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book College Algebra in Context with Applications for the Managerial, Life, and Social Sciences 3rd Edition by Ronald J Harshbarger, Lisa Yocco cover

College Algebra in Context with Applications for the Managerial, Life, and Social Sciences 3rd Edition by Ronald J Harshbarger, Lisa Yocco

النسخة 3الرقم المعياري الدولي: 032157060X
book College Algebra in Context with Applications for the Managerial, Life, and Social Sciences 3rd Edition by Ronald J Harshbarger, Lisa Yocco cover

College Algebra in Context with Applications for the Managerial, Life, and Social Sciences 3rd Edition by Ronald J Harshbarger, Lisa Yocco

النسخة 3الرقم المعياري الدولي: 032157060X
تمرين 22
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الخطوة 1 من3

a. Steps to create a scatter plot to identify the best model by using a graphing utility.

1. Set     <div class=answer> a. Steps to create a scatter plot to identify the best model by using a graphing utility. 1. Set   corresponds to the year 1960 2. Set the window of the scatter plot as   3. Use table graph feature and enter the corresponding tabular values as shown below: <table style=border-collapse:collapse; border=1>     <tbody>      <tr>       <td>   </td>       <td>   </td>       <td>   </td>       <td>   </td>      </tr>      <tr>       <td> 0 </td>       <td> 180.671 </td>       <td> 35 </td>       <td> 263.044 </td>      </tr>      <tr>       <td> 5 </td>       <td> 194.303 </td>       <td> 38 </td>       <td> 270.561 </td>      </tr>      <tr>       <td> 10 </td>       <td> 205.052 </td>       <td> 40 </td>       <td> 281.422 </td>      </tr>      <tr>       <td> 15 </td>       <td> 215.973 </td>       <td> 43 </td>       <td> 294.043 </td>      </tr>      <tr>       <td> 20 </td>       <td> 227.726 </td>       <td> 65 </td>       <td> 358.030 </td>      </tr>      <tr>       <td> 25 </td>       <td> 238.466 </td>       <td> 90 </td>       <td> 408.695 </td>      </tr>      <tr>       <td> 30 </td>       <td> 249.948 </td>       <td> </td>       <td> </td>      </tr>     </tbody>    </table> corresponds to the year 1960

2. Set the window of the scatter plot as     <div class=answer> a. Steps to create a scatter plot to identify the best model by using a graphing utility. 1. Set   corresponds to the year 1960 2. Set the window of the scatter plot as   3. Use table graph feature and enter the corresponding tabular values as shown below: <table style=border-collapse:collapse; border=1>     <tbody>      <tr>       <td>   </td>       <td>   </td>       <td>   </td>       <td>   </td>      </tr>      <tr>       <td> 0 </td>       <td> 180.671 </td>       <td> 35 </td>       <td> 263.044 </td>      </tr>      <tr>       <td> 5 </td>       <td> 194.303 </td>       <td> 38 </td>       <td> 270.561 </td>      </tr>      <tr>       <td> 10 </td>       <td> 205.052 </td>       <td> 40 </td>       <td> 281.422 </td>      </tr>      <tr>       <td> 15 </td>       <td> 215.973 </td>       <td> 43 </td>       <td> 294.043 </td>      </tr>      <tr>       <td> 20 </td>       <td> 227.726 </td>       <td> 65 </td>       <td> 358.030 </td>      </tr>      <tr>       <td> 25 </td>       <td> 238.466 </td>       <td> 90 </td>       <td> 408.695 </td>      </tr>      <tr>       <td> 30 </td>       <td> 249.948 </td>       <td> </td>       <td> </td>      </tr>     </tbody>    </table>

3. Use table graph feature and enter the corresponding tabular values as

shown below:

    <div class=answer> a. Steps to create a scatter plot to identify the best model by using a graphing utility. 1. Set   corresponds to the year 1960 2. Set the window of the scatter plot as   3. Use table graph feature and enter the corresponding tabular values as shown below: <table style=border-collapse:collapse; border=1>     <tbody>      <tr>       <td>   </td>       <td>   </td>       <td>   </td>       <td>   </td>      </tr>      <tr>       <td> 0 </td>       <td> 180.671 </td>       <td> 35 </td>       <td> 263.044 </td>      </tr>      <tr>       <td> 5 </td>       <td> 194.303 </td>       <td> 38 </td>       <td> 270.561 </td>      </tr>      <tr>       <td> 10 </td>       <td> 205.052 </td>       <td> 40 </td>       <td> 281.422 </td>      </tr>      <tr>       <td> 15 </td>       <td> 215.973 </td>       <td> 43 </td>       <td> 294.043 </td>      </tr>      <tr>       <td> 20 </td>       <td> 227.726 </td>       <td> 65 </td>       <td> 358.030 </td>      </tr>      <tr>       <td> 25 </td>       <td> 238.466 </td>       <td> 90 </td>       <td> 408.695 </td>      </tr>      <tr>       <td> 30 </td>       <td> 249.948 </td>       <td> </td>       <td> </td>      </tr>     </tbody>    </table>

