Deck 49: The Inverse of a Square Matrix

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Question
Find the inverse of the matrix (if it exists). ​​ [1237]\left[ \begin{array} { l l } 1 & 2 \\3 & 7\end{array} \right]

A)​ [7231]\left[ \begin{array} { l l } 7 & 2 \\3 & 1\end{array} \right]
B)​ [7231]\left[ \begin{array} { c c } 7 & - 2 \\- 3 & 1\end{array} \right]
C)​ [7231]\left[ \begin{array} { l l } - 7 & - 2 \\- 3 & - 1\end{array} \right]
D)​ [7231]\left[ \begin{array} { c c } - 7 & - 2 \\3 & 1\end{array} \right]
E)​ [7231]\left[ \begin{array} { c c } - 7 & 2 \\3 & - 1\end{array} \right]
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Question
Use the inverse formula A1=1adbc[dbca]A ^ { - 1 } = \frac { 1 } { a d - b c } \left[ \begin{array} { c c } d & - b \\- c & a\end{array} \right] to find the inverse of the 2×2 matrix (if it exists). ​​ [2315]\left[ \begin{array} { l l } 2 & 3 \\1 & 5\end{array} \right]

A)​ 17[5312]\frac { 1 } { 7 } \left[ \begin{array} { l l } 5 & 3 \\1 & 2\end{array} \right]
B)​ 17[5312]\frac { 1 } { 7 } \left[ \begin{array} { c c } - 5 & - 3 \\1 & 2\end{array} \right]
C)​ 17[5312]\frac { 1 } { 7 } \left[ \begin{array} { c c } - 5 & 3 \\1 & - 2\end{array} \right]
D)​ 17[5312]\frac { 1 } { 7 } \left[ \begin{array} { c c } 5 & - 3 \\- 1 & 2\end{array} \right]
E)​ 17[5312]\frac { 1 } { 7 } \left[ \begin{array} { l l } - 5 & - 3 \\- 1 & - 2\end{array} \right]
Question
Solve the system of linear equations. ​​ {x2y=02x3y=8\left\{ \begin{array} { l } x - 2 y = 0 \\2 x - 3 y = 8\end{array} \right.

A)​ (16,8)( 16,8 )
B)​ (16,8)( 16 , - 8 )
C)​ (8,16)( - 8,16 )
D)​ (8,16)( 8,16 )
E)​ (16,8)( - 16,8 )
Question
Use the inverse formula A1=1adbc[dbca]A ^ { - 1 } = \frac { 1 } { a d - b c } \left[ \begin{array} { c c } d & - b \\- c & a\end{array} \right] to find the inverse of the 2×2 matrix (if it exists).​ [67513]\left[ \begin{array} { c c } 6 & 7 \\- 5 & 13\end{array} \right]

A)​ 1113[13756]\frac { 1 } { 113 } \left[ \begin{array} { c c } 13 & - 7 \\5 & 6\end{array} \right]
B)​ 1113[13756]\frac { 1 } { 113 } \left[ \begin{array} { c c } - 13 & 7 \\5 & - 6\end{array} \right]
C)​ 1113[13756]\frac { 1 } { 113 } \left[ \begin{array} { c c } - 13 & - 7 \\5 & 6\end{array} \right]
D)​ 1113[13756]\frac { 1 } { 113 } \left[ \begin{array} { c c } 13 & 7 \\5 & 6\end{array} \right]
E)​ 1113[13756]\frac { 1 } { 113 } \left[ \begin{array} { c c } - 13 & - 7 \\- 5 & - 6\end{array} \right]
Question
Use the inverse formula A1=1adbc[dbca]A ^ { - 1 } = \frac { 1 } { a d - b c } \left[ \begin{array} { c c } d & - b \\- c & a\end{array} \right] to find the inverse of the matrix (if it exists). ​​ [7979]\left[ \begin{array} { c c } - 7 & - 9 \\7 & 9\end{array} \right]

A)​ [9977]\left[ \begin{array} { c c } - 9 & - 9 \\7 & 7\end{array} \right]
B)​ [9977]\left[ \begin{array} { r r } - 9 & - 9 \\- 7 & - 7\end{array} \right]
C)​ [9977]\left[ \begin{array} { c c } - 9 & 9 \\7 & - 7\end{array} \right]
D) [9977]\left[ \begin{array} { c c } 9 & - 9 \\7 & 7\end{array} \right]
E)​Does not exist
Question
Use the inverse formula A1=1adbc[dbca]A ^ { - 1 } = \frac { 1 } { a d - b c } \left[ \begin{array} { c c } d & - b \\- c & a\end{array} \right] to find the inverse of the 2×2 matrix (if it exists). ​​ [1232]\left[ \begin{array} { c c } 1 & - 2 \\- 3 & 2\end{array} \right]

A)​ 14[2231]- \frac { 1 } { 4 } \left[ \begin{array} { c c } - 2 & - 2 \\3 & 1\end{array} \right]
B)​ 14[2231]- \frac { 1 } { 4 } \left[ \begin{array} { l l } - 2 & - 2 \\- 3 & - 1\end{array} \right]
C)​ 14[2231]- \frac { 1 } { 4 } \left[ \begin{array} { l l } 2 & 2 \\3 & 1\end{array} \right]
D)​ 14[2231]- \frac { 1 } { 4 } \left[ \begin{array} { c c } - 2 & 2 \\3 & - 1\end{array} \right]
E)​ 14[2231]- \frac { 1 } { 4 } \left[ \begin{array} { c c } 2 & - 2 \\3 & 1\end{array} \right]
Question
Find the inverse of the matrix (if it exists).​ [3004]\left[ \begin{array} { l l } 3 & 0 \\0 & 4\end{array} \right]

A)​ [140014]\left[ \begin{array} { l l } \frac { 1 } { 4 } & 0 \\0 & \frac { 1 } { 4 }\end{array} \right]
B)​ [14000]\left[ \begin{array} { l l } \frac { 1 } { 4 } & 0 \\0 & 0\end{array} \right]
C)​ [014140]\left[ \begin{array} { c c } 0 & \frac { 1 } { 4 } \\\frac { 1 } { 4 } & 0\end{array} \right]
D)​ [140013]\left[ \begin{array} { l l } \frac { 1 } { 4 } & 0 \\0 & \frac { 1 } { 3 }\end{array} \right]
E)​ [130014]\left[ \begin{array} { l l } \frac { 1 } { 3 } & 0 \\0 & \frac { 1 } { 4 }\end{array} \right]
Question
Find the inverse of the matrix (if it exists).​ [6778]\left[ \begin{array} { l l } 6 & - 7 \\7 & - 8\end{array} \right]

A)​ [8776]\left[ \begin{array} { c c } - 8 & 7 \\7 & 6\end{array} \right]
B)​ [8776]\left[ \begin{array} { c c } - 8 & 7 \\- 7 & 6\end{array} \right]
C)​ [8776]\left[ \begin{array} { c c } - 8 & - 7 \\- 7 & 6\end{array} \right]
D)​ [8776]\left[ \begin{array} { c c } - 8 & 7 \\7 & - 6\end{array} \right]
E)​ [8776]\left[ \begin{array} { c c } - 8 & - 7 \\7 & 6\end{array} \right]
Question
Use the inverse formula A1=1adbc[dbca]A ^ { - 1 } = \frac { 1 } { a d - b c } \left[ \begin{array} { c c } d & - b \\- c & a\end{array} \right] to find the inverse of the 2×2 matrix (if it exists). ​​ [12352]\left[ \begin{array} { c c } - 12 & 3 \\5 & 2\end{array} \right]

A)​ 139[23512]- \frac { 1 } { 39 } \left[ \begin{array} { c c } 2 & - 3 \\- 5 & - 12\end{array} \right]
B)​ 139[23512]- \frac { 1 } { 39 } \left[ \begin{array} { c c } - 2 & - 3 \\5 & 12\end{array} \right]
C)​ 139[23512]- \frac { 1 } { 39 } \left[ \begin{array} { c c } - 2 & 3 \\5 & - 12\end{array} \right]
D)​ 139[23512]- \frac { 1 } { 39 } \left[ \begin{array} { c c } 2 & - 3 \\5 & 12\end{array} \right]
E)​ 139[23512]- \frac { 1 } { 39 } \left[ \begin{array} { l l } - 2 & - 3 \\- 5 & - 12\end{array} \right]
Question
Find the inverse of the matrix (if it exists).​ [4131]\left[ \begin{array} { c c } 4 & - 1 \\- 3 & 1\end{array} \right]

A)​ [1134]\left[ \begin{array} { l l } 1 & 1 \\3 & 4\end{array} \right]
B)​ [1134]\left[ \begin{array} { c c } 1 & 1 \\- 3 & 4\end{array} \right]
C)​ [1134]\left[ \begin{array} { c c } - 1 & 1 \\3 & 4\end{array} \right]
D)​ [1134]\left[ \begin{array} { c c } 1 & 1 \\3 & - 4\end{array} \right]
E)Does not exist
Question
Use an inverse matrix to solve (if possible)the system of linear equations.​ {3x+4y=25x+3y=4\left\{ \begin{array} { l } 3 x + 4 y = - 2 \\5 x + 3 y = 4\end{array} \right.

A)​ (2,2)( - 2,2 )
B)​ (2,2)( 2,2 )
C)​ (2,2)( - 2 , - 2 )
D)​ (2,2)( 2 , - 2 )
E)​ (1,2)( - 1,2 )
Question
Find the inverse of the matrix (if it exists).​ [40060051111]\left[ \begin{array} { c c c } 4 & 0 & 0 \\6 & 0 & 0 \\5 & 11 & 11\end{array} \right]

A)​ [4006005411]\left[ \begin{array} { c c c } - 4 & 0 & 0 \\- 6 & 0 & 0 \\5 & 4 & 11\end{array} \right]
B)​ [4006005411]\left[ \begin{array} { c c c } - 4 & 0 & 0 \\- 6 & 0 & 0 \\- 5 & - 4 & - 11\end{array} \right]
C)​ [4006005411]\left[ \begin{array} { c c c } 4 & 0 & 0 \\6 & 0 & 0 \\5 & 4 & 11\end{array} \right]
D)​ [4006005411]\left[ \begin{array} { c c c } - 4 & 0 & 0 \\- 6 & 0 & 0 \\- 5 & 4 & 11\end{array} \right]
E)Does not exist
Question
Solve the system of linear equations.​ {x+y+z=73x+5y+4z=83x+6y+5z=0\left\{ \begin{array} { c } x + y + z = - 7 \\3 x + 5 y + 4 z = 8 \\3 x + 6 y + 5 z = 0\end{array} \right.

A)​ (2,37,45)( 2,37 , - 45 )
B)​ (1,37,45)( - 1,37 , - 45 )
C)​ (1,37,45)( - 1 , - 37 , - 45 )
D)​ (1,37,45)( 1,37 , - 45 )
E)​ (1,38,45)( 1,38 , - 45 )
Question
Solve the system of linear equations.​ {x2y=62x3y=4\left\{ \begin{array} { c } x - 2 y = 6 \\2 x - 3 y = 4\end{array} \right. ​ ​

A)​ (10,8)( - 10 , - 8 )
B)​ (10,8)( - 10,8 )
C)​ (10,4)( - 10,4 )
D)​ (4,10)( - 4 , - 10 )
E)​ (10,8)( 10,8 )
Question
Find the inverse of the matrix (if it exists).​ [733419]\left[ \begin{array} { c c } - 7 & 33 \\4 & - 19\end{array} \right]

A)​ [193347]\left[ \begin{array} { c c } - 19 & - 33 \\4 & - 7\end{array} \right]
B)​ [193347]\left[ \begin{array} { c c } - 19 & - 33 \\- 4 & - 7\end{array} \right]
C)​ [193347]\left[ \begin{array} { c c } 19 & - 33 \\- 4 & - 7\end{array} \right]
D)​ [193347]\left[ \begin{array} { c c } 19 & - 33 \\4 & - 7\end{array} \right]
E)​ [193347]\left[ \begin{array} { c c } 19 & - 33 \\4 & 7\end{array} \right]
Question
Solve the system of linear equations.​ {x2y=52x3y=10\left\{ \begin{array} { l l } x - 2 y & = 5 \\2 x - 3 y & = 10\end{array} \right.

A)​ (5,10)( 5,10 )
B)​ (5,5)( 5,5 )
C)​ (10,5)( 10,5 )
D)​ (5,0)( 5,0 )
E)​ (0,5)( 0,5 )
Question
Solve the system of linear equations.​ {x2y=32x3y=4\left\{ \begin{array} { l } x - 2 y = 3 \\2 x - 3 y = - 4\end{array} \right.

A)​ (17,4)( - 17,4 )
B)​ (17,10)( - 17,10 )
C)​ (4,17)( - 4 , - 17 )
D)​ (17,10)( 17,10 )
E)​ (17,10)( - 17 , - 10 )
Question
Find the inverse of the matrix (if it exists).​ [500200157]\left[ \begin{array} { c c c } - 5 & 0 & 0 \\2 & 0 & 0 \\1 & 5 & 7\end{array} \right]

A)​ [500200157]\left[ \begin{array} { l l l } 5 & 0 & 0 \\2 & 0 & 0 \\1 & 5 & 7\end{array} \right]
B)​ [500200157]\left[ \begin{array} { c c c } - 5 & 0 & 0 \\- 2 & 0 & 0 \\1 & 5 & 7\end{array} \right]
C) [500200157]\left[ \begin{array} { c c c } - 5 & 0 & 0 \\- 2 & 0 & 0 \\- 1 & - 5 & - 7\end{array} \right]
D)​ [500200157]\left[ \begin{array} { l l l } - 5 & 0 & 0 \\- 2 & 0 & 0 \\- 1 & 5 & 7\end{array} \right]
E)​Does not exist
Question
Solve the system of linear equations.​ {x+y+z=03x+5y+4z=93x+6y+5z=6\left\{ \begin{array} { l } x + y + z = 0 \\3 x + 5 y + 4 z = 9 \\3 x + 6 y + 5 z = 6\end{array} \right.

A)​ (3,12,15)( 3,12 , - 15 )
B)​ (3,12,15)( 3,12,15 )
C)​ (3,12,15)( - 3 , - 12 , - 15 )
D)​ (3,12,15)( 3 , - 12 , - 15 )
E)​ (3,12,15)( - 3,12 , - 15 )
Question
​Use an inverse matrix to solve (if possible)the system of linear equations.​ {18x+12y=1430x+24y=24\left\{ \begin{array} { l } 18 x + 12 y = 14 \\30 x + 24 y = 24\end{array} \right.

