normality of the treatment populations.
B) Homogeneous treatment variances.
C) Independent sample observations.
D) Equal population sizes for groups.
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39
Which Excel function gives the right-tail p-value for an ANOVA test with a test statistic Fcalc = 4.52,n = 29 observations,and c = 4 groups?

A) =F.DIST.RT(4.52,3,25)
B) =F.INV(4.52,4,28)
C) =F.DIST(4.52,4,28)
D) =F.INV(4.52,3,25)
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40
Variation "within" the ANOVA treatments represents:

A) random variation.
B) differences between group means.
C) differences between group variances.
D) the effect of sample size.
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41
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   The F-test statistic is:</strong> A) 2.84. B) 3.56. C) 2.80. D) 2.79. The F-test statistic is:

A) 2.84.
B) 3.56.
C) 2.80.
D) 2.79.
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42
One-factor analysis of variance:

A) requires that the number of observations in each group be identical.
B) has less power when the number of observations per group is not identical.
C) is extremely sensitive to slight departures from normality.
D) is a generalization of the t-test for paired observations.
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43
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   The sample size is:</strong> A) 20. B) 23. C) 24. The sample size is:

A) 20.
B) 23.
C) 24.
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44
In a one-factor ANOVA,the total sum of squares is equal to:

A) the sum of squares within groups plus the sum of squares between groups.
B) the sum of squares within groups times the sum of squares between groups.
C) the sum of squares within groups divided by the sum of squares between groups.
D) the means of all the groups squared.
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45
The within-treatment variation reflects:

A) variation among individuals of the same group.
B) variation between individuals in different groups.
C) variation explained by factors included in the ANOVA model.
D) variation that is not part of the ANOVA model.
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46
The Internal Revenue Service wishes to study the time required to process tax returns in three regional centers.A random sample of three tax returns is chosen from each of three centers.The time (in days)required to process each return is recorded as shown below. <strong>The Internal Revenue Service wishes to study the time required to process tax returns in three regional centers.A random sample of three tax returns is chosen from each of three centers.The time (in days)required to process each return is recorded as shown below.   The test to use to compare the means for all three groups would require:</strong> A) three-factor ANOVA. B) one-factor ANOVA. C) repeated two-sample test of means. D) two-factor ANOVA with replication. The test to use to compare the means for all three groups would require:

A) three-factor ANOVA.
B) one-factor ANOVA.
C) repeated two-sample test of means.
D) two-factor ANOVA with replication.
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47
The Internal Revenue Service wishes to study the time required to process tax returns in three regional centers.A random sample of three tax returns is chosen from each of three centers.The time (in days)required to process each return is recorded as shown below. <strong>The Internal Revenue Service wishes to study the time required to process tax returns in three regional centers.A random sample of three tax returns is chosen from each of three centers.The time (in days)required to process each return is recorded as shown below.   Degrees of freedom for the between-groups sum of squares in the ANOVA would be:</strong> A) 11. B) 2. C) 4. Degrees of freedom for the between-groups sum of squares in the ANOVA would be:

A) 11.
B) 2.
C) 4.
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48
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   Degrees of freedom for the F-test are:</strong> A) 5,22. B) 4,21. C) 3,20. D) impossible to determine. Degrees of freedom for the F-test are:

A) 5,22.
B) 4,21.
C) 3,20.
D) impossible to determine.
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49
Systolic blood pressure of randomly selected HMO patients was recorded on a particular Wednesday,with the results shown here: <strong>Systolic blood pressure of randomly selected HMO patients was recorded on a particular Wednesday,with the results shown here:   The appropriate hypothesis test is:</strong> A) one-factor ANOVA. B) two-factor ANOVA. C) three-factor ANOVA. D) four-factor ANOVA. The appropriate hypothesis test is:

A) one-factor ANOVA.
B) two-factor ANOVA.
C) three-factor ANOVA.
D) four-factor ANOVA.
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50
Prof.Gristmill sampled exam scores for five randomly chosen students from each of his two sections of ACC 200.His sample results are shown. <strong>Prof.Gristmill sampled exam scores for five randomly chosen students from each of his two sections of ACC 200.His sample results are shown.   He could test the population means for equality using:</strong> A) a t-test for two means from independent samples. B) a t-test for two means from paired (related)samples. C) a one-factor ANOVA. D) either a one-factor ANOVA or a two-tailed t-test. He could test the population means for equality using:

A) a t-test for two means from independent samples.
B) a t-test for two means from paired (related)samples.
C) a one-factor ANOVA.
D) either a one-factor ANOVA or a two-tailed t-test.
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51
For this one-factor ANOVA (some information is missing),what is the F-test statistic? <strong>For this one-factor ANOVA (some information is missing),what is the F-test statistic?  </strong> A) 0.159 B) 2.833 C) 1.703 D) Cannot be determined

A) 0.159
B) 2.833
C) 1.703
D) Cannot be determined
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52
Identify the degrees of freedom for the treatment and error in this one-factor ANOVA (blanks indicate missing information). <strong>Identify the degrees of freedom for the treatment and error in this one-factor ANOVA (blanks indicate missing information).  </strong> A) 4,24 B) 3,20 C) 5,23

A) 4,24
B) 3,20
C) 5,23
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53
For this one-factor ANOVA (some information is missing),how many treatment groups were there? <strong>For this one-factor ANOVA (some information is missing),how many treatment groups were there?  </strong> A) Cannot be determined B) 3 C) 4 D) 2

A) Cannot be determined
B) 3
C) 4
D) 2
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54
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   Degrees of freedom for between groups variation are:</strong> A) 3. B) 4. C) 5. D) Can't tell from given information. Degrees of freedom for between groups variation are:

A) 3.
B) 4.
C) 5.
D) Can't tell from given information.
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55
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   At α = 0.05,the difference between group means is:</strong> A) highly significant. B) barely significant. C) not quite significant. D) clearly insignificant. At α = 0.05,the difference between group means is:

A) highly significant.
B) barely significant.
C) not quite significant.
D) clearly insignificant.
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56
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   SS for between groups variation will be:</strong> A) 129.99. B) 630.83. C) 1233.4. D) Can't tell. SS for between groups variation will be:

A) 129.99.
B) 630.83.
C) 1233.4.
D) Can't tell.
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57
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   The critical value of F at α = 0.05 is:</strong> A) 1.645. B) 2.84. C) 3.10. D) 4.28. The critical value of F at α = 0.05 is:

A) 1.645.
B) 2.84.
C) 3.10.
D) 4.28.
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58
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   The number of treatment groups is:</strong> A) 4. B) 3. C) 2. D) The number of treatment groups is:

A) 4.
B) 3.
C) 2.
D)
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59
Given the following ANOVA table (some information is missing),find the critical value of F.05. <strong>Given the following ANOVA table (some information is missing),find the critical value of F<sub>.05</sub>.  </strong> A) 3.06 B) 2.90 C) 2.36 D) 3.41

A) 3.06
B) 2.90
C) 2.36
D) 3.41
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60
Given the following ANOVA table (some information is missing),find the F statistic. <strong>Given the following ANOVA table (some information is missing),find the F statistic.  </strong> A) 3.71 B) 0.99 C) 0.497 D) 4.02

A) 3.71
B) 0.99
C) 0.497
D) 4.02
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61
Refer to the following partial ANOVA results from Excel (some information is missing). ANOVA Table <strong>Refer to the following partial ANOVA results from Excel (some information is missing). ANOVA Table   The number of treatment groups is:</strong> A) 5. B) 4. C) 3. D) impossible to ascertain from given. The number of treatment groups is:

A) 5.
B) 4.
C) 3.
D) impossible to ascertain from given.
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62
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   The number of observations in the entire sample is:</strong> A) 20. B) 19. C) The number of observations in the entire sample is:

A) 20.
B) 19.
C)
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63
Systolic blood pressure of randomly selected HMO patients was recorded on a particular Wednesday,with the results shown here.An ANOVA test was performed using these data. <strong>Systolic blood pressure of randomly selected HMO patients was recorded on a particular Wednesday,with the results shown here.An ANOVA test was performed using these data.   What are the degrees of freedom for the error sum of squares?</strong> A) 3 B) 19 C) 16 D) It depends on α. What are the degrees of freedom for the error sum of squares?

