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book College Algebra in Context with Applications for the Managerial, Life, and Social Sciences 3rd Edition by Ronald J Harshbarger, Lisa Yocco cover

College Algebra in Context with Applications for the Managerial, Life, and Social Sciences 3rd Edition by Ronald J Harshbarger, Lisa Yocco

النسخة 3الرقم المعياري الدولي: 032157060X
book College Algebra in Context with Applications for the Managerial, Life, and Social Sciences 3rd Edition by Ronald J Harshbarger, Lisa Yocco cover

College Algebra in Context with Applications for the Managerial, Life, and Social Sciences 3rd Edition by Ronald J Harshbarger, Lisa Yocco

النسخة 3الرقم المعياري الدولي: 032157060X
تمرين 8
الحلول خطوة بخطوة
موثّق
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الخطوة 1 من12

Consider the table. The table represents the prison time by multiplying the probabilities of being arrested.

Year

x

Expected prison time (days)

y

1970

10.1

1980

10.6

1985

13.2

1990

18.0

1992

18.5

1993

17.2

1994

19.5

1995

20.2

1996

21.7

(a)

Let    <div class=answer> Consider the table. The table represents the prison time by multiplying the probabilities of being arrested. <table style=border-collapse:collapse; border=1>     <tbody>      <tr>       <td> Year <i>x</i> </td>       <td> Expected prison time (days) <i>y</i> </td>      </tr>      <tr>       <td> 1970 </td>       <td> 10.1 </td>      </tr>      <tr>       <td> 1980 </td>       <td> 10.6 </td>      </tr>      <tr>       <td> 1985 </td>       <td> 13.2 </td>      </tr>      <tr>       <td> 1990 </td>       <td> 18.0 </td>      </tr>      <tr>       <td> 1992 </td>       <td> 18.5 </td>      </tr>      <tr>       <td> 1993 </td>       <td> 17.2 </td>      </tr>      <tr>       <td> 1994 </td>       <td> 19.5 </td>      </tr>      <tr>       <td> 1995 </td>       <td> 20.2 </td>      </tr>      <tr>       <td> 1996 </td>       <td> 21.7 </td>      </tr>     </tbody>    </table> (a) Let   represents the 1960,   represents 1970and so on. To find the linear model enter the data in graphing calculator as follows. Use TI – 84 graphing calculator to find the linear regression curve. Enter the table of values first. Step 1 : First press   and select the   option by pressing 1 from the displayed menu. Next, enter the each value in L1 followed by pressing the enter key and enter the corresponding <i>x </i>value in L2 followed by pressing the enter key. The output will be displayed as shown:       represents the 1960,     <div class=answer> Consider the table. The table represents the prison time by multiplying the probabilities of being arrested. <table style=border-collapse:collapse; border=1>     <tbody>      <tr>       <td> Year <i>x</i> </td>       <td> Expected prison time (days) <i>y</i> </td>      </tr>      <tr>       <td> 1970 </td>       <td> 10.1 </td>      </tr>      <tr>       <td> 1980 </td>       <td> 10.6 </td>      </tr>      <tr>       <td> 1985 </td>       <td> 13.2 </td>      </tr>      <tr>       <td> 1990 </td>       <td> 18.0 </td>      </tr>      <tr>       <td> 1992 </td>       <td> 18.5 </td>      </tr>      <tr>       <td> 1993 </td>       <td> 17.2 </td>      </tr>      <tr>       <td> 1994 </td>       <td> 19.5 </td>      </tr>      <tr>       <td> 1995 </td>       <td> 20.2 </td>      </tr>      <tr>       <td> 1996 </td>       <td> 21.7 </td>      </tr>     </tbody>    </table> (a) Let   represents the 1960,   represents 1970and so on. To find the linear model enter the data in graphing calculator as follows. Use TI – 84 graphing calculator to find the linear regression curve. Enter the table of values first. Step 1 : First press   and select the   option by pressing 1 from the displayed menu. Next, enter the each value in L1 followed by pressing the enter key and enter the corresponding <i>x </i>value in L2 followed by pressing the enter key. The output will be displayed as shown:       represents 1970and so on.