A)​( 56\frac { 5 } { 6 } , 16\frac { 1 } { 6 } )
B)​( 4, 16\frac { 1 } { 6 } )
C)​( 23\frac { 2 } { 3 } , 16\frac { 1 } { 6 } )
D)​( 23\frac { 2 } { 3 } , 14\frac { 1 } { 4 } )
E)​( 23\frac { 2 } { 3 } ,3 )
Question
The table shows the enrollment projections (in millions)for public universities in the United States for the years 2010 through 2012.
Year
Enrollment projections
2010
13)83
2011
14)07
2012
14)23
The data can be modeled by the quadratic function y=at2+bt+cy=a t^{2}+b t+c .Create a system of linear equations for the data.Let t represent the year,with t = 10 corresponding to 2010.

A) {100a+10b+c=13.83121a11b+c=14.07144a+12b+c=14.23\left\{ \begin{array} { l } 100 a + 10 b + c = 13.83 \\121 a - 11 b + c = 14.07 \\144 a + 12 b + c = 14.23\end{array} \right.
B)​ {100a10b+c=13.83121a+11b+c=14.07144a+12b+c=14.23\left\{ \begin{array} { l } 100 a - 10 b + c = 13.83 \\121 a + 11 b + c = 14.07 \\144 a + 12 b + c = 14.23\end{array} \right.
C)​ {100a+10b+c=13.83121a+11b+c=14.07144a+12b+c=14.23\left\{ \begin{array} { l } 100 a + 10 b + c = 13.83 \\121 a + 11 b + c = 14.07 \\144 a + 12 b + c = 14.23\end{array} \right.
D)​ {100a+10b+c=13.83121a+11b+c=14.07144a+12bc=14.23\left\{ \begin{array} { l } 100 a + 10 b + c = 13.83 \\121 a + 11 b + c = 14.07 \\144 a + 12 b - c = 14.23\end{array} \right.
E)​ {100a10bc=13.83121a11bc=14.07144a12bc=14.23\left\{ \begin{array} { l } 100 a - 10 b - c = 13.83 \\121 a - 11 b - c = 14.07 \\144 a - 12 b - c = 14.23\end{array} \right.
Question
Consider a person who invests in AAA-rated bonds,A-rated bonds,and B-rated bonds.The average yields are 6.5% on AAA bonds,7% on A bonds,and 9% on B bonds.The person invests twice as much in B bonds as in A bonds.Let x,y and z represent the amounts invested in AAA,A,and B bonds,respectively. Total Investment
Annual Return
$12,000
890 {x+y+z=12,000 (total investment) 0.065x+0.07y+0.09z=890 (annual retum) 2yz=0\left\{ \begin{array} { c l } x + y + z & = 12,000 \text { (total investment) } \\0.065 x + 0.07 y + 0.09 z & = 890 \text { (annual retum) } \\2 y - z & = 0\end{array} \right. Use the inverse of the coefficient matrix of this system to find the amount invested in each type of bond.

A)$7,000 in AAA-rated bonds $2,000 in A-rated bonds
$4,000 in B-rated bonds
B)$5,000 in AAA-rated bonds $7,000 in A-rated bonds
$3,000 in B-rated bonds
C)$5,000 in AAA-rated bonds $6,000 in A-rated bonds
$4,000 in B-rated bonds
D)$3,000 in AAA-rated bonds $2,000 in A-rated bonds
$6,000 in B-rated bonds
E)$6,000 in AAA-rated bonds $2,000 in A-rated bonds
$4,000 in B-rated bonds
Question
Find the inverse of the matrix [24610]\left[ \begin{array} { c c } 2 & 4 \\- 6 & - 10\end{array} \right] .

A)​ 113[24610]\frac { 1 } { 13 } \left[ \begin{array} { l l } - 2 & - 4 \\- 6 & 10\end{array} \right]
B)​ [24106]\left[ \begin{array} { c c } - 2 & - 4 \\10 & 6\end{array} \right]
C)​ [26814]\left[ \begin{array} { c c } 2 & - 6 \\8 & - 14\end{array} \right]
D)​ 17[24610]\frac { 1 } { 7 } \left[ \begin{array} { c c } 2 & 4 \\- 6 & - 10\end{array} \right]
E)​ 12[5231]\frac { 1 } { 2 } \left[ \begin{array} { c c } - 5 & - 2 \\3 & 1\end{array} \right]
Question
Find the inverse of the matrix [1432]\left[ \begin{array} { c c } - 1 & 4 \\3 & - 2\end{array} \right] (if it exists).

A)​ 110[2431]- \frac { 1 } { - 10 } \left[ \begin{array} { l l } - 2 & - 4 \\- 3 & - 1\end{array} \right]
B) 110[1432]- \frac { 1 } { - 10 } \left[ \begin{array} { c c } - 1 & 4 \\3 & - 2\end{array} \right]
C)​ 110[2431]\frac { 1 } { - 10 } \left[ \begin{array} { l l } - 2 & - 4 \\- 3 & - 1\end{array} \right]
D)​ 110[2431]\frac { 1 } { - 10 } \left[ \begin{array} { l l } 2 & 4 \\3 & 1\end{array} \right]
E)​does not exist
Question
A small home business creates muffins,bones,and cookies for dogs.In addition to other ingredients,each muffin requires 2 units of beef,3 units of chicken,and 2 units of liver.Each bone requires 1 unit of beef,1 unit of chicken,and 1 unit of liver.Each cookie requires 2 units of beef,1 unit of chicken,and 1.5 units of liver.Find the numbers of muffins,bones,and cookies that the company can create with the given amounts of ingredients. ​
875 units of beef
830 units of chicken
850 units of liver

A)765 muffins,5 bones,50 cookies
B)50 muffins,765 bones,50 cookies
C)5 muffins,765 bones,50 cookies
D)50 muffins,765 bones,5 cookies
E)5 muffins,5 bones,830 cookies
Question
A florist is creating 10 centerpieces for the tables at a wedding reception.Roses cost $2.50 each,lilies cost $8 each,and irises cost $4 each.The customer has a budget of $300 allocated for the centerpieces and wants each centerpiece to contain 12 flowers,with twice as many roses as the number of irises and lilies combined. ​
Write a system of linear equations that represents the situation.

A) {2.5r8l4i=300r2l2i=0rli=120\left\{ \begin{array} { l l } 2.5 r - 8 l - 4 i & = 300 \\- r - 2 l - 2 i & = 0 \\r - l - i & = 120\end{array} \right.
B)​ {2.5r+8l+4i=300r+2l+2i=0r+l+i=120\left\{ \begin{array} { l l } 2.5 r + 8 l + 4 i & = 300 \\r + 2 l + 2 i & = 0 \\r + l + i & = 120\end{array} \right.
C)​ {2.5r+8l+4i=300r+2l+2i=0r+l+i=120\left\{ \begin{array} { l l } 2.5 r + 8 l + 4 i & = 300 \\- r + 2 l + 2 i & = 0 \\r + l + i & = 120\end{array} \right.
D)​ {2.5r8l+4i=300r+2l+2i=0r+l+i=120\left\{ \begin{array} { l l } 2.5 r - 8 l + 4 i & = 300 \\- r + 2 l + 2 i & = 0 \\r + l + i & = 120\end{array} \right.
E)​ {2.5r+8l4i=300r+2l+2i=0r+l+i=120\left\{ \begin{array} { l l } 2.5 r + 8 l - 4 i & = 300 \\- r + 2 l + 2 i & = 0 \\r + l + i & = 120\end{array} \right.
Question
​Solve the system of linear equations {2x+3y=154x3y=10\left\{ \begin{array} { l } 2 x + 3 y = - 15 \\4 x - 3 y = 10\end{array} \right. using the inverse matrix [16162919]\left[ \begin{array} { c c } \frac { 1 } { 6 } & \frac { 1 } { 6 } \\\\\frac { 2 } { 9 } & - \frac { 1 } { 9 }\end{array} \right]

A)​ [xy]=[5652]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { l } \frac { 5 } { 6 } \\\\\frac { 5 } { 2 }\end{array} \right]
B)​ [xy]=[56409]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { c } - \frac { 5 } { 6 } \\\\- \frac { 40 } { 9 }\end{array} \right]
C)​ [xy]=[251852]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { c } \frac { 25 } { 18 } \\\\\frac { 5 } { 2 }\end{array} \right]
D)​ [xy]=[520]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { l } \frac { 5 } { 2 } \\0\end{array} \right]
E)​ [xy]=[5356]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { c } - \frac { 5 } { 3 } \\\\\frac { 5 } { 6 }\end{array} \right]
Question
Use an inverse matrix to solve (if possible)the system of linear equations.​ {0.2x0.6y=14.4x+1.4y=20.8\left\{ \begin{array} { l } 0.2 x - 0.6 y = 14.4 \\- x + 1.4 y = - 20.8\end{array} \right.

A)(-24,-31)
B)(-23,-32)
C)(-22,-32)
D)(-24,-32)
E)(-23,-30)
Question
​Use an inverse matrix to solve (if possible)the system of linear equations.​ {1.8x5y=428.8x16y=5\left\{ \begin{array} { l l } 1.8 x - 5 y & = 4 \\28.8 x - 16 y & = 5\end{array} \right.

A)​( 116\frac { 1 } { 16 } ,16)
B)​(0,0)
C)​( 116\frac { 1 } { 16 } , 516\frac { 5 } { 16 } )
D)​(16,16)
E)​No solution
Question
A coffee manufacturer sells a 14-pound package that contains three flavors of coffee for $25.French vanilla coffee costs $5 per pound,hazelnut flavored coffee costs $5.50 per pound,and Swiss chocolate flavored coffee costs $6 per pound.The package contains the same amount of hazelnut as Swiss chocolate.Let f represent the number of pounds of French vanilla,h represent the number of pounds of hazelnut,and s represent the number of pounds of Swiss chocolate. ​
Write a system of linear equations that represents the situation.

A) {5f5.5h+6s=25f+h+s=14hs=0\left\{ \begin{array} { c l } 5 f - 5.5 h + 6 s & = 25 \\f + h + s & = 14 \\h - s & = 0\end{array} \right.
B)​ {5f+5.5h+6s=25f+h+s=14hs=0\left\{ \begin{aligned}5 f + 5.5 h + 6 s & = 25 \\f + h + s & = 14 \\h - s & = 0\end{aligned} \right.
C)​ {5f5.5h+6s=25fh+s=14hs=0\left\{ \begin{array} { c l } 5 f - 5.5 h + 6 s & = 25 \\f - h + s & = 14 \\h - s & = 0\end{array} \right.
D)​ {5f5.5h+6s=25f+h+s=14h+s=0\left\{ \begin{array} { c l } 5 f - 5.5 h + 6 s & = 25 \\f + h + s & = 14 \\h + s & = 0\end{array} \right.
E)​ {5f5.5h6s=25fhs=14h+s=0\left\{ \begin{array} { c l } 5 f - 5.5 h - 6 s & = 25 \\f - h - s & = 14 \\h + s & = 0\end{array} \right.
Question
Find the inverse of the matrix [1622811]\left[ \begin{array} { c c } - 16 & 22 \\- 8 & 11\end{array} \right] (if it exists).

A)does not exist
B)​ 116- \frac { 1 } { 16 } [1122816]\left[ \begin{array} { c c } 11 & - 22 \\8 & - 16\end{array} \right]
C)​ 111\frac { 1 } { 11 } [1622811]\left[ \begin{array} { c c } - 16 & 22 \\- 8 & 11\end{array} \right]
D)​ 122- \frac { 1 } { 22 } [1122816]\left[ \begin{array} { c c } - 11 & 22 \\- 8 & 16\end{array} \right]
E)​ 18\frac { 1 } { 8 } [1122816]\left[ \begin{array} { c c } 11 & - 22 \\8 & - 16\end{array} \right]
Question
Consider a person who invests in AAA-rated bonds,A-rated bonds,and B-rated bonds.The average yields are 6.5% on AAA bonds,7% on A bonds,and 9% on B bonds.The person invests twice as much in B bonds as in A bonds.Let x,y and z represent the amounts invested in AAA,A,and B bonds,respectively. Total Investment
Annual Return
$32,000
2465 {x+y+z=32,000 (total investment) 0.065x+0.07y+0.09z=2465 (annual retur) 2yz=0\left\{ \begin{array} { c l } x + y + z & = 32,000 \text { (total investment) } \\0.065 x + 0.07 y + 0.09 z & = 2465 \text { (annual retur) } \\2 y - z & = 0\end{array} \right. Use the inverse of the coefficient matrix of this system to find the amount invested in each type of bond.

A)$11,000 in AAA-rated bonds $7,000 in A-rated bonds
$14,000 in B-rated bonds
B)$11,000 in AAA-rated bonds $14,000 in A-rated bonds
$7,000 in B-rated bonds
C)$14,000 in AAA-rated bonds $11,000 in A-rated bonds
$7,000 in B-rated bonds
D)$14,000 in AAA-rated bonds $7,000 in A-rated bonds
$11,000 in B-rated bonds
E)$7,000 in AAA-rated bonds $11,000 in A-rated bonds
$14,000 in B-rated bonds
Question
A small home business creates muffins,bones,and cookies for dogs.In addition to other ingredients,each muffin requires 2 units of beef,3 units of chicken,and 2 units of liver.Each bone requires 1 unit of beef,1 unit of chicken,and 1 unit of liver.Each cookie requires 2 units of beef,1 unit of chicken,and 1.5 units of liver.Find the numbers of muffins,bones,and cookies that the company can create with the given amounts of ingredients. ​
900 units of beef
700 units of chicken
800 units of liver

A)200 muffins,500 bones,200 cookies
B)200 muffins,500 bones,0 cookies
C)0 muffins,0 bones,700 cookies
D)500 muffins,0 bones,200 cookies
E)0 muffins,500 bones,200 cookies
Question
​Solve the system of linear equations {3x+6y=16x+8y=2\left\{ \begin{array} { l } 3 x + 6 y = 1 \\6 x + 8 y = 2\end{array} \right. using the inverse matrix [23121214]\left[ \begin{array} { c c } - \frac { 2 } { 3 } & \frac { 1 } { 2 } \\\frac { 1 } { 2 } & - \frac { 1 } { 4 }\end{array} \right]

A)​ [xy]=[11120]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { c } \frac { 11 } { 12 } \\0\end{array} \right]
B)​ [xy]=[130]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { l } \frac { 1 } { 3 } \\0\end{array} \right]
C)​ [xy]=[111213]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { c } \frac { 11 } { 12 } \\\\\frac { 1 } { 3 }\end{array} \right]
D)​ [xy]=[1312]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { c } \frac { 1 } { 3 } \\- \frac { 1 } { 2 }\end{array} \right]
E)​ [xy]=[1213]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { c } - \frac { 1 } { 2 } \\\frac { 1 } { 3 }\end{array} \right]
Question
Consider a person who invests in AAA-rated bonds,A-rated bonds,and B-rated bonds.The average yields are 6.5% on AAA bonds,7% on A bonds,and 9% on B bonds.The person invests twice as much in B bonds as in A bonds.Let x,y and z represent the amounts invested in AAA,A,and B bonds,respectively.  Total Investment  Annual Return $12,000890\begin{array} { | c | c | } \hline \text { Total Investment } & \text { Annual Return } \\\hline \$ 12,000 & 890 \\\hline\end{array} {x+y+z=663,000 (total investment) 0.065x+0.07y+0.09z=47,000 (annual retum) 2yz=0\left\{ \begin{array} { c l } x + y + z & = 663,000 \text { (total investment) } \\0.065 x + 0.07 y + 0.09 z & = 47,000 \text { (annual retum) } \\2 y - z & = 0\end{array} \right. Use the inverse of the coefficient matrix of this system to find the amount invested in each type of bond.