A) 3
B) 19
C) 16
D) It depends on α.
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64
Refer to the following partial ANOVA results from Excel (some information is missing). ANOVA Table <strong>Refer to the following partial ANOVA results from Excel (some information is missing). ANOVA Table   The number of observations in the original sample was:</strong> A) 59. B) 60. C) 58. The number of observations in the original sample was:

A) 59.
B) 60.
C) 58.
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65
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   The MS (mean square)for the treatments is:</strong> A) 239.13. B) 106.88. C) 1,130.8. D) impossible to ascertain from the information given. The MS (mean square)for the treatments is:

A) 239.13.
B) 106.88.
C) 1,130.8.
D) impossible to ascertain from the information given.
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66
To compare the cost of three shipping methods,a random sample of four shipments is taken for each of three firms.The cost per shipment is shown below. <strong>To compare the cost of three shipping methods,a random sample of four shipments is taken for each of three firms.The cost per shipment is shown below.   In a one-factor ANOVA,degrees of freedom for the between-groups sum of squares will be:</strong> A) 11. B) 3. C) 2. In a one-factor ANOVA,degrees of freedom for the between-groups sum of squares will be:

A) 11.
B) 3.
C) 2.
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67
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   Our decision about the hypothesis of equal treatment means is that the null hypothesis:</strong> A) cannot be rejected at α = .05. B) can be rejected at α = .05. C) can be rejected for any typical value of α. D) cannot be assessed from the given information. Our decision about the hypothesis of equal treatment means is that the null hypothesis:

A) cannot be rejected at α = .05.
B) can be rejected at α = .05.
C) can be rejected for any typical value of α.
D) cannot be assessed from the given information.
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68
Refer to the following partial ANOVA results from Excel (some information is missing). <strong>Refer to the following partial ANOVA results from Excel (some information is missing).   The F statistic is:</strong> A) 4.87. B) 3.38. C) 5.93. D) 6.91. The F statistic is:

A) 4.87.
B) 3.38.
C) 5.93.
D) 6.91.
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69
Systolic blood pressure of randomly selected HMO patients was recorded on a particular Wednesday,with the results shown here.An ANOVA test was performed using these data. <strong>Systolic blood pressure of randomly selected HMO patients was recorded on a particular Wednesday,with the results shown here.An ANOVA test was performed using these data.   Degrees of freedom for the between-treatments sum of squares would be:</strong> A) 3. B) 19. C) 17. D) depends on α. Degrees of freedom for the between-treatments sum of squares would be:

A) 3.
B) 19.
C) 17.
D) depends on α.
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70
To compare the cost of three shipping methods,a random sample of four shipments is taken for each of three firms.The cost per shipment is shown below. <strong>To compare the cost of three shipping methods,a random sample of four shipments is taken for each of three firms.The cost per shipment is shown below.   In a one-factor ANOVA,degrees of freedom for the within-groups sum of squares will be:</strong> A) 11. B) 3. C) 9. In a one-factor ANOVA,degrees of freedom for the within-groups sum of squares will be:

A) 11.
B) 3.
C) 9.
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71
Refer to the following partial ANOVA results from Excel (some information is missing). ANOVA Table <strong>Refer to the following partial ANOVA results from Excel (some information is missing). ANOVA Table   The F statistic is:</strong> A) 2.88. B) 4.87. C) 5.93. D) 6.91. The F statistic is:

A) 2.88.
B) 4.87.
C) 5.93.
D) 6.91.
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72
What is the .05 critical value of Tukey's test statistic for a one-factor ANOVA with n1 = 6,n2 = 6,n3 = 6? Note: This question requires access to a Tukey table.

A) 3.67
B) 2.60
C) 3.58
D) 2.75
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73
Refer to the following MegaStat output (some information is missing).The sample size was n = 65 in a one-factor ANOVA. <strong>Refer to the following MegaStat output (some information is missing).The sample size was n = 65 in a one-factor ANOVA.   At α = .05,which is the critical value of the test statistic for a two-tailed test for a significant difference in means that are to be compared simultaneously? Note: This question requires a Tukey table.</strong> A) 2.81 B) 2.54 C) 2.33 D) 1.96 At α = .05,which is the critical value of the test statistic for a two-tailed test for a significant difference in means that are to be compared simultaneously? Note: This question requires a Tukey table.