To find the linear model enter the data in graphing calculator as follows.

Use TI – 84 graphing calculator to find the linear regression curve.

Enter the table of values first.

Step 1: First press    <div class=answer> Consider the table. The table represents the prison time by multiplying the probabilities of being arrested. <table style=border-collapse:collapse; border=1>     <tbody>      <tr>       <td> Year <i>x</i> </td>       <td> Expected prison time (days) <i>y</i> </td>      </tr>      <tr>       <td> 1970 </td>       <td> 10.1 </td>      </tr>      <tr>       <td> 1980 </td>       <td> 10.6 </td>      </tr>      <tr>       <td> 1985 </td>       <td> 13.2 </td>      </tr>      <tr>       <td> 1990 </td>       <td> 18.0 </td>      </tr>      <tr>       <td> 1992 </td>       <td> 18.5 </td>      </tr>      <tr>       <td> 1993 </td>       <td> 17.2 </td>      </tr>      <tr>       <td> 1994 </td>       <td> 19.5 </td>      </tr>      <tr>       <td> 1995 </td>       <td> 20.2 </td>      </tr>      <tr>       <td> 1996 </td>       <td> 21.7 </td>      </tr>     </tbody>    </table> (a) Let   represents the 1960,   represents 1970and so on. To find the linear model enter the data in graphing calculator as follows. Use TI – 84 graphing calculator to find the linear regression curve. Enter the table of values first. Step 1 : First press   and select the   option by pressing 1 from the displayed menu. Next, enter the each value in L1 followed by pressing the enter key and enter the corresponding <i>x </i>value in L2 followed by pressing the enter key. The output will be displayed as shown:       and select the    <div class=answer> Consider the table. The table represents the prison time by multiplying the probabilities of being arrested. <table style=border-collapse:collapse; border=1>     <tbody>      <tr>       <td> Year <i>x</i> </td>       <td> Expected prison time (days) <i>y</i> </td>      </tr>      <tr>       <td> 1970 </td>       <td> 10.1 </td>      </tr>      <tr>       <td> 1980 </td>       <td> 10.6 </td>      </tr>      <tr>       <td> 1985 </td>       <td> 13.2 </td>      </tr>      <tr>       <td> 1990 </td>       <td> 18.0 </td>      </tr>      <tr>       <td> 1992 </td>       <td> 18.5 </td>      </tr>      <tr>       <td> 1993 </td>       <td> 17.2 </td>      </tr>      <tr>       <td> 1994 </td>       <td> 19.5 </td>      </tr>      <tr>       <td> 1995 </td>       <td> 20.2 </td>      </tr>      <tr>       <td> 1996 </td>       <td> 21.7 </td>      </tr>     </tbody>    </table> (a) Let   represents the 1960,   represents 1970and so on. To find the linear model enter the data in graphing calculator as follows. Use TI – 84 graphing calculator to find the linear regression curve. Enter the table of values first. Step 1 : First press   and select the   option by pressing 1 from the displayed menu. Next, enter the each value in L1 followed by pressing the enter key and enter the corresponding <i>x </i>value in L2 followed by pressing the enter key. The output will be displayed as shown:       option by pressing 1 from the displayed menu.

Next, enter the each value in L1 followed by pressing the enter key and enter the corresponding x value in L2 followed by pressing the enter key.

The output will be displayed as shown:

    <div class=answer> Consider the table. The table represents the prison time by multiplying the probabilities of being arrested. <table style=border-collapse:collapse; border=1>     <tbody>      <tr>       <td> Year <i>x</i> </td>       <td> Expected prison time (days) <i>y</i> </td>      </tr>      <tr>       <td> 1970 </td>       <td> 10.1 </td>      </tr>      <tr>       <td> 1980 </td>       <td> 10.6 </td>      </tr>      <tr>       <td> 1985 </td>       <td> 13.2 </td>      </tr>      <tr>       <td> 1990 </td>       <td> 18.0 </td>      </tr>      <tr>       <td> 1992 </td>       <td> 18.5 </td>      </tr>      <tr>       <td> 1993 </td>       <td> 17.2 </td>      </tr>      <tr>       <td> 1994 </td>       <td> 19.5 </td>      </tr>      <tr>       <td> 1995 </td>       <td> 20.2 </td>      </tr>      <tr>       <td> 1996 </td>       <td> 21.7 </td>      </tr>     </tbody>    </table> (a) Let   represents the 1960,   represents 1970and so on. To find the linear model enter the data in graphing calculator as follows. Use TI – 84 graphing calculator to find the linear regression curve. Enter the table of values first. Step 1 : First press   and select the   option by pressing 1 from the displayed menu. Next, enter the each value in L1 followed by pressing the enter key and enter the corresponding <i>x </i>value in L2 followed by pressing the enter key. The output will be displayed as shown:           <div class=answer> Consider the table. The table represents the prison time by multiplying the probabilities of being arrested. <table style=border-collapse:collapse; border=1>     <tbody>      <tr>       <td> Year <i>x</i> </td>       <td> Expected prison time (days) <i>y</i> </td>      </tr>      <tr>       <td> 1970 </td>       <td> 10.1 </td>      </tr>      <tr>       <td> 1980 </td>       <td> 10.6 </td>      </tr>      <tr>       <td> 1985 </td>       <td> 13.2 </td>      </tr>      <tr>       <td> 1990 </td>       <td> 18.0 </td>      </tr>      <tr>       <td> 1992 </td>       <td> 18.5 </td>      </tr>      <tr>       <td> 1993 </td>       <td> 17.2 </td>      </tr>      <tr>       <td> 1994 </td>       <td> 19.5 </td>      </tr>      <tr>       <td> 1995 </td>       <td> 20.2 </td>      </tr>      <tr>       <td> 1996 </td>       <td> 21.7 </td>      </tr>     </tbody>    </table> (a) Let   represents the 1960,   represents 1970and so on. To find the linear model enter the data in graphing calculator as follows. Use TI – 84 graphing calculator to find the linear regression curve. Enter the table of values first. Step 1 : First press   and select the   option by pressing 1 from the displayed menu. Next, enter the each value in L1 followed by pressing the enter key and enter the corresponding <i>x </i>value in L2 followed by pressing the enter key. The output will be displayed as shown:

    <div class=answer> Consider the table. The table represents the prison time by multiplying the probabilities of being arrested. <table style=border-collapse:collapse; border=1>     <tbody>      <tr>       <td> Year <i>x</i> </td>       <td> Expected prison time (days) <i>y</i> </td>      </tr>      <tr>       <td> 1970 </td>       <td> 10.1 </td>      </tr>      <tr>       <td> 1980 </td>       <td> 10.6 </td>      </tr>      <tr>       <td> 1985 </td>       <td> 13.2 </td>      </tr>      <tr>       <td> 1990 </td>       <td> 18.0 </td>      </tr>      <tr>       <td> 1992 </td>       <td> 18.5 </td>      </tr>      <tr>       <td> 1993 </td>       <td> 17.2 </td>      </tr>      <tr>       <td> 1994 </td>       <td> 19.5 </td>      </tr>      <tr>       <td> 1995 </td>       <td> 20.2 </td>      </tr>      <tr>       <td> 1996 </td>       <td> 21.7 </td>      </tr>     </tbody>    </table> (a) Let   represents the 1960,   represents 1970and so on. To find the linear model enter the data in graphing calculator as follows. Use TI – 84 graphing calculator to find the linear regression curve. Enter the table of values first. Step 1 : First press   and select the   option by pressing 1 from the displayed menu. Next, enter the each value in L1 followed by pressing the enter key and enter the corresponding <i>x </i>value in L2 followed by pressing the enter key. The output will be displayed as shown:


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College Algebra in Context with Applications for the Managerial, Life, and Social Sciences 3rd Edition by Ronald J Harshbarger, Lisa Yocco
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