A)$142,000 in AAA-rated bonds $451,000 in A-rated bonds
$71,000 in B-rated bonds
B)$450,000 in AAA-rated bonds $71,000 in A-rated bonds
$142,000 in B-rated bonds
C)$143,000 in AAA-rated bonds $71,000 in A-rated bonds
$450,000 in B-rated bonds
D)$72,000 in AAA-rated bonds $450,000 in A-rated bonds
$142,000 in B-rated bonds
E)$450,000 in AAA-rated bonds $142,000 in A-rated bonds
$70,000 in B-rated bonds
Question
Use the matrix capabilities of a graphing utility to find the inverse of the matrix 19[453483120]\frac { 1 } { 9 } \left[ \begin{array} { c c c } - 4 & - 5 & 3 \\- 4 & - 8 & 3 \\1 & 2 & 0\end{array} \right] (if it exists).

A)​ [9126030039]\left[ \begin{array} { c c c } - 9 & 12 & 6 \\0 & - 3 & 0 \\0 & 3 & - 9\end{array} \right]
B)​ [6693300312]\left[ \begin{array} { c c c } - 6 & 6 & 9 \\3 & - 3 & 0 \\0 & 3 & 12\end{array} \right]
C)​ [609030036]\left[ \begin{array} { c c c } - 6 & 0 & 9 \\0 & - 3 & 0 \\0 & 3 & - 6\end{array} \right]
D) [3390300612]\left[ \begin{array} { c c c } 3 & 3 & 9 \\0 & - 3 & 0 \\0 & 6 & 12\end{array} \right]
E)​does not exist ​
Question
A small home business creates muffins,bones,and cookies for dogs.In addition to other ingredients,each muffin requires 2 units of beef,3 units of chicken,and 2 units of liver.Each bone requires 1 unit of beef,1 unit of chicken,and 1 unit of liver.Each cookie requires 2 units of beef,1 unit of chicken,and 1.5 units of liver.Find the numbers of muffins,bones,and cookies that the company can create with the given amounts of ingredients. ​
3,000 units of beef
2,950 units of chicken
2,900 units of liver

A)200 muffins,2,300 bones,200 cookies
B)150 muffins,150 bones,2,950 cookies
C)200 muffins,2,300 bones,150 cookies
D)2,300 muffins,150 bones,200 cookies
E)150 muffins,2,300 bones,200 cookies
Question
Find the inverse of the matrix [777213528214235]\left[ \begin{array} { c c c } 7 & 7 & 7 \\21 & 35 & 28 \\21 & 42 & 35\end{array} \right] . ​

A)​ 17[111321332]\frac { 1 } { 7 } \left[ \begin{array} { c c c } 1 & 1 & - 1 \\- 3 & 2 & - 1 \\3 & - 3 & 2\end{array} \right]
B)​ 17[111021332]\frac { 1 } { 7 } \left[ \begin{array} { c c c } 1 & 1 & 1 \\0 & - 2 & - 1 \\3 & - 3 & 2\end{array} \right]
C)​ 7[310311132]- 7 \left[ \begin{array} { c c c } 3 & 1 & 0 \\- 3 & 1 & - 1 \\1 & - 3 & 2\end{array} \right]
D)​ 17[101321233]- \frac { 1 } { 7 } \left[ \begin{array} { c c c } 1 & 0 & - 1 \\- 3 & 2 & - 1 \\2 & - 3 & 3\end{array} \right]
E)​ 7[111301332]7 \left[ \begin{array} { c c c } 1 & 1 & 1 \\- 3 & 0 & - 1 \\3 & - 3 & 2\end{array} \right]
Question
Find the inverse of the following matrix.​ [cosθsinθsinθcosθ]\left[ \begin{array} { c c } \cos \theta & \sin \theta \\- \sin \theta & \cos \theta\end{array} \right]

A)​ [cosθsinθsinθcosθ]\left[ \begin{array} { c c } \cos \theta & - \sin \theta \\\sin \theta & \cos \theta\end{array} \right]
B)​ [cosθsinθsinθcosθ]\left[ \begin{array} { c c } - \cos \theta & - \sin \theta \\\sin \theta & \cos \theta\end{array} \right]
C)​ [cosθsinθsinθcosθ]\left[ \begin{array} { c c } \cos \theta & \sin \theta \\- \sin \theta & \cos \theta\end{array} \right]
D)​ [cosθsinθsinθcosθ]\left[ \begin{array} { c c } \cos \theta & \sin \theta \\- \sin \theta & - \cos \theta\end{array} \right]
E)​ [cosθsinθsinθcosθ]\left[ \begin{array} { l l } \cos \theta & - \sin \theta \\\sin \theta & - \cos \theta\end{array} \right]
Question
A small home business creates muffins,bones,and cookies for dogs.In addition to other ingredients,each muffin requires 2 units of beef,3 units of chicken,and 2 units of liver.Each bone requires 1 unit of beef,1 unit of chicken,and 1 unit of liver.Each cookie requires 2 units of beef,1 unit of chicken,and 1.5 units of liver.Find the numbers of muffins,bones,and cookies that the company can create with the given amounts of ingredients. ​
800 units of beef
750 units of chicken
725 units of liver

A)150 muffins,300 bones,150 cookies
B)150 muffins,300 bones,100 cookies
C)300 muffins,100 bones,150 cookies
D)100 muffins,300 bones,150 cookies
E)100 muffins,100 bones,750 cookies
Question
​Solve the system of linear equations {6x+18y+6z=112x+30y=218x+6y12z=1\left\{ \begin{array} { l l } - 6 x + 18 y + 6 z & = 1 \\12 x + 30 y & = 2 \\18 x + 6 y - 12 z & = - 1\end{array} \right. using an inverse matrix. ​

A)​ [xyz]=[161213]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 1 } { 6 } \\\\\frac { - 1 } { 2 } \\\\\frac { 1 } { 3 }\end{array} \right]
B)​ [xyz]=[161213]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 1 } { 6 } \\\\\frac { - 1 } { 2 } \\\\\frac { - 1 } { 3 }\end{array} \right]
C)​ [xyz]=[16012]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 1 } { 6 } \\0 \\\frac { 1 } { 2 }\end{array} \right]
D)​ [xyz]=[01316]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } 0 \\\frac { 1 } { 3 } \\\frac { - 1 } { 6 }\end{array} \right]
E)​ [xyz]=[16013]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { l } \frac { 1 } { 6 } \\0 \\\frac { 1 } { 3 }\end{array} \right]
Question
​Solve the system of linear equations​ {7x+7y+7z=021x+35y+28z=621x+42y+35z=1\left\{ \begin{array} { l l } 7 x + 7 y + 7 z & = 0 \\21 x + 35 y + 28 z & = 6 \\21 x + 42 y + 35 z & = 1\end{array} \right. ​using the inverse matrix 17[111321332]\frac { 1 } { 7 } \left[ \begin{array} { c c c } 1 & 1 & - 1 \\- 3 & 2 & - 1 \\3 & - 3 & 2\end{array} \right] .

A)​ [xyz]=[57117127]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 5 } { 7 } \\\\\frac { 11 } { 7 } \\\\\frac { - 12 } { 7 }\end{array} \right]
B)​ [xyz]=[57117167]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 5 } { 7 } \\\\\frac { 11 } { 7 } \\\\\frac { - 16 } { 7 }\end{array} \right]
C)​ [xyz]=[16757117]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 16 } { 7 } \\\\\frac { 5 } { 7 } \\\\\frac { 11 } { 7 }\end{array} \right]
D)​ [xyz]=[12711757]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 12 } { 7 } \\\\\frac { 11 } { 7 } \\\\\frac { - 5 } { 7 }\end{array} \right]
E)​ [xyz]=[57167117]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 5 } { 7 } \\\\\frac { - 16 } { 7 } \\\\\frac { 11 } { 7 }\end{array} \right]
Question
Find the inverse of A.​ A=[2341]A = \left[ \begin{array} { c c } 2 & 3 \\- 4 & 1\end{array} \right]

A)​ A1=[17372717]A ^ { - 1 } = \left[ \begin{array} { c c } \frac { 1 } { 7 } & - \frac { 3 } { 7 } \\\\\frac { 2 } { 7 } & \frac { 1 } { 7 }\end{array} \right]
B)​ A1=[1143142717]A ^ { - 1 } = \left[ \begin{array} { c c } \frac { 1 } { 14 } & - \frac { 3 } { 14 } \\\\\frac { 2 } { 7 } & \frac { 1 } { 7 }\end{array} \right]
C)​ A1=[1143727114]A ^ { - 1 } = \left[ \begin{array} { c c } \frac { 1 } { 14 } & - \frac { 3 } { 7 } \\\\\frac { 2 } { 7 } & \frac { 1 } { 14 }\end{array} \right]
D)​ A1=[1143142717]A ^ { - 1 } = \left[ \begin{array} { c c } \frac { 1 } { 14 } & \frac { 3 } { 14 } \\\frac { 2 } { 7 } & \frac { 1 } { 7 }\end{array} \right]
E)​ A1=[1737214114]A ^ { - 1 } = \left[ \begin{array} { c c } \frac { 1 } { 7 } & - \frac { 3 } { 7 } \\\frac { 2 } { 14 } & \frac { 1 } { 14 }\end{array} \right]
Question
Find the inverse of the matrix.​ [105115511]\left[ \begin{array} { c c c } 1 & 0 & 5 \\1 & 1 & 5 \\- 5 & 1 & 1\end{array} \right]

A)​​ [2955110611]\left[ \begin{array} { c c c } - 29 & 5 & - 5 \\- 1 & 1 & 0 \\6 & 1 & 1\end{array} \right]
B) [4526526110626126126]\left[ \begin{array} { c c c } 4 & \frac { 5 } { 26 } & - \frac { 5 } { 26 } \\1 & 1 & 0 \\\frac { 6 } { 26 } & - \frac { 1 } { 26 } & \frac { 1 } { 26 }\end{array} \right]
C)​ [426526526110626126126]\left[ \begin{array} { c c c } - \frac { 4 } { 26 } & \frac { 5 } { 26 } & - \frac { 5 } { 26 } \\- 1 & 1 & 0 \\\frac { 6 } { 26 } & - \frac { 1 } { 26 } & \frac { 1 } { 26 }\end{array} \right]
D)​ [2955111611]\left[ \begin{array} { c c c } 29 & 5 & - 5 \\- 1 & 1 & - 1 \\6 & - 1 & 1\end{array} \right]
E)​ [2955111611]\left[ \begin{array} { c c c } 29 & 5 & - 5 \\- 1 & 1 & 1 \\6 & - 1 & 1\end{array} \right]
Question
Find the inverse of the matrix [81447]\left[ \begin{array} { c c } - 8 & 14 \\- 4 & 7\end{array} \right] (if it exists).

A)​ 14[71448]\frac { 1 } { 4 } \left[ \begin{array} { l l } 7 & - 14 \\4 & - 8\end{array} \right]
B)​ 18[71448]- \frac { 1 } { 8 } \left[ \begin{array} { c c } 7 & - 14 \\4 & - 8\end{array} \right]
C)​ 14[71448]- \frac { 1 } { 4 } \left[ \begin{array} { c c } - 7 & - 14 \\4 & 8\end{array} \right]
D)​ 17[81447]\frac { 1 } { 7 } \left[ \begin{array} { c c } - 8 & 14 \\- 4 & 7\end{array} \right]
E)does not exist
Question
Use a graphing calculator to find the inverse of the matrix.​ [1483014800140001]\left[ \begin{array} { l l l l } 1 & 4 & 8 & 3 \\0 & 1 & 4 & 8 \\0 & 0 & 1 & 4 \\0 & 0 & 0 & 1\end{array} \right] ​ ​

A)​ [1483014800140001]\left[ \begin{array} { c c c c } 1 & 4 & 8 & - 3 \\0 & 1 & - 4 & 8 \\0 & 0 & 1 & 4 \\0 & 0 & 0 & 1\end{array} \right]
B)​ [1483014800140001]\left[ \begin{array} { c c c c } 1 & - 4 & 8 & 3 \\0 & 1 & - 4 & 8 \\0 & 0 & 1 & - 4 \\0 & 0 & 0 & 1\end{array} \right]
C)​ [1483014800140001]\left[ \begin{array} { c c c c } 1 & - 4 & - 8 & - 3 \\0 & 1 & - 4 & - 8 \\0 & 0 & 1 & - 4 \\0 & 0 & 0 & 1\end{array} \right]
D)​ [1483014800140001]\left[ \begin{array} { c c c c } 1 & - 4 & 8 & - 3 \\0 & 1 & - 4 & 8 \\0 & 0 & 1 & - 4 \\0 & 0 & 0 & 1\end{array} \right]
E)​ [1483014800140001]\left[ \begin{array} { c c c c } 1 & 4 & 8 & - 3 \\0 & 1 & 4 & 8 \\0 & 0 & 1 & 4 \\0 & 0 & 0 & 1\end{array} \right]
Question
​Solve the system of linear equations {4x+4y=38x20y=9\left\{ \begin{array} { l } 4 x + 4 y = 3 \\8 x - 20 y = - 9\end{array} \right. using an inverse matrix.