    <div class=answer> a. Steps to create a scatter plot to identify the best model by using a graphing utility. 1. Set   corresponds to the year 1960 2. Set the window of the scatter plot as   3. Use table graph feature and enter the corresponding tabular values as shown below: <table style=border-collapse:collapse; border=1>     <tbody>      <tr>       <td>   </td>       <td>   </td>       <td>   </td>       <td>   </td>      </tr>      <tr>       <td> 0 </td>       <td> 180.671 </td>       <td> 35 </td>       <td> 263.044 </td>      </tr>      <tr>       <td> 5 </td>       <td> 194.303 </td>       <td> 38 </td>       <td> 270.561 </td>      </tr>      <tr>       <td> 10 </td>       <td> 205.052 </td>       <td> 40 </td>       <td> 281.422 </td>      </tr>      <tr>       <td> 15 </td>       <td> 215.973 </td>       <td> 43 </td>       <td> 294.043 </td>      </tr>      <tr>       <td> 20 </td>       <td> 227.726 </td>       <td> 65 </td>       <td> 358.030 </td>      </tr>      <tr>       <td> 25 </td>       <td> 238.466 </td>       <td> 90 </td>       <td> 408.695 </td>      </tr>      <tr>       <td> 30 </td>       <td> 249.948 </td>       <td> </td>       <td> </td>      </tr>     </tbody>    </table>

    <div class=answer> a. Steps to create a scatter plot to identify the best model by using a graphing utility. 1. Set   corresponds to the year 1960 2. Set the window of the scatter plot as   3. Use table graph feature and enter the corresponding tabular values as shown below: <table style=border-collapse:collapse; border=1>     <tbody>      <tr>       <td>   </td>       <td>   </td>       <td>   </td>       <td>   </td>      </tr>      <tr>       <td> 0 </td>       <td> 180.671 </td>       <td> 35 </td>       <td> 263.044 </td>      </tr>      <tr>       <td> 5 </td>       <td> 194.303 </td>       <td> 38 </td>       <td> 270.561 </td>      </tr>      <tr>       <td> 10 </td>       <td> 205.052 </td>       <td> 40 </td>       <td> 281.422 </td>      </tr>      <tr>       <td> 15 </td>       <td> 215.973 </td>       <td> 43 </td>       <td> 294.043 </td>      </tr>      <tr>       <td> 20 </td>       <td> 227.726 </td>       <td> 65 </td>       <td> 358.030 </td>      </tr>      <tr>       <td> 25 </td>       <td> 238.466 </td>       <td> 90 </td>       <td> 408.695 </td>      </tr>      <tr>       <td> 30 </td>       <td> 249.948 </td>       <td> </td>       <td> </td>      </tr>     </tbody>    </table>

    <div class=answer> a. Steps to create a scatter plot to identify the best model by using a graphing utility. 1. Set   corresponds to the year 1960 2. Set the window of the scatter plot as   3. Use table graph feature and enter the corresponding tabular values as shown below: <table style=border-collapse:collapse; border=1>     <tbody>      <tr>       <td>   </td>       <td>   </td>       <td>   </td>       <td>   </td>      </tr>      <tr>       <td> 0 </td>       <td> 180.671 </td>       <td> 35 </td>       <td> 263.044 </td>      </tr>      <tr>       <td> 5 </td>       <td> 194.303 </td>       <td> 38 </td>       <td> 270.561 </td>      </tr>      <tr>       <td> 10 </td>       <td> 205.052 </td>       <td> 40 </td>       <td> 281.422 </td>      </tr>      <tr>       <td> 15 </td>       <td> 215.973 </td>       <td> 43 </td>       <td> 294.043 </td>      </tr>      <tr>       <td> 20 </td>       <td> 227.726 </td>       <td> 65 </td>       <td> 358.030 </td>      </tr>      <tr>       <td> 25 </td>       <td> 238.466 </td>       <td> 90 </td>       <td> 408.695 </td>      </tr>      <tr>       <td> 30 </td>       <td> 249.948 </td>       <td> </td>       <td> </td>      </tr>     </tbody>    </table>

0

180.671

35

263.044

5

194.303

38

270.561

10

205.052

40

281.422

15

215.973

43

294.043

20

227.726

65

358.030

25

238.466

90

408.695

30

249.948


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الخطوة 3 من 3

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College Algebra in Context with Applications for the Managerial, Life, and Social Sciences 3rd Edition by Ronald J Harshbarger, Lisa Yocco
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