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book College Algebra in Context with Applications for the Managerial, Life, and Social Sciences 3rd Edition by Ronald J Harshbarger, Lisa Yocco cover

College Algebra in Context with Applications for the Managerial, Life, and Social Sciences 3rd Edition by Ronald J Harshbarger, Lisa Yocco

Edition 3ISBN: 032157060X
book College Algebra in Context with Applications for the Managerial, Life, and Social Sciences 3rd Edition by Ronald J Harshbarger, Lisa Yocco cover

College Algebra in Context with Applications for the Managerial, Life, and Social Sciences 3rd Edition by Ronald J Harshbarger, Lisa Yocco

Edition 3ISBN: 032157060X
Exercise 23
Step-by-step solution
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Step 1 of 2

Consider the inequality <div class=answer> Consider the inequality . Let us solve this inequality both algebraically and graphically. To solve this inequality, first multiply both sides by the least common denominator 10. Remove parentheses by distributive property. Subtract from both sides. Add 5 to both sides. Divide both sides by 28. Thus, the algebraic solution of the inequality is . .

Let us solve this inequality both algebraically and graphically.

To solve this inequality, first multiply both sides by the least common denominator 10.

<div class=answer> Consider the inequality . Let us solve this inequality both algebraically and graphically. To solve this inequality, first multiply both sides by the least common denominator 10. Remove parentheses by distributive property. Subtract from both sides. Add 5 to both sides. Divide both sides by 28. Thus, the algebraic solution of the inequality is .

<div class=answer> Consider the inequality . Let us solve this inequality both algebraically and graphically. To solve this inequality, first multiply both sides by the least common denominator 10. Remove parentheses by distributive property. Subtract from both sides. Add 5 to both sides. Divide both sides by 28. Thus, the algebraic solution of the inequality is . Remove parentheses by distributive property.

<div class=answer> Consider the inequality . Let us solve this inequality both algebraically and graphically. To solve this inequality, first multiply both sides by the least common denominator 10. Remove parentheses by distributive property. Subtract from both sides. Add 5 to both sides. Divide both sides by 28. Thus, the algebraic solution of the inequality is . Subtract <div class=answer> Consider the inequality . Let us solve this inequality both algebraically and graphically. To solve this inequality, first multiply both sides by the least common denominator 10. Remove parentheses by distributive property. Subtract from both sides. Add 5 to both sides. Divide both sides by 28. Thus, the algebraic solution of the inequality is . from both sides.

<div class=answer> Consider the inequality . Let us solve this inequality both algebraically and graphically. To solve this inequality, first multiply both sides by the least common denominator 10. Remove parentheses by distributive property. Subtract from both sides. Add 5 to both sides. Divide both sides by 28. Thus, the algebraic solution of the inequality is .

<div class=answer> Consider the inequality . Let us solve this inequality both algebraically and graphically. To solve this inequality, first multiply both sides by the least common denominator 10. Remove parentheses by distributive property. Subtract from both sides. Add 5 to both sides. Divide both sides by 28. Thus, the algebraic solution of the inequality is . Add 5 to both sides.

<div class=answer> Consider the inequality . Let us solve this inequality both algebraically and graphically. To solve this inequality, first multiply both sides by the least common denominator 10. Remove parentheses by distributive property. Subtract from both sides. Add 5 to both sides. Divide both sides by 28. Thus, the algebraic solution of the inequality is .

<div class=answer> Consider the inequality . Let us solve this inequality both algebraically and graphically. To solve this inequality, first multiply both sides by the least common denominator 10. Remove parentheses by distributive property. Subtract from both sides. Add 5 to both sides. Divide both sides by 28. Thus, the algebraic solution of the inequality is . Divide both sides by 28.

Thus, the algebraic solution of the inequality <div class=answer> Consider the inequality . Let us solve this inequality both algebraically and graphically. To solve this inequality, first multiply both sides by the least common denominator 10. Remove parentheses by distributive property. Subtract from both sides. Add 5 to both sides. Divide both sides by 28. Thus, the algebraic solution of the inequality is . is <div class=answer> Consider the inequality . Let us solve this inequality both algebraically and graphically. To solve this inequality, first multiply both sides by the least common denominator 10. Remove parentheses by distributive property. Subtract from both sides. Add 5 to both sides. Divide both sides by 28. Thus, the algebraic solution of the inequality is . .

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College Algebra in Context with Applications for the Managerial, Life, and Social Sciences 3rd Edition by Ronald J Harshbarger, Lisa Yocco
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