A)​ [xy]=[3141528]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { l } \frac { 3 } { 14 } \\\\\frac { 15 } { 28 }\end{array} \right]
B)​ [xy]=[928127]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { l } \frac { 9 } { 28 } \\\\\frac { 12 } { 7 }\end{array} \right]
C)​ [xy]=[928314]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { c } \frac { 9 } { 28 } \\\\\frac { - 3 } { 14 }\end{array} \right]
D)​ [xy]=[971528]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { c } \frac { 9 } { 7 } \\\\\frac { 15 } { 28 }\end{array} \right]
E)​ [xy]=[97314]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { c } \frac { - 9 } { 7 } \\\\\frac { - 3 } { 14 }\end{array} \right]
Question
Find the inverse of the matrix.​ [152015001]\left[ \begin{array} { l l l } 1 & 5 & 2 \\0 & 1 & 5 \\0 & 0 & 1\end{array} \right]

A)​ [1523015001]\left[ \begin{array} { c c c } 1 & 5 & - 23 \\0 & 1 & 5 \\0 & 0 & 1\end{array} \right]
B)​ [1523015001]\left[ \begin{array} { c c c } - 1 & - 5 & 23 \\0 & - 1 & - 5 \\0 & 0 & - 1\end{array} \right]
C)​ [1523015001]\left[ \begin{array} { c c c } 1 & - 5 & - 23 \\0 & 1 & - 5 \\0 & 0 & 1\end{array} \right]
D)​ [1523015001]\left[ \begin{array} { l l l } 1 & 5 & 23 \\0 & 1 & 5 \\0 & 0 & 1\end{array} \right]
E)​ [1523015001]\left[ \begin{array} { c c c } 1 & - 5 & 23 \\0 & 1 & - 5 \\0 & 0 & 1\end{array} \right]
Question
Find the inverse of A.​ A=[412482001248]A = \left[ \begin{array} { c c c } - 4 & 12 & 4 \\8 & 20 & 0 \\12 & 4 & - 8\end{array} \right]

A)​ A1=136[1075412131011]A ^ { - 1 } = \frac { 1 } { 36 } \left[ \begin{array} { c c c } 10 & 7 & 5 \\4 & - 1 & 2 \\- 13 & 10 & - 11\end{array} \right]
B)​ A1=124[1075412131011]A ^ { - 1 } = \frac { 1 } { 24 } \left[ \begin{array} { c c c } 10 & 7 & 5 \\4 & 1 & 2 \\13 & 10 & 11\end{array} \right]
C)​ A1=128[1075412131011]A ^ { - 1 } = \frac { 1 } { 28 } \left[ \begin{array} { c c c } - 10 & 7 & - 5 \\4 & - 1 & 2 \\- 13 & 10 & - 11\end{array} \right]
D)​ A1=136[1075412131011]A ^ { - 1 } = \frac { 1 } { 36 } \left[ \begin{array} { c c c } - 10 & 7 & - 5 \\4 & - 1 & 2 \\- 13 & 10 & - 11\end{array} \right]
E)​ A1=128[1075412131011]A ^ { - 1 } = \frac { 1 } { 28 } \left[ \begin{array} { c c c } 10 & 7 & 5 \\4 & 1 & 2 \\13 & 10 & 11\end{array} \right]
Question
Find the inverse of the matrix.​ [4114]\left[ \begin{array} { l l } 4 & 1 \\1 & 4\end{array} \right]

A)​​ [415115115415]\left[ \begin{array} { c c } \frac { 4 } { 15 } & \frac { 1 } { 15 } \\\\\frac { 1 } { 15 } & \frac { 4 } { 15 }\end{array} \right]
B)​ [415115115415]\left[ \begin{array} { l } - \frac { 4 } { 15 } - \frac { 1 } { 15 } \\- \frac { 1 } { 15 } - \frac { 4 } { 15 }\end{array} \right]
C)​ [415115115415\left[ \begin{array} { c c } \frac { 4 } { 15 } & - \frac { 1 } { 15 } \\- \frac { 1 } { 15 } & \frac { 4 } { 15 }\end{array} \right.
D)​ [415115115415]\left[ \begin{array} { c c } - \frac { 4 } { 15 } & \frac { 1 } { 15 } \\\frac { 1 } { 15 } & - \frac { 4 } { 15 }\end{array} \right]
E)​ [41500415]\left[ \begin{array} { c c } \frac { 4 } { 15 } & 0 \\0 & \frac { 4 } { 15 }\end{array} \right]
Question
​Solve the system of linear equations {4x18x24x38x4=012x120x28x312x4=158x120x28x320x4=104x1+16x2+16x3+44x4=0\left\{ \begin{array} { l l } 4 x _ { 1 } - 8 x _ { 2 } - 4 x _ { 3 } - 8 x _ { 4 } & = 0 \\12 x _ { 1 } - 20 x _ { 2 } - 8 x _ { 3 } - 12 x _ { 4 } & = - 15 \\8 x _ { 1 } - 20 x _ { 2 } - 8 x _ { 3 } - 20 x _ { 4 } & = 10 \\- 4 x _ { 1 } + 16 x _ { 2 } + 16 x _ { 3 } + 44 x _ { 4 } & = 0\end{array} \right. using the inverse matrix 14[24712103012973212311]\frac { 1 } { 4 } \left[ \begin{array} { c c c c } - 24 & 7 & 1 & - 2 \\- 10 & 3 & 0 & - 1 \\- 29 & 7 & 3 & - 2 \\12 & - 3 & - 1 & 1\end{array} \right] .

A)​ [x1x2x3x4]=[954454754354]\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { c } \frac { - 95 } { 4 } \\\\\frac { - 45 } { 4 } \\\\\frac { - 75 } { 4 } \\\\\frac { 35 } { 4 }\end{array} \right]
B)​ [x1x2x3x4]=[054052]\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { c } 0 \\\frac { - 5 } { 4 } \\0 \\\frac { - 5 } { 2 }\end{array} \right]
C)​ [x1x2x3x4]=[4549540354]\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { c } \frac { - 45 } { 4 } \\\\\frac { - 95 } { 4 } \\\\0 \\\\\frac { 35 } { 4 }\end{array} \right]
D)​ [x1x2x3x4]=[15454052]\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { r } \frac { - 15 } { 4 } \\\frac { 5 } { 4 } \\0 \\\frac { 5 } { 2 }\end{array} \right]
E)​ [x1x2x3x4]=[354254454454]\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { c } \frac { - 35 } { 4 } \\\\\frac { - 25 } { 4 } \\\\\frac { 45 } { 4 } \\\\\frac { - 45 } { 4 }\end{array} \right]
Question
​Solve the system of linear equations {5x110x25x310x4=015x125x210x315x4=810x125x210x325x4=85x1+20x2+20x3+55x4=16\left\{ \begin{array} { l l } 5 x _ { 1 } - 10 x _ { 2 } - 5 x _ { 3 } - 10 x _ { 4 } & = 0 \\15 x _ { 1 } - 25 x _ { 2 } - 10 x _ { 3 } - 15 x _ { 4 } & = 8 \\10 x _ { 1 } - 25 x _ { 2 } - 10 x _ { 3 } - 25 x _ { 4 } & = - 8 \\- 5 x _ { 1 } + 20 x _ { 2 } + 20 x _ { 3 } + 55 x _ { 4 } & = 16\end{array} \right. using the inverse matrix 15[24712103012973212311]\frac { 1 } { 5 } \left[ \begin{array} { c c c c } - 24 & 7 & 1 & - 2 \\- 10 & 3 & 0 & - 1 \\- 29 & 7 & 3 & - 2 \\12 & - 3 & - 1 & 1\end{array} \right] .

A)​ [x1x2x3x4]=[1658585165]\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { c } \frac { 16 } { 5 } \\\\\frac { 8 } { 5 } \\\\\frac { - 8 } { 5 } \\\\\frac { - 16 } { 5 }\end{array} \right]
B)​ [x1x2x3x4]=[0850165]\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { c } 0 \\\\\frac { 8 } { 5 } \\\\0 \\\\\frac { 16 } { 5 }\end{array} \right]
C)​ [x1x2x3x4]=[1658500]\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { c } \frac { 16 } { 5 } \\\\\frac { 8 } { 5 } \\\\0 \\\\0\end{array} \right]
D)​ [x1x2x3x4]=[245850165]\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { c } \frac { 24 } { 5 } \\\\\frac { - 8 } { 5 } \\\\0 \\\\\frac { - 16 } { 5 }\end{array} \right]
E)​ [x1x2x3x4]=[24585165165]\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { c } \frac { 24 } { 5 } \\\\\frac { - 8 } { 5 } \\\\\frac { - 16 } { 5 } \\\\\frac { 16 } { 5 }\end{array} \right]
Question
Find the inverse of the matrix [36915]\left[ \begin{array} { c c } 3 & 6 \\- 9 & - 15\end{array} \right] .

A)​ 17[36915]\frac { 1 } { 7 } \left[ \begin{array} { c c } 3 & 6 \\- 9 & - 15\end{array} \right]
B)​ 13[5231]\frac { 1 } { 3 } \left[ \begin{array} { c c } - 5 & - 2 \\3 & 1\end{array} \right]
C)​ [36159]\left[ \begin{array} { c c } - 3 & - 6 \\15 & 9\end{array} \right]
D)​ [391221]\left[ \begin{array} { c c } 3 & - 9 \\12 & - 21\end{array} \right]
E)​ 113[36915]\frac { 1 } { 13 } \left[ \begin{array} { l l } - 3 & - 6 \\- 9 & 15\end{array} \right]
Question
Find the inverse of the matrix [888244032244840]\left[ \begin{array} { c c c } 8 & 8 & 8 \\24 & 40 & 32 \\24 & 48 & 40\end{array} \right] .

A)​ 18[111321332]\frac { 1 } { 8 } \left[ \begin{array} { c c c } 1 & 1 & - 1 \\- 3 & 2 & - 1 \\3 & - 3 & 2\end{array} \right]
B)​ 18[111021332]\frac { 1 } { 8 } \left[ \begin{array} { c c c } 1 & 1 & 1 \\0 & - 2 & - 1 \\3 & - 3 & 2\end{array} \right]
C)​ 8[111301332]8 \left[ \begin{array} { c c c } 1 & 1 & 1 \\- 3 & 0 & - 1 \\3 & - 3 & 2\end{array} \right]
D)​ 18[101321233]- \frac { 1 } { 8 } \left[ \begin{array} { c c c } 1 & 0 & - 1 \\- 3 & 2 & - 1 \\2 & - 3 & 3\end{array} \right]
E)​ 8[310311132]- 8 \left[ \begin{array} { c c c } 3 & 1 & 0 \\- 3 & 1 & - 1 \\1 & - 3 & 2\end{array} \right]
Question
​Use the matrix capabilities of a graphing utility to solve the following system of linear equations: {15x5y=310x+10y=620z=12\left\{ \begin{array} { c c c } 15 x - 5 y & = & 3 \\10 x + 10 y & = & 6 \\20 z & = & - 12\end{array} \right.

A)​ [xyz]=[31091035]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 3 } { 10 } \\\\\frac { 9 } { 10 } \\\\\frac { - 3 } { 5 }\end{array} \right]
B)​ [xyz]=[910035]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 9 } { 10 } \\0 \\\frac { - 3 } { 5 }\end{array} \right]
C)​ [xyz]=[31031035]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 3 } { 10 } \\\\\frac { 3 } { 10 } \\\\\frac { - 3 } { 5 }\end{array} \right]
D)​ [xyz]=[3103100]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 3 } { 10 } \\\\\frac { - 3 } { 10 } \\\\0\end{array} \right]
E)​ [xyz]=[31031035]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 3 } { 10 } \\\\\frac { 3 } { 10 } \\\\\frac { - 3 } { 5 }\end{array} \right]
Question
​Use the matrix capabilities of a graphing utility to solve the following system of linear equations:​ {14x+14y+21z=107x7y=57x+28z=20\left\{ \begin{array} { l l } - 14 x + 14 y + 21 z & = 10 \\7 x - 7 y & = - 5 \\7 x + 28 z & = 20\end{array} \right.

A)​ [xyz]=[2072570]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 20 } { 7 } \\\frac { 25 } { 7 } \\0\end{array} \right]
B)​ [xyz]=[1070157]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 10 } { 7 } \\0 \\\frac { - 15 } { 7 }\end{array} \right]
C)​ [xyz]=[15710757]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 15 } { 7 } \\\frac { 10 } { 7 } \\\frac { 5 } { 7 }\end{array} \right]
D)​ [xyz]=[57207107]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 5 } { 7 } \\\\\frac { - 20 } { 7 } \\\\\frac { 10 } { 7 }\end{array} \right]
E)​ [xyz]=[157107107]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 15 } { 7 } \\\\\frac { - 10 } { 7 } \\\\ \frac { 10 } { 7 }\end{array} \right]
Question
Find the inverse of the matrix [2154]\left[ \begin{array} { c c } - 2 & 1 \\5 & 4\end{array} \right] (if it exists).

A)​ 113[4152]\frac { 1 } { 13 } \left[ \begin{array} { c c } 4 & - 1 \\- 5 & - 2\end{array} \right]
B)​ 113[4152]- \frac { 1 } { 13 } \left[ \begin{array} { c c } 4 & - 1 \\- 5 & - 2\end{array} \right]
C)​ 113[4152]- \frac { 1 } { 13 } \left[ \begin{array} { c c } - 4 & 1 \\5 & 2\end{array} \right]
D)​ 113[2154]- \frac { 1 } { 13 } \left[ \begin{array} { c c } - 2 & 1 \\5 & 4\end{array} \right]
E)does not exist
Question
Show that B is the inverse of A.Show all your work. Show that B is the inverse of A.Show all your work.   ​<div style=padding-top: 35px>
Question
​Solve the system of linear equations​ {9x+9y+9z=127x+45y+36z=327x+54y+45z=2\left\{ \begin{array} { l l } 9 x + 9 y + 9 z & = 1 \\27 x + 45 y + 36 z & = - 3 \\27 x + 54 y + 45 z & = 2\end{array} \right. ​using the inverse matrix 19[111321332]\frac { 1 } { 9 } \left[ \begin{array} { c c c } 1 & 1 & - 1 \\- 3 & 2 & - 1 \\3 & - 3 & 2\end{array} \right] .