A) 2.81
B) 2.54
C) 2.33
D) 1.96
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74
Refer to the following MegaStat output (some information is missing).The sample size was n = 24 in a one-factor ANOVA. <strong>Refer to the following MegaStat output (some information is missing).The sample size was n = 24 in a one-factor ANOVA.   At α = .05,what is the critical value of the Tukey test statistic for a two-tailed test for a significant difference in means that are to be compared simultaneously? Note: This question requires access to a Tukey table.</strong> A) 2.07 B) 2.80 C) 2.76 D) 1.96 At α = .05,what is the critical value of the Tukey test statistic for a two-tailed test for a significant difference in means that are to be compared simultaneously? Note: This question requires access to a Tukey table.

A) 2.07
B) 2.80
C) 2.76
D) 1.96
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75
Refer to the following MegaStat output (some information is missing).The sample size was n = 65 in a one-factor ANOVA. <strong>Refer to the following MegaStat output (some information is missing).The sample size was n = 65 in a one-factor ANOVA.   Which pairs of days differ significantly? Note: This question requires access to a Tukey table.</strong> A) (Mon,Thu)and (Mon,Wed)only. B) (Mon,Wed)only. C) (Mon,Thu)only. D) (Mon,Thu)and (Mon,Wed)and (Mon,Fri)and (Mon,Tue). Which pairs of days differ significantly? Note: This question requires access to a Tukey table.

A) (Mon,Thu)and (Mon,Wed)only.
B) (Mon,Wed)only.
C) (Mon,Thu)only.
D) (Mon,Thu)and (Mon,Wed)and (Mon,Fri)and (Mon,Tue).
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76
What is the .05 critical value of Hartley's test statistic for a one-factor ANOVA with n1 = 5,n2 = 8,n3 = 7,n4 = 8,n5 = 6,n6 = 8? Note: This question requires access to a Hartley table.

A) 10.8
B) 11.8
C) 13.7
D) 15.0
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77
Sound levels are measured at random moments under typical driving conditions for various full-size truck models.The ANOVA results are shown below. <strong>Sound levels are measured at random moments under typical driving conditions for various full-size truck models.The ANOVA results are shown below.   The test statistic for Hartley's test for homogeneity of variance is:</strong> A) 2.25. B) 5.04. C) 4.61. D) 4.45. The test statistic for Hartley's test for homogeneity of variance is:

A) 2.25.
B) 5.04.
C) 4.61.
D) 4.45.
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78
Refer to the following MegaStat output (some information is missing).The sample size was n = 24 in a one-factor ANOVA. <strong>Refer to the following MegaStat output (some information is missing).The sample size was n = 24 in a one-factor ANOVA.   Which pairs of meds differ at α = .05? Note: This question requires access to a Tukey table.</strong> A) Med 1,Med 2 B) Med 2,Med 4 C) Med 3,Med 4 D) None of them. Which pairs of meds differ at α = .05? Note: This question requires access to a Tukey table.

A) Med 1,Med 2
B) Med 2,Med 4
C) Med 3,Med 4
D) None of them.
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79
Sound levels are measured at random moments under typical driving conditions for various full-size truck models.The Excel ANOVA results are shown below. <strong>Sound levels are measured at random moments under typical driving conditions for various full-size truck models.The Excel ANOVA results are shown below.   The test statistic to compare the five means simultaneously is:</strong> A) 2.96. B) 15.8. C) 5.56. D) 4.45. The test statistic to compare the five means simultaneously is:

A) 2.96.
B) 15.8.
C) 5.56.
D) 4.45.
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80
To compare the cost of three shipping methods,a random sample of four shipments is taken for each of three firms.The cost per shipment is shown below. <strong>To compare the cost of three shipping methods,a random sample of four shipments is taken for each of three firms.The cost per shipment is shown below.   Degrees of freedom for the total sum of squares in a one-factor ANOVA would be:</strong> A) 11. B) 8. C) 2. Degrees of freedom for the total sum of squares in a one-factor ANOVA would be:

A) 11.
B) 8.
C) 2.
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