A)​ [xyz]=[592349]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 5 } { 9 } \\\\\frac { - 2 } { 3 } \\\\\frac { 4 } { 9 }\end{array} \right]
B)​ [xyz]=[49119169]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 4 } { 9 } \\\\\frac { - 11 } { 9 } \\\\\frac { 16 } { 9 }\end{array} \right]
C)​ [xyz]=[119frac16949]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 11 } { 9 } \\\\\\frac { 16 } { 9 } \\\\\frac { - 4 } { 9 }\end{array} \right]
D)​ [xyz]=[591329]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 5 } { 9 } \\\\\frac { 1 } { 3 } \\\\\frac { - 2 } { 9 }\end{array} \right]
E)​ [xyz]=[16949119]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 16 } { 9 } \\\\\frac { - 4 } { 9 } \\\\\frac { - 11 } { 9 }\end{array} \right]
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Deck 49: The Inverse of a Square Matrix
1
Find the inverse of the matrix (if it exists). ​​ [1237]\left[ \begin{array} { l l } 1 & 2 \\3 & 7\end{array} \right]

A)​ [7231]\left[ \begin{array} { l l } 7 & 2 \\3 & 1\end{array} \right]
B)​ [7231]\left[ \begin{array} { c c } 7 & - 2 \\- 3 & 1\end{array} \right]
C)​ [7231]\left[ \begin{array} { l l } - 7 & - 2 \\- 3 & - 1\end{array} \right]
D)​ [7231]\left[ \begin{array} { c c } - 7 & - 2 \\3 & 1\end{array} \right]
E)​ [7231]\left[ \begin{array} { c c } - 7 & 2 \\3 & - 1\end{array} \right]
[7231]\left[ \begin{array} { c c } 7 & - 2 \\- 3 & 1\end{array} \right]
2
Use the inverse formula A1=1adbc[dbca]A ^ { - 1 } = \frac { 1 } { a d - b c } \left[ \begin{array} { c c } d & - b \\- c & a\end{array} \right] to find the inverse of the 2×2 matrix (if it exists). ​​ [2315]\left[ \begin{array} { l l } 2 & 3 \\1 & 5\end{array} \right]

A)​ 17[5312]\frac { 1 } { 7 } \left[ \begin{array} { l l } 5 & 3 \\1 & 2\end{array} \right]
B)​ 17[5312]\frac { 1 } { 7 } \left[ \begin{array} { c c } - 5 & - 3 \\1 & 2\end{array} \right]
C)​ 17[5312]\frac { 1 } { 7 } \left[ \begin{array} { c c } - 5 & 3 \\1 & - 2\end{array} \right]
D)​ 17[5312]\frac { 1 } { 7 } \left[ \begin{array} { c c } 5 & - 3 \\- 1 & 2\end{array} \right]
E)​ 17[5312]\frac { 1 } { 7 } \left[ \begin{array} { l l } - 5 & - 3 \\- 1 & - 2\end{array} \right]
17[5312]\frac { 1 } { 7 } \left[ \begin{array} { c c } 5 & - 3 \\- 1 & 2\end{array} \right]
3
Solve the system of linear equations. ​​ {x2y=02x3y=8\left\{ \begin{array} { l } x - 2 y = 0 \\2 x - 3 y = 8\end{array} \right.

A)​ (16,8)( 16,8 )
B)​ (16,8)( 16 , - 8 )
C)​ (8,16)( - 8,16 )
D)​ (8,16)( 8,16 )
E)​ (16,8)( - 16,8 )
(16,8)( 16,8 )
4
Use the inverse formula A1=1adbc[dbca]A ^ { - 1 } = \frac { 1 } { a d - b c } \left[ \begin{array} { c c } d & - b \\- c & a\end{array} \right] to find the inverse of the 2×2 matrix (if it exists).​ [67513]\left[ \begin{array} { c c } 6 & 7 \\- 5 & 13\end{array} \right]

A)​ 1113[13756]\frac { 1 } { 113 } \left[ \begin{array} { c c } 13 & - 7 \\5 & 6\end{array} \right]
B)​ 1113[13756]\frac { 1 } { 113 } \left[ \begin{array} { c c } - 13 & 7 \\5 & - 6\end{array} \right]
C)​ 1113[13756]\frac { 1 } { 113 } \left[ \begin{array} { c c } - 13 & - 7 \\5 & 6\end{array} \right]
D)​ 1113[13756]\frac { 1 } { 113 } \left[ \begin{array} { c c } 13 & 7 \\5 & 6\end{array} \right]
E)​ 1113[13756]\frac { 1 } { 113 } \left[ \begin{array} { c c } - 13 & - 7 \\- 5 & - 6\end{array} \right]
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5
Use the inverse formula A1=1adbc[dbca]A ^ { - 1 } = \frac { 1 } { a d - b c } \left[ \begin{array} { c c } d & - b \\- c & a\end{array} \right] to find the inverse of the matrix (if it exists). ​​ [7979]\left[ \begin{array} { c c } - 7 & - 9 \\7 & 9\end{array} \right]

A)​ [9977]\left[ \begin{array} { c c } - 9 & - 9 \\7 & 7\end{array} \right]
B)​ [9977]\left[ \begin{array} { r r } - 9 & - 9 \\- 7 & - 7\end{array} \right]
C)​ [9977]\left[ \begin{array} { c c } - 9 & 9 \\7 & - 7\end{array} \right]
D) [9977]\left[ \begin{array} { c c } 9 & - 9 \\7 & 7\end{array} \right]
E)​Does not exist
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6
Use the inverse formula A1=1adbc[dbca]A ^ { - 1 } = \frac { 1 } { a d - b c } \left[ \begin{array} { c c } d & - b \\- c & a\end{array} \right] to find the inverse of the 2×2 matrix (if it exists). ​​ [1232]\left[ \begin{array} { c c } 1 & - 2 \\- 3 & 2\end{array} \right]

A)​ 14[2231]- \frac { 1 } { 4 } \left[ \begin{array} { c c } - 2 & - 2 \\3 & 1\end{array} \right]
B)​ 14[2231]- \frac { 1 } { 4 } \left[ \begin{array} { l l } - 2 & - 2 \\- 3 & - 1\end{array} \right]
C)​ 14[2231]- \frac { 1 } { 4 } \left[ \begin{array} { l l } 2 & 2 \\3 & 1\end{array} \right]
D)​ 14[2231]- \frac { 1 } { 4 } \left[ \begin{array} { c c } - 2 & 2 \\3 & - 1\end{array} \right]
E)​ 14[2231]- \frac { 1 } { 4 } \left[ \begin{array} { c c } 2 & - 2 \\3 & 1\end{array} \right]
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7
Find the inverse of the matrix (if it exists).​ [3004]\left[ \begin{array} { l l } 3 & 0 \\0 & 4\end{array} \right]

A)​ [140014]\left[ \begin{array} { l l } \frac { 1 } { 4 } & 0 \\0 & \frac { 1 } { 4 }\end{array} \right]
B)​ [14000]\left[ \begin{array} { l l } \frac { 1 } { 4 } & 0 \\0 & 0\end{array} \right]
C)​ [014140]\left[ \begin{array} { c c } 0 & \frac { 1 } { 4 } \\\frac { 1 } { 4 } & 0\end{array} \right]
D)​ [140013]\left[ \begin{array} { l l } \frac { 1 } { 4 } & 0 \\0 & \frac { 1 } { 3 }\end{array} \right]
E)​ [130014]\left[ \begin{array} { l l } \frac { 1 } { 3 } & 0 \\0 & \frac { 1 } { 4 }\end{array} \right]
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8
Find the inverse of the matrix (if it exists).​ [6778]\left[ \begin{array} { l l } 6 & - 7 \\7 & - 8\end{array} \right]

A)​ [8776]\left[ \begin{array} { c c } - 8 & 7 \\7 & 6\end{array} \right]
B)​ [8776]\left[ \begin{array} { c c } - 8 & 7 \\- 7 & 6\end{array} \right]
C)​ [8776]\left[ \begin{array} { c c } - 8 & - 7 \\- 7 & 6\end{array} \right]
D)​ [8776]\left[ \begin{array} { c c } - 8 & 7 \\7 & - 6\end{array} \right]
E)​ [8776]\left[ \begin{array} { c c } - 8 & - 7 \\7 & 6\end{array} \right]
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9
Use the inverse formula A1=1adbc[dbca]A ^ { - 1 } = \frac { 1 } { a d - b c } \left[ \begin{array} { c c } d & - b \\- c & a\end{array} \right] to find the inverse of the 2×2 matrix (if it exists). ​​ [12352]\left[ \begin{array} { c c } - 12 & 3 \\5 & 2\end{array} \right]

A)​ 139[23512]- \frac { 1 } { 39 } \left[ \begin{array} { c c } 2 & - 3 \\- 5 & - 12\end{array} \right]
B)​ 139[23512]- \frac { 1 } { 39 } \left[ \begin{array} { c c } - 2 & - 3 \\5 & 12\end{array} \right]
C)​ 139[23512]- \frac { 1 } { 39 } \left[ \begin{array} { c c } - 2 & 3 \\5 & - 12\end{array} \right]
D)​ 139[23512]- \frac { 1 } { 39 } \left[ \begin{array} { c c } 2 & - 3 \\5 & 12\end{array} \right]
E)​ 139[23512]- \frac { 1 } { 39 } \left[ \begin{array} { l l } - 2 & - 3 \\- 5 & - 12\end{array} \right]
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10
Find the inverse of the matrix (if it exists).​ [4131]\left[ \begin{array} { c c } 4 & - 1 \\- 3 & 1\end{array} \right]

A)​ [1134]\left[ \begin{array} { l l } 1 & 1 \\3 & 4\end{array} \right]
B)​ [1134]\left[ \begin{array} { c c } 1 & 1 \\- 3 & 4\end{array} \right]
C)​ [1134]\left[ \begin{array} { c c } - 1 & 1 \\3 & 4\end{array} \right]
D)​ [1134]\left[ \begin{array} { c c } 1 & 1 \\3 & - 4\end{array} \right]
E)Does not exist
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11
Use an inverse matrix to solve (if possible)the system of linear equations.​ {3x+4y=25x+3y=4\left\{ \begin{array} { l } 3 x + 4 y = - 2 \\5 x + 3 y = 4\end{array} \right.

A)​ (2,2)( - 2,2 )
B)​ (2,2)( 2,2 )
C)​ (2,2)( - 2 , - 2 )
D)​ (2,2)( 2 , - 2 )
E)​ (1,2)( - 1,2 )
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12
Find the inverse of the matrix (if it exists).​ [40060051111]\left[ \begin{array} { c c c } 4 & 0 & 0 \\6 & 0 & 0 \\5 & 11 & 11\end{array} \right]

A)​ [4006005411]\left[ \begin{array} { c c c } - 4 & 0 & 0 \\- 6 & 0 & 0 \\5 & 4 & 11\end{array} \right]
B)​ [4006005411]\left[ \begin{array} { c c c } - 4 & 0 & 0 \\- 6 & 0 & 0 \\- 5 & - 4 & - 11\end{array} \right]
C)​ [4006005411]\left[ \begin{array} { c c c } 4 & 0 & 0 \\6 & 0 & 0 \\5 & 4 & 11\end{array} \right]
D)​ [4006005411]\left[ \begin{array} { c c c } - 4 & 0 & 0 \\- 6 & 0 & 0 \\- 5 & 4 & 11\end{array} \right]
E)Does not exist
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13
Solve the system of linear equations.​ {x+y+z=73x+5y+4z=83x+6y+5z=0\left\{ \begin{array} { c } x + y + z = - 7 \\3 x + 5 y + 4 z = 8 \\3 x + 6 y + 5 z = 0\end{array} \right.

A)​ (2,37,45)( 2,37 , - 45 )
B)​ (1,37,45)( - 1,37 , - 45 )
C)​ (1,37,45)( - 1 , - 37 , - 45 )
D)​ (1,37,45)( 1,37 , - 45 )
E)​ (1,38,45)( 1,38 , - 45 )
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14
Solve the system of linear equations.​ {x2y=62x3y=4\left\{ \begin{array} { c } x - 2 y = 6 \\2 x - 3 y = 4\end{array} \right. ​ ​

A)​ (10,8)( - 10 , - 8 )
B)​ (10,8)( - 10,8 )
C)​ (10,4)( - 10,4 )
D)​ (4,10)( - 4 , - 10 )
E)​ (10,8)( 10,8 )
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15
Find the inverse of the matrix (if it exists).​ [733419]\left[ \begin{array} { c c } - 7 & 33 \\4 & - 19\end{array} \right]

A)​ [193347]\left[ \begin{array} { c c } - 19 & - 33 \\4 & - 7\end{array} \right]
B)​ [193347]\left[ \begin{array} { c c } - 19 & - 33 \\- 4 & - 7\end{array} \right]
C)​ [193347]\left[ \begin{array} { c c } 19 & - 33 \\- 4 & - 7\end{array} \right]
D)​ [193347]\left[ \begin{array} { c c } 19 & - 33 \\4 & - 7\end{array} \right]
E)​ [193347]\left[ \begin{array} { c c } 19 & - 33 \\4 & 7\end{array} \right]
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16
Solve the system of linear equations.​ {x2y=52x3y=10\left\{ \begin{array} { l l } x - 2 y & = 5 \\2 x - 3 y & = 10\end{array} \right.

A)​ (5,10)( 5,10 )
B)​ (5,5)( 5,5 )
C)​ (10,5)( 10,5 )
D)​ (5,0)( 5,0 )
E)​ (0,5)( 0,5 )
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17
Solve the system of linear equations.​ {x2y=32x3y=4\left\{ \begin{array} { l } x - 2 y = 3 \\2 x - 3 y = - 4\end{array} \right.

A)​ (17,4)( - 17,4 )
B)​ (17,10)( - 17,10 )
C)​ (4,17)( - 4 , - 17 )
D)​ (17,10)( 17,10 )
E)​ (17,10)( - 17 , - 10 )
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18
Find the inverse of the matrix (if it exists).​ [500200157]\left[ \begin{array} { c c c } - 5 & 0 & 0 \\2 & 0 & 0 \\1 & 5 & 7\end{array} \right]

A)​ [500200157]\left[ \begin{array} { l l l } 5 & 0 & 0 \\2 & 0 & 0 \\1 & 5 & 7\end{array} \right]
B)​ [500200157]\left[ \begin{array} { c c c } - 5 & 0 & 0 \\- 2 & 0 & 0 \\1 & 5 & 7\end{array} \right]
C) [500200157]\left[ \begin{array} { c c c } - 5 & 0 & 0 \\- 2 & 0 & 0 \\- 1 & - 5 & - 7\end{array} \right]
D)​ [500200157]\left[ \begin{array} { l l l } - 5 & 0 & 0 \\- 2 & 0 & 0 \\- 1 & 5 & 7\end{array} \right]
E)​Does not exist
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19
Solve the system of linear equations.​ {x+y+z=03x+5y+4z=93x+6y+5z=6\left\{ \begin{array} { l } x + y + z = 0 \\3 x + 5 y + 4 z = 9 \\3 x + 6 y + 5 z = 6\end{array} \right.

A)​ (3,12,15)( 3,12 , - 15 )
B)​ (3,12,15)( 3,12,15 )
C)​ (3,12,15)( - 3 , - 12 , - 15 )
D)​ (3,12,15)( 3 , - 12 , - 15 )
E)​ (3,12,15)( - 3,12 , - 15 )
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20
​Use an inverse matrix to solve (if possible)the system of linear equations.​ {18x+12y=1430x+24y=24\left\{ \begin{array} { l } 18 x + 12 y = 14 \\30 x + 24 y = 24\end{array} \right.

A)​( 56\frac { 5 } { 6 } , 16\frac { 1 } { 6 } )
B)​( 4, 16\frac { 1 } { 6 } )
C)​( 23\frac { 2 } { 3 } , 16\frac { 1 } { 6 } )
D)​( 23\frac { 2 } { 3 } , 14\frac { 1 } { 4 } )
E)​( 23\frac { 2 } { 3 } ,3 )
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21
The table shows the enrollment projections (in millions)for public universities in the United States for the years 2010 through 2012.
Year
Enrollment projections
2010
13)83
2011
14)07
2012
14)23
The data can be modeled by the quadratic function y=at2+bt+cy=a t^{2}+b t+c .Create a system of linear equations for the data.Let t represent the year,with t = 10 corresponding to 2010.

A) {100a+10b+c=13.83121a11b+c=14.07144a+12b+c=14.23\left\{ \begin{array} { l } 100 a + 10 b + c = 13.83 \\121 a - 11 b + c = 14.07 \\144 a + 12 b + c = 14.23\end{array} \right.
B)​ {100a10b+c=13.83121a+11b+c=14.07144a+12b+c=14.23\left\{ \begin{array} { l } 100 a - 10 b + c = 13.83 \\121 a + 11 b + c = 14.07 \\144 a + 12 b + c = 14.23\end{array} \right.
C)​ {100a+10b+c=13.83121a+11b+c=14.07144a+12b+c=14.23\left\{ \begin{array} { l } 100 a + 10 b + c = 13.83 \\121 a + 11 b + c = 14.07 \\144 a + 12 b + c = 14.23\end{array} \right.
D)​ {100a+10b+c=13.83121a+11b+c=14.07144a+12bc=14.23\left\{ \begin{array} { l } 100 a + 10 b + c = 13.83 \\121 a + 11 b + c = 14.07 \\144 a + 12 b - c = 14.23\end{array} \right.
E)​ {100a10bc=13.83121a11bc=14.07144a12bc=14.23\left\{ \begin{array} { l } 100 a - 10 b - c = 13.83 \\121 a - 11 b - c = 14.07 \\144 a - 12 b - c = 14.23\end{array} \right.
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22
Consider a person who invests in AAA-rated bonds,A-rated bonds,and B-rated bonds.The average yields are 6.5% on AAA bonds,7% on A bonds,and 9% on B bonds.The person invests twice as much in B bonds as in A bonds.Let x,y and z represent the amounts invested in AAA,A,and B bonds,respectively. Total Investment
Annual Return
$12,000
890 {x+y+z=12,000 (total investment) 0.065x+0.07y+0.09z=890 (annual retum) 2yz=0\left\{ \begin{array} { c l } x + y + z & = 12,000 \text { (total investment) } \\0.065 x + 0.07 y + 0.09 z & = 890 \text { (annual retum) } \\2 y - z & = 0\end{array} \right. Use the inverse of the coefficient matrix of this system to find the amount invested in each type of bond.

A)$7,000 in AAA-rated bonds $2,000 in A-rated bonds
$4,000 in B-rated bonds
B)$5,000 in AAA-rated bonds $7,000 in A-rated bonds
$3,000 in B-rated bonds
C)$5,000 in AAA-rated bonds $6,000 in A-rated bonds
$4,000 in B-rated bonds
D)$3,000 in AAA-rated bonds $2,000 in A-rated bonds
$6,000 in B-rated bonds
E)$6,000 in AAA-rated bonds $2,000 in A-rated bonds
$4,000 in B-rated bonds
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23
Find the inverse of the matrix [24610]\left[ \begin{array} { c c } 2 & 4 \\- 6 & - 10\end{array} \right] .

A)​ 113[24610]\frac { 1 } { 13 } \left[ \begin{array} { l l } - 2 & - 4 \\- 6 & 10\end{array} \right]
B)​ [24106]\left[ \begin{array} { c c } - 2 & - 4 \\10 & 6\end{array} \right]
C)​ [26814]\left[ \begin{array} { c c } 2 & - 6 \\8 & - 14\end{array} \right]
D)​ 17[24610]\frac { 1 } { 7 } \left[ \begin{array} { c c } 2 & 4 \\- 6 & - 10\end{array} \right]
E)​ 12[5231]\frac { 1 } { 2 } \left[ \begin{array} { c c } - 5 & - 2 \\3 & 1\end{array} \right]
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24
Find the inverse of the matrix [1432]\left[ \begin{array} { c c } - 1 & 4 \\3 & - 2\end{array} \right] (if it exists).

A)​ 110[2431]- \frac { 1 } { - 10 } \left[ \begin{array} { l l } - 2 & - 4 \\- 3 & - 1\end{array} \right]
B) 110[1432]- \frac { 1 } { - 10 } \left[ \begin{array} { c c } - 1 & 4 \\3 & - 2\end{array} \right]
C)​ 110[2431]\frac { 1 } { - 10 } \left[ \begin{array} { l l } - 2 & - 4 \\- 3 & - 1\end{array} \right]
D)​ 110[2431]\frac { 1 } { - 10 } \left[ \begin{array} { l l } 2 & 4 \\3 & 1\end{array} \right]
E)​does not exist
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25
A small home business creates muffins,bones,and cookies for dogs.In addition to other ingredients,each muffin requires 2 units of beef,3 units of chicken,and 2 units of liver.Each bone requires 1 unit of beef,1 unit of chicken,and 1 unit of liver.Each cookie requires 2 units of beef,1 unit of chicken,and 1.5 units of liver.Find the numbers of muffins,bones,and cookies that the company can create with the given amounts of ingredients. ​
875 units of beef
830 units of chicken
850 units of liver

A)765 muffins,5 bones,50 cookies
B)50 muffins,765 bones,50 cookies
C)5 muffins,765 bones,50 cookies
D)50 muffins,765 bones,5 cookies
E)5 muffins,5 bones,830 cookies
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26
A florist is creating 10 centerpieces for the tables at a wedding reception.Roses cost $2.50 each,lilies cost $8 each,and irises cost $4 each.The customer has a budget of $300 allocated for the centerpieces and wants each centerpiece to contain 12 flowers,with twice as many roses as the number of irises and lilies combined. ​
Write a system of linear equations that represents the situation.

A) {2.5r8l4i=300r2l2i=0rli=120\left\{ \begin{array} { l l } 2.5 r - 8 l - 4 i & = 300 \\- r - 2 l - 2 i & = 0 \\r - l - i & = 120\end{array} \right.
B)​ {2.5r+8l+4i=300r+2l+2i=0r+l+i=120\left\{ \begin{array} { l l } 2.5 r + 8 l + 4 i & = 300 \\r + 2 l + 2 i & = 0 \\r + l + i & = 120\end{array} \right.
C)​ {2.5r+8l+4i=300r+2l+2i=0r+l+i=120\left\{ \begin{array} { l l } 2.5 r + 8 l + 4 i & = 300 \\- r + 2 l + 2 i & = 0 \\r + l + i & = 120\end{array} \right.
D)​ {2.5r8l+4i=300r+2l+2i=0r+l+i=120\left\{ \begin{array} { l l } 2.5 r - 8 l + 4 i & = 300 \\- r + 2 l + 2 i & = 0 \\r + l + i & = 120\end{array} \right.
E)​ {2.5r+8l4i=300r+2l+2i=0r+l+i=120\left\{ \begin{array} { l l } 2.5 r + 8 l - 4 i & = 300 \\- r + 2 l + 2 i & = 0 \\r + l + i & = 120\end{array} \right.
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27
​Solve the system of linear equations {2x+3y=154x3y=10\left\{ \begin{array} { l } 2 x + 3 y = - 15 \\4 x - 3 y = 10\end{array} \right. using the inverse matrix [16162919]\left[ \begin{array} { c c } \frac { 1 } { 6 } & \frac { 1 } { 6 } \\\\\frac { 2 } { 9 } & - \frac { 1 } { 9 }\end{array} \right]

A)​ [xy]=[5652]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { l } \frac { 5 } { 6 } \\\\\frac { 5 } { 2 }\end{array} \right]
B)​ [xy]=[56409]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { c } - \frac { 5 } { 6 } \\\\- \frac { 40 } { 9 }\end{array} \right]
C)​ [xy]=[251852]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { c } \frac { 25 } { 18 } \\\\\frac { 5 } { 2 }\end{array} \right]
D)​ [xy]=[520]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { l } \frac { 5 } { 2 } \\0\end{array} \right]
E)​ [xy]=[5356]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { c } - \frac { 5 } { 3 } \\\\\frac { 5 } { 6 }\end{array} \right]
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28
Use an inverse matrix to solve (if possible)the system of linear equations.​ {0.2x0.6y=14.4x+1.4y=20.8\left\{ \begin{array} { l } 0.2 x - 0.6 y = 14.4 \\- x + 1.4 y = - 20.8\end{array} \right.

A)(-24,-31)
B)(-23,-32)
C)(-22,-32)
D)(-24,-32)
E)(-23,-30)
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29
​Use an inverse matrix to solve (if possible)the system of linear equations.​ {1.8x5y=428.8x16y=5\left\{ \begin{array} { l l } 1.8 x - 5 y & = 4 \\28.8 x - 16 y & = 5\end{array} \right.

A)​( 116\frac { 1 } { 16 } ,16)
B)​(0,0)
C)​( 116\frac { 1 } { 16 } , 516\frac { 5 } { 16 } )
D)​(16,16)
E)​No solution
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30
A coffee manufacturer sells a 14-pound package that contains three flavors of coffee for $25.French vanilla coffee costs $5 per pound,hazelnut flavored coffee costs $5.50 per pound,and Swiss chocolate flavored coffee costs $6 per pound.The package contains the same amount of hazelnut as Swiss chocolate.Let f represent the number of pounds of French vanilla,h represent the number of pounds of hazelnut,and s represent the number of pounds of Swiss chocolate. ​
Write a system of linear equations that represents the situation.

A) {5f5.5h+6s=25f+h+s=14hs=0\left\{ \begin{array} { c l } 5 f - 5.5 h + 6 s & = 25 \\f + h + s & = 14 \\h - s & = 0\end{array} \right.
B)​ {5f+5.5h+6s=25f+h+s=14hs=0\left\{ \begin{aligned}5 f + 5.5 h + 6 s & = 25 \\f + h + s & = 14 \\h - s & = 0\end{aligned} \right.
C)​ {5f5.5h+6s=25fh+s=14hs=0\left\{ \begin{array} { c l } 5 f - 5.5 h + 6 s & = 25 \\f - h + s & = 14 \\h - s & = 0\end{array} \right.
D)​ {5f5.5h+6s=25f+h+s=14h+s=0\left\{ \begin{array} { c l } 5 f - 5.5 h + 6 s & = 25 \\f + h + s & = 14 \\h + s & = 0\end{array} \right.
E)​ {5f5.5h6s=25fhs=14h+s=0\left\{ \begin{array} { c l } 5 f - 5.5 h - 6 s & = 25 \\f - h - s & = 14 \\h + s & = 0\end{array} \right.
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31
Find the inverse of the matrix [1622811]\left[ \begin{array} { c c } - 16 & 22 \\- 8 & 11\end{array} \right] (if it exists).

A)does not exist
B)​ 116- \frac { 1 } { 16 } [1122816]\left[ \begin{array} { c c } 11 & - 22 \\8 & - 16\end{array} \right]
C)​ 111\frac { 1 } { 11 } [1622811]\left[ \begin{array} { c c } - 16 & 22 \\- 8 & 11\end{array} \right]
D)​ 122- \frac { 1 } { 22 } [1122816]\left[ \begin{array} { c c } - 11 & 22 \\- 8 & 16\end{array} \right]
E)​ 18\frac { 1 } { 8 } [1122816]\left[ \begin{array} { c c } 11 & - 22 \\8 & - 16\end{array} \right]
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32
Consider a person who invests in AAA-rated bonds,A-rated bonds,and B-rated bonds.The average yields are 6.5% on AAA bonds,7% on A bonds,and 9% on B bonds.The person invests twice as much in B bonds as in A bonds.Let x,y and z represent the amounts invested in AAA,A,and B bonds,respectively. Total Investment
Annual Return
$32,000
2465 {x+y+z=32,000 (total investment) 0.065x+0.07y+0.09z=2465 (annual retur) 2yz=0\left\{ \begin{array} { c l } x + y + z & = 32,000 \text { (total investment) } \\0.065 x + 0.07 y + 0.09 z & = 2465 \text { (annual retur) } \\2 y - z & = 0\end{array} \right. Use the inverse of the coefficient matrix of this system to find the amount invested in each type of bond.

A)$11,000 in AAA-rated bonds $7,000 in A-rated bonds
$14,000 in B-rated bonds
B)$11,000 in AAA-rated bonds $14,000 in A-rated bonds
$7,000 in B-rated bonds
C)$14,000 in AAA-rated bonds $11,000 in A-rated bonds
$7,000 in B-rated bonds
D)$14,000 in AAA-rated bonds $7,000 in A-rated bonds
$11,000 in B-rated bonds
E)$7,000 in AAA-rated bonds $11,000 in A-rated bonds
$14,000 in B-rated bonds
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33
A small home business creates muffins,bones,and cookies for dogs.In addition to other ingredients,each muffin requires 2 units of beef,3 units of chicken,and 2 units of liver.Each bone requires 1 unit of beef,1 unit of chicken,and 1 unit of liver.Each cookie requires 2 units of beef,1 unit of chicken,and 1.5 units of liver.Find the numbers of muffins,bones,and cookies that the company can create with the given amounts of ingredients. ​
900 units of beef
700 units of chicken
800 units of liver

A)200 muffins,500 bones,200 cookies
B)200 muffins,500 bones,0 cookies
C)0 muffins,0 bones,700 cookies
D)500 muffins,0 bones,200 cookies
E)0 muffins,500 bones,200 cookies
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34
​Solve the system of linear equations {3x+6y=16x+8y=2\left\{ \begin{array} { l } 3 x + 6 y = 1 \\6 x + 8 y = 2\end{array} \right. using the inverse matrix [23121214]\left[ \begin{array} { c c } - \frac { 2 } { 3 } & \frac { 1 } { 2 } \\\frac { 1 } { 2 } & - \frac { 1 } { 4 }\end{array} \right]

A)​ [xy]=[11120]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { c } \frac { 11 } { 12 } \\0\end{array} \right]
B)​ [xy]=[130]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { l } \frac { 1 } { 3 } \\0\end{array} \right]
C)​ [xy]=[111213]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { c } \frac { 11 } { 12 } \\\\\frac { 1 } { 3 }\end{array} \right]
D)​ [xy]=[1312]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { c } \frac { 1 } { 3 } \\- \frac { 1 } { 2 }\end{array} \right]
E)​ [xy]=[1213]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { c } - \frac { 1 } { 2 } \\\frac { 1 } { 3 }\end{array} \right]
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35
Consider a person who invests in AAA-rated bonds,A-rated bonds,and B-rated bonds.The average yields are 6.5% on AAA bonds,7% on A bonds,and 9% on B bonds.The person invests twice as much in B bonds as in A bonds.Let x,y and z represent the amounts invested in AAA,A,and B bonds,respectively.  Total Investment  Annual Return $12,000890\begin{array} { | c | c | } \hline \text { Total Investment } & \text { Annual Return } \\\hline \$ 12,000 & 890 \\\hline\end{array} {x+y+z=663,000 (total investment) 0.065x+0.07y+0.09z=47,000 (annual retum) 2yz=0\left\{ \begin{array} { c l } x + y + z & = 663,000 \text { (total investment) } \\0.065 x + 0.07 y + 0.09 z & = 47,000 \text { (annual retum) } \\2 y - z & = 0\end{array} \right. Use the inverse of the coefficient matrix of this system to find the amount invested in each type of bond.

A)$142,000 in AAA-rated bonds $451,000 in A-rated bonds
$71,000 in B-rated bonds
B)$450,000 in AAA-rated bonds $71,000 in A-rated bonds
$142,000 in B-rated bonds
C)$143,000 in AAA-rated bonds $71,000 in A-rated bonds
$450,000 in B-rated bonds
D)$72,000 in AAA-rated bonds $450,000 in A-rated bonds
$142,000 in B-rated bonds
E)$450,000 in AAA-rated bonds $142,000 in A-rated bonds
$70,000 in B-rated bonds
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36
Use the matrix capabilities of a graphing utility to find the inverse of the matrix 19[453483120]\frac { 1 } { 9 } \left[ \begin{array} { c c c } - 4 & - 5 & 3 \\- 4 & - 8 & 3 \\1 & 2 & 0\end{array} \right] (if it exists).

A)​ [9126030039]\left[ \begin{array} { c c c } - 9 & 12 & 6 \\0 & - 3 & 0 \\0 & 3 & - 9\end{array} \right]
B)​ [6693300312]\left[ \begin{array} { c c c } - 6 & 6 & 9 \\3 & - 3 & 0 \\0 & 3 & 12\end{array} \right]
C)​ [609030036]\left[ \begin{array} { c c c } - 6 & 0 & 9 \\0 & - 3 & 0 \\0 & 3 & - 6\end{array} \right]
D) [3390300612]\left[ \begin{array} { c c c } 3 & 3 & 9 \\0 & - 3 & 0 \\0 & 6 & 12\end{array} \right]
E)​does not exist ​
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37
A small home business creates muffins,bones,and cookies for dogs.In addition to other ingredients,each muffin requires 2 units of beef,3 units of chicken,and 2 units of liver.Each bone requires 1 unit of beef,1 unit of chicken,and 1 unit of liver.Each cookie requires 2 units of beef,1 unit of chicken,and 1.5 units of liver.Find the numbers of muffins,bones,and cookies that the company can create with the given amounts of ingredients. ​
3,000 units of beef
2,950 units of chicken
2,900 units of liver

A)200 muffins,2,300 bones,200 cookies
B)150 muffins,150 bones,2,950 cookies
C)200 muffins,2,300 bones,150 cookies
D)2,300 muffins,150 bones,200 cookies
E)150 muffins,2,300 bones,200 cookies
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38
Find the inverse of the matrix [777213528214235]\left[ \begin{array} { c c c } 7 & 7 & 7 \\21 & 35 & 28 \\21 & 42 & 35\end{array} \right] . ​

A)​ 17[111321332]\frac { 1 } { 7 } \left[ \begin{array} { c c c } 1 & 1 & - 1 \\- 3 & 2 & - 1 \\3 & - 3 & 2\end{array} \right]
B)​ 17[111021332]\frac { 1 } { 7 } \left[ \begin{array} { c c c } 1 & 1 & 1 \\0 & - 2 & - 1 \\3 & - 3 & 2\end{array} \right]
C)​ 7[310311132]- 7 \left[ \begin{array} { c c c } 3 & 1 & 0 \\- 3 & 1 & - 1 \\1 & - 3 & 2\end{array} \right]
D)​ 17[101321233]- \frac { 1 } { 7 } \left[ \begin{array} { c c c } 1 & 0 & - 1 \\- 3 & 2 & - 1 \\2 & - 3 & 3\end{array} \right]
E)​ 7[111301332]7 \left[ \begin{array} { c c c } 1 & 1 & 1 \\- 3 & 0 & - 1 \\3 & - 3 & 2\end{array} \right]
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39
Find the inverse of the following matrix.​ [cosθsinθsinθcosθ]\left[ \begin{array} { c c } \cos \theta & \sin \theta \\- \sin \theta & \cos \theta\end{array} \right]

A)​ [cosθsinθsinθcosθ]\left[ \begin{array} { c c } \cos \theta & - \sin \theta \\\sin \theta & \cos \theta\end{array} \right]
B)​ [cosθsinθsinθcosθ]\left[ \begin{array} { c c } - \cos \theta & - \sin \theta \\\sin \theta & \cos \theta\end{array} \right]
C)​ [cosθsinθsinθcosθ]\left[ \begin{array} { c c } \cos \theta & \sin \theta \\- \sin \theta & \cos \theta\end{array} \right]
D)​ [cosθsinθsinθcosθ]\left[ \begin{array} { c c } \cos \theta & \sin \theta \\- \sin \theta & - \cos \theta\end{array} \right]
E)​ [cosθsinθsinθcosθ]\left[ \begin{array} { l l } \cos \theta & - \sin \theta \\\sin \theta & - \cos \theta\end{array} \right]
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40
A small home business creates muffins,bones,and cookies for dogs.In addition to other ingredients,each muffin requires 2 units of beef,3 units of chicken,and 2 units of liver.Each bone requires 1 unit of beef,1 unit of chicken,and 1 unit of liver.Each cookie requires 2 units of beef,1 unit of chicken,and 1.5 units of liver.Find the numbers of muffins,bones,and cookies that the company can create with the given amounts of ingredients. ​
800 units of beef
750 units of chicken
725 units of liver

A)150 muffins,300 bones,150 cookies
B)150 muffins,300 bones,100 cookies
C)300 muffins,100 bones,150 cookies
D)100 muffins,300 bones,150 cookies
E)100 muffins,100 bones,750 cookies
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41
​Solve the system of linear equations {6x+18y+6z=112x+30y=218x+6y12z=1\left\{ \begin{array} { l l } - 6 x + 18 y + 6 z & = 1 \\12 x + 30 y & = 2 \\18 x + 6 y - 12 z & = - 1\end{array} \right. using an inverse matrix. ​

A)​ [xyz]=[161213]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 1 } { 6 } \\\\\frac { - 1 } { 2 } \\\\\frac { 1 } { 3 }\end{array} \right]
B)​ [xyz]=[161213]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 1 } { 6 } \\\\\frac { - 1 } { 2 } \\\\\frac { - 1 } { 3 }\end{array} \right]
C)​ [xyz]=[16012]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 1 } { 6 } \\0 \\\frac { 1 } { 2 }\end{array} \right]
D)​ [xyz]=[01316]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } 0 \\\frac { 1 } { 3 } \\\frac { - 1 } { 6 }\end{array} \right]
E)​ [xyz]=[16013]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { l } \frac { 1 } { 6 } \\0 \\\frac { 1 } { 3 }\end{array} \right]
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42
​Solve the system of linear equations​ {7x+7y+7z=021x+35y+28z=621x+42y+35z=1\left\{ \begin{array} { l l } 7 x + 7 y + 7 z & = 0 \\21 x + 35 y + 28 z & = 6 \\21 x + 42 y + 35 z & = 1\end{array} \right. ​using the inverse matrix 17[111321332]\frac { 1 } { 7 } \left[ \begin{array} { c c c } 1 & 1 & - 1 \\- 3 & 2 & - 1 \\3 & - 3 & 2\end{array} \right] .

A)​ [xyz]=[57117127]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 5 } { 7 } \\\\\frac { 11 } { 7 } \\\\\frac { - 12 } { 7 }\end{array} \right]
B)​ [xyz]=[57117167]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 5 } { 7 } \\\\\frac { 11 } { 7 } \\\\\frac { - 16 } { 7 }\end{array} \right]
C)​ [xyz]=[16757117]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 16 } { 7 } \\\\\frac { 5 } { 7 } \\\\\frac { 11 } { 7 }\end{array} \right]
D)​ [xyz]=[12711757]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 12 } { 7 } \\\\\frac { 11 } { 7 } \\\\\frac { - 5 } { 7 }\end{array} \right]
E)​ [xyz]=[57167117]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 5 } { 7 } \\\\\frac { - 16 } { 7 } \\\\\frac { 11 } { 7 }\end{array} \right]
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43
Find the inverse of A.​ A=[2341]A = \left[ \begin{array} { c c } 2 & 3 \\- 4 & 1\end{array} \right]

A)​ A1=[17372717]A ^ { - 1 } = \left[ \begin{array} { c c } \frac { 1 } { 7 } & - \frac { 3 } { 7 } \\\\\frac { 2 } { 7 } & \frac { 1 } { 7 }\end{array} \right]
B)​ A1=[1143142717]A ^ { - 1 } = \left[ \begin{array} { c c } \frac { 1 } { 14 } & - \frac { 3 } { 14 } \\\\\frac { 2 } { 7 } & \frac { 1 } { 7 }\end{array} \right]
C)​ A1=[1143727114]A ^ { - 1 } = \left[ \begin{array} { c c } \frac { 1 } { 14 } & - \frac { 3 } { 7 } \\\\\frac { 2 } { 7 } & \frac { 1 } { 14 }\end{array} \right]
D)​ A1=[1143142717]A ^ { - 1 } = \left[ \begin{array} { c c } \frac { 1 } { 14 } & \frac { 3 } { 14 } \\\frac { 2 } { 7 } & \frac { 1 } { 7 }\end{array} \right]
E)​ A1=[1737214114]A ^ { - 1 } = \left[ \begin{array} { c c } \frac { 1 } { 7 } & - \frac { 3 } { 7 } \\\frac { 2 } { 14 } & \frac { 1 } { 14 }\end{array} \right]
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44
Find the inverse of the matrix.​ [105115511]\left[ \begin{array} { c c c } 1 & 0 & 5 \\1 & 1 & 5 \\- 5 & 1 & 1\end{array} \right]

A)​​ [2955110611]\left[ \begin{array} { c c c } - 29 & 5 & - 5 \\- 1 & 1 & 0 \\6 & 1 & 1\end{array} \right]
B) [4526526110626126126]\left[ \begin{array} { c c c } 4 & \frac { 5 } { 26 } & - \frac { 5 } { 26 } \\1 & 1 & 0 \\\frac { 6 } { 26 } & - \frac { 1 } { 26 } & \frac { 1 } { 26 }\end{array} \right]
C)​ [426526526110626126126]\left[ \begin{array} { c c c } - \frac { 4 } { 26 } & \frac { 5 } { 26 } & - \frac { 5 } { 26 } \\- 1 & 1 & 0 \\\frac { 6 } { 26 } & - \frac { 1 } { 26 } & \frac { 1 } { 26 }\end{array} \right]
D)​ [2955111611]\left[ \begin{array} { c c c } 29 & 5 & - 5 \\- 1 & 1 & - 1 \\6 & - 1 & 1\end{array} \right]
E)​ [2955111611]\left[ \begin{array} { c c c } 29 & 5 & - 5 \\- 1 & 1 & 1 \\6 & - 1 & 1\end{array} \right]
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45
Find the inverse of the matrix [81447]\left[ \begin{array} { c c } - 8 & 14 \\- 4 & 7\end{array} \right] (if it exists).

A)​ 14[71448]\frac { 1 } { 4 } \left[ \begin{array} { l l } 7 & - 14 \\4 & - 8\end{array} \right]
B)​ 18[71448]- \frac { 1 } { 8 } \left[ \begin{array} { c c } 7 & - 14 \\4 & - 8\end{array} \right]
C)​ 14[71448]- \frac { 1 } { 4 } \left[ \begin{array} { c c } - 7 & - 14 \\4 & 8\end{array} \right]
D)​ 17[81447]\frac { 1 } { 7 } \left[ \begin{array} { c c } - 8 & 14 \\- 4 & 7\end{array} \right]
E)does not exist
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46
Use a graphing calculator to find the inverse of the matrix.​ [1483014800140001]\left[ \begin{array} { l l l l } 1 & 4 & 8 & 3 \\0 & 1 & 4 & 8 \\0 & 0 & 1 & 4 \\0 & 0 & 0 & 1\end{array} \right] ​ ​

A)​ [1483014800140001]\left[ \begin{array} { c c c c } 1 & 4 & 8 & - 3 \\0 & 1 & - 4 & 8 \\0 & 0 & 1 & 4 \\0 & 0 & 0 & 1\end{array} \right]
B)​ [1483014800140001]\left[ \begin{array} { c c c c } 1 & - 4 & 8 & 3 \\0 & 1 & - 4 & 8 \\0 & 0 & 1 & - 4 \\0 & 0 & 0 & 1\end{array} \right]
C)​ [1483014800140001]\left[ \begin{array} { c c c c } 1 & - 4 & - 8 & - 3 \\0 & 1 & - 4 & - 8 \\0 & 0 & 1 & - 4 \\0 & 0 & 0 & 1\end{array} \right]
D)​ [1483014800140001]\left[ \begin{array} { c c c c } 1 & - 4 & 8 & - 3 \\0 & 1 & - 4 & 8 \\0 & 0 & 1 & - 4 \\0 & 0 & 0 & 1\end{array} \right]
E)​ [1483014800140001]\left[ \begin{array} { c c c c } 1 & 4 & 8 & - 3 \\0 & 1 & 4 & 8 \\0 & 0 & 1 & 4 \\0 & 0 & 0 & 1\end{array} \right]
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47
​Solve the system of linear equations {4x+4y=38x20y=9\left\{ \begin{array} { l } 4 x + 4 y = 3 \\8 x - 20 y = - 9\end{array} \right. using an inverse matrix.

A)​ [xy]=[3141528]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { l } \frac { 3 } { 14 } \\\\\frac { 15 } { 28 }\end{array} \right]
B)​ [xy]=[928127]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { l } \frac { 9 } { 28 } \\\\\frac { 12 } { 7 }\end{array} \right]
C)​ [xy]=[928314]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { c } \frac { 9 } { 28 } \\\\\frac { - 3 } { 14 }\end{array} \right]
D)​ [xy]=[971528]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { c } \frac { 9 } { 7 } \\\\\frac { 15 } { 28 }\end{array} \right]
E)​ [xy]=[97314]\left[ \begin{array} { l } x \\y\end{array} \right] = \left[ \begin{array} { c } \frac { - 9 } { 7 } \\\\\frac { - 3 } { 14 }\end{array} \right]
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48
Find the inverse of the matrix.​ [152015001]\left[ \begin{array} { l l l } 1 & 5 & 2 \\0 & 1 & 5 \\0 & 0 & 1\end{array} \right]

A)​ [1523015001]\left[ \begin{array} { c c c } 1 & 5 & - 23 \\0 & 1 & 5 \\0 & 0 & 1\end{array} \right]
B)​ [1523015001]\left[ \begin{array} { c c c } - 1 & - 5 & 23 \\0 & - 1 & - 5 \\0 & 0 & - 1\end{array} \right]
C)​ [1523015001]\left[ \begin{array} { c c c } 1 & - 5 & - 23 \\0 & 1 & - 5 \\0 & 0 & 1\end{array} \right]
D)​ [1523015001]\left[ \begin{array} { l l l } 1 & 5 & 23 \\0 & 1 & 5 \\0 & 0 & 1\end{array} \right]
E)​ [1523015001]\left[ \begin{array} { c c c } 1 & - 5 & 23 \\0 & 1 & - 5 \\0 & 0 & 1\end{array} \right]
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49
Find the inverse of A.​ A=[412482001248]A = \left[ \begin{array} { c c c } - 4 & 12 & 4 \\8 & 20 & 0 \\12 & 4 & - 8\end{array} \right]

A)​ A1=136[1075412131011]A ^ { - 1 } = \frac { 1 } { 36 } \left[ \begin{array} { c c c } 10 & 7 & 5 \\4 & - 1 & 2 \\- 13 & 10 & - 11\end{array} \right]
B)​ A1=124[1075412131011]A ^ { - 1 } = \frac { 1 } { 24 } \left[ \begin{array} { c c c } 10 & 7 & 5 \\4 & 1 & 2 \\13 & 10 & 11\end{array} \right]
C)​ A1=128[1075412131011]A ^ { - 1 } = \frac { 1 } { 28 } \left[ \begin{array} { c c c } - 10 & 7 & - 5 \\4 & - 1 & 2 \\- 13 & 10 & - 11\end{array} \right]
D)​ A1=136[1075412131011]A ^ { - 1 } = \frac { 1 } { 36 } \left[ \begin{array} { c c c } - 10 & 7 & - 5 \\4 & - 1 & 2 \\- 13 & 10 & - 11\end{array} \right]
E)​ A1=128[1075412131011]A ^ { - 1 } = \frac { 1 } { 28 } \left[ \begin{array} { c c c } 10 & 7 & 5 \\4 & 1 & 2 \\13 & 10 & 11\end{array} \right]
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50
Find the inverse of the matrix.​ [4114]\left[ \begin{array} { l l } 4 & 1 \\1 & 4\end{array} \right]

A)​​ [415115115415]\left[ \begin{array} { c c } \frac { 4 } { 15 } & \frac { 1 } { 15 } \\\\\frac { 1 } { 15 } & \frac { 4 } { 15 }\end{array} \right]
B)​ [415115115415]\left[ \begin{array} { l } - \frac { 4 } { 15 } - \frac { 1 } { 15 } \\- \frac { 1 } { 15 } - \frac { 4 } { 15 }\end{array} \right]
C)​ [415115115415\left[ \begin{array} { c c } \frac { 4 } { 15 } & - \frac { 1 } { 15 } \\- \frac { 1 } { 15 } & \frac { 4 } { 15 }\end{array} \right.
D)​ [415115115415]\left[ \begin{array} { c c } - \frac { 4 } { 15 } & \frac { 1 } { 15 } \\\frac { 1 } { 15 } & - \frac { 4 } { 15 }\end{array} \right]
E)​ [41500415]\left[ \begin{array} { c c } \frac { 4 } { 15 } & 0 \\0 & \frac { 4 } { 15 }\end{array} \right]
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51
​Solve the system of linear equations {4x18x24x38x4=012x120x28x312x4=158x120x28x320x4=104x1+16x2+16x3+44x4=0\left\{ \begin{array} { l l } 4 x _ { 1 } - 8 x _ { 2 } - 4 x _ { 3 } - 8 x _ { 4 } & = 0 \\12 x _ { 1 } - 20 x _ { 2 } - 8 x _ { 3 } - 12 x _ { 4 } & = - 15 \\8 x _ { 1 } - 20 x _ { 2 } - 8 x _ { 3 } - 20 x _ { 4 } & = 10 \\- 4 x _ { 1 } + 16 x _ { 2 } + 16 x _ { 3 } + 44 x _ { 4 } & = 0\end{array} \right. using the inverse matrix 14[24712103012973212311]\frac { 1 } { 4 } \left[ \begin{array} { c c c c } - 24 & 7 & 1 & - 2 \\- 10 & 3 & 0 & - 1 \\- 29 & 7 & 3 & - 2 \\12 & - 3 & - 1 & 1\end{array} \right] .

A)​ [x1x2x3x4]=[954454754354]\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { c } \frac { - 95 } { 4 } \\\\\frac { - 45 } { 4 } \\\\\frac { - 75 } { 4 } \\\\\frac { 35 } { 4 }\end{array} \right]
B)​ [x1x2x3x4]=[054052]\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { c } 0 \\\frac { - 5 } { 4 } \\0 \\\frac { - 5 } { 2 }\end{array} \right]
C)​ [x1x2x3x4]=[4549540354]\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { c } \frac { - 45 } { 4 } \\\\\frac { - 95 } { 4 } \\\\0 \\\\\frac { 35 } { 4 }\end{array} \right]
D)​ [x1x2x3x4]=[15454052]\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { r } \frac { - 15 } { 4 } \\\frac { 5 } { 4 } \\0 \\\frac { 5 } { 2 }\end{array} \right]
E)​ [x1x2x3x4]=[354254454454]\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { c } \frac { - 35 } { 4 } \\\\\frac { - 25 } { 4 } \\\\\frac { 45 } { 4 } \\\\\frac { - 45 } { 4 }\end{array} \right]
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52
​Solve the system of linear equations {5x110x25x310x4=015x125x210x315x4=810x125x210x325x4=85x1+20x2+20x3+55x4=16\left\{ \begin{array} { l l } 5 x _ { 1 } - 10 x _ { 2 } - 5 x _ { 3 } - 10 x _ { 4 } & = 0 \\15 x _ { 1 } - 25 x _ { 2 } - 10 x _ { 3 } - 15 x _ { 4 } & = 8 \\10 x _ { 1 } - 25 x _ { 2 } - 10 x _ { 3 } - 25 x _ { 4 } & = - 8 \\- 5 x _ { 1 } + 20 x _ { 2 } + 20 x _ { 3 } + 55 x _ { 4 } & = 16\end{array} \right. using the inverse matrix 15[24712103012973212311]\frac { 1 } { 5 } \left[ \begin{array} { c c c c } - 24 & 7 & 1 & - 2 \\- 10 & 3 & 0 & - 1 \\- 29 & 7 & 3 & - 2 \\12 & - 3 & - 1 & 1\end{array} \right] .

A)​ [x1x2x3x4]=[1658585165]\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { c } \frac { 16 } { 5 } \\\\\frac { 8 } { 5 } \\\\\frac { - 8 } { 5 } \\\\\frac { - 16 } { 5 }\end{array} \right]
B)​ [x1x2x3x4]=[0850165]\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { c } 0 \\\\\frac { 8 } { 5 } \\\\0 \\\\\frac { 16 } { 5 }\end{array} \right]
C)​ [x1x2x3x4]=[1658500]\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { c } \frac { 16 } { 5 } \\\\\frac { 8 } { 5 } \\\\0 \\\\0\end{array} \right]
D)​ [x1x2x3x4]=[245850165]\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { c } \frac { 24 } { 5 } \\\\\frac { - 8 } { 5 } \\\\0 \\\\\frac { - 16 } { 5 }\end{array} \right]
E)​ [x1x2x3x4]=[24585165165]\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { c } \frac { 24 } { 5 } \\\\\frac { - 8 } { 5 } \\\\\frac { - 16 } { 5 } \\\\\frac { 16 } { 5 }\end{array} \right]
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53
Find the inverse of the matrix [36915]\left[ \begin{array} { c c } 3 & 6 \\- 9 & - 15\end{array} \right] .

A)​ 17[36915]\frac { 1 } { 7 } \left[ \begin{array} { c c } 3 & 6 \\- 9 & - 15\end{array} \right]
B)​ 13[5231]\frac { 1 } { 3 } \left[ \begin{array} { c c } - 5 & - 2 \\3 & 1\end{array} \right]
C)​ [36159]\left[ \begin{array} { c c } - 3 & - 6 \\15 & 9\end{array} \right]
D)​ [391221]\left[ \begin{array} { c c } 3 & - 9 \\12 & - 21\end{array} \right]
E)​ 113[36915]\frac { 1 } { 13 } \left[ \begin{array} { l l } - 3 & - 6 \\- 9 & 15\end{array} \right]
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54
Find the inverse of the matrix [888244032244840]\left[ \begin{array} { c c c } 8 & 8 & 8 \\24 & 40 & 32 \\24 & 48 & 40\end{array} \right] .

A)​ 18[111321332]\frac { 1 } { 8 } \left[ \begin{array} { c c c } 1 & 1 & - 1 \\- 3 & 2 & - 1 \\3 & - 3 & 2\end{array} \right]
B)​ 18[111021332]\frac { 1 } { 8 } \left[ \begin{array} { c c c } 1 & 1 & 1 \\0 & - 2 & - 1 \\3 & - 3 & 2\end{array} \right]
C)​ 8[111301332]8 \left[ \begin{array} { c c c } 1 & 1 & 1 \\- 3 & 0 & - 1 \\3 & - 3 & 2\end{array} \right]
D)​ 18[101321233]- \frac { 1 } { 8 } \left[ \begin{array} { c c c } 1 & 0 & - 1 \\- 3 & 2 & - 1 \\2 & - 3 & 3\end{array} \right]
E)​ 8[310311132]- 8 \left[ \begin{array} { c c c } 3 & 1 & 0 \\- 3 & 1 & - 1 \\1 & - 3 & 2\end{array} \right]
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55
​Use the matrix capabilities of a graphing utility to solve the following system of linear equations: {15x5y=310x+10y=620z=12\left\{ \begin{array} { c c c } 15 x - 5 y & = & 3 \\10 x + 10 y & = & 6 \\20 z & = & - 12\end{array} \right.

A)​ [xyz]=[31091035]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 3 } { 10 } \\\\\frac { 9 } { 10 } \\\\\frac { - 3 } { 5 }\end{array} \right]
B)​ [xyz]=[910035]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 9 } { 10 } \\0 \\\frac { - 3 } { 5 }\end{array} \right]
C)​ [xyz]=[31031035]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 3 } { 10 } \\\\\frac { 3 } { 10 } \\\\\frac { - 3 } { 5 }\end{array} \right]
D)​ [xyz]=[3103100]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 3 } { 10 } \\\\\frac { - 3 } { 10 } \\\\0\end{array} \right]
E)​ [xyz]=[31031035]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 3 } { 10 } \\\\\frac { 3 } { 10 } \\\\\frac { - 3 } { 5 }\end{array} \right]
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56
​Use the matrix capabilities of a graphing utility to solve the following system of linear equations:​ {14x+14y+21z=107x7y=57x+28z=20\left\{ \begin{array} { l l } - 14 x + 14 y + 21 z & = 10 \\7 x - 7 y & = - 5 \\7 x + 28 z & = 20\end{array} \right.

A)​ [xyz]=[2072570]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 20 } { 7 } \\\frac { 25 } { 7 } \\0\end{array} \right]
B)​ [xyz]=[1070157]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 10 } { 7 } \\0 \\\frac { - 15 } { 7 }\end{array} \right]
C)​ [xyz]=[15710757]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 15 } { 7 } \\\frac { 10 } { 7 } \\\frac { 5 } { 7 }\end{array} \right]
D)​ [xyz]=[57207107]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 5 } { 7 } \\\\\frac { - 20 } { 7 } \\\\\frac { 10 } { 7 }\end{array} \right]
E)​ [xyz]=[157107107]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 15 } { 7 } \\\\\frac { - 10 } { 7 } \\\\ \frac { 10 } { 7 }\end{array} \right]
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57
Find the inverse of the matrix [2154]\left[ \begin{array} { c c } - 2 & 1 \\5 & 4\end{array} \right] (if it exists).

A)​ 113[4152]\frac { 1 } { 13 } \left[ \begin{array} { c c } 4 & - 1 \\- 5 & - 2\end{array} \right]
B)​ 113[4152]- \frac { 1 } { 13 } \left[ \begin{array} { c c } 4 & - 1 \\- 5 & - 2\end{array} \right]
C)​ 113[4152]- \frac { 1 } { 13 } \left[ \begin{array} { c c } - 4 & 1 \\5 & 2\end{array} \right]
D)​ 113[2154]- \frac { 1 } { 13 } \left[ \begin{array} { c c } - 2 & 1 \\5 & 4\end{array} \right]
E)does not exist
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58
Show that B is the inverse of A.Show all your work. Show that B is the inverse of A.Show all your work.   ​
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59
​Solve the system of linear equations​ {9x+9y+9z=127x+45y+36z=327x+54y+45z=2\left\{ \begin{array} { l l } 9 x + 9 y + 9 z & = 1 \\27 x + 45 y + 36 z & = - 3 \\27 x + 54 y + 45 z & = 2\end{array} \right. ​using the inverse matrix 19[111321332]\frac { 1 } { 9 } \left[ \begin{array} { c c c } 1 & 1 & - 1 \\- 3 & 2 & - 1 \\3 & - 3 & 2\end{array} \right] .

A)​ [xyz]=[592349]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 5 } { 9 } \\\\\frac { - 2 } { 3 } \\\\\frac { 4 } { 9 }\end{array} \right]
B)​ [xyz]=[49119169]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 4 } { 9 } \\\\\frac { - 11 } { 9 } \\\\\frac { 16 } { 9 }\end{array} \right]
C)​ [xyz]=[119frac16949]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 11 } { 9 } \\\\\\frac { 16 } { 9 } \\\\\frac { - 4 } { 9 }\end{array} \right]
D)​ [xyz]=[591329]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 5 } { 9 } \\\\\frac { 1 } { 3 } \\\\\frac { - 2 } { 9 }\end{array} \right]
E)​ [xyz]=[16949119]\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 16 } { 9 } \\\\\frac { - 4 } { 9 } \\\\\frac { - 11 } { 9 }\end{array} \right]
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