Vinegar is a solution of acetic acid,HC₂H₃O₂ ,dissolved in water.A 5.54-g sample of vinegar was Vneutralized by 30.10 mL of 0.100 M NaOH.What is the percent by weight of acetic acid in the vinegar? A)0.0543% B)1.08% C)3.26% D)5.43% E)9.23%

Question

Quizplus · Accepted Answer

To find the percent by weight of acetic acid in the vinegar, we need to first find the number of moles of NaOH used to neutralize the acetic acid in the vinegar. From the balanced chemical equation for the reaction between acetic acid and NaOH, we know that 1 mole of acetic acid will react with 1 mole of NaOH: HC₂H₃O₂ + NaOH → NaC₂H₃ + H2O₂ So the number of moles of NaOH used is equal to the number of moles of acetic acid in the vinegar: 0.100 mol/L × 0.03010 L = 0.00301 mol NaOH used 0.00301 mol NaOH used = 0.00301 mol acetic acid in vinegar Next, we need to find the mass of acetic acid in the vinegar, using the molar mass of acetic acid: molar mass of acetic acid = 2(1.01 g/mol + 12.01 g/mol) + 16.00 g/mol = 60.05 g/mol mass of acetic acid in vinegar = 0.00301 mol × 60.05 g/mol = 0.180 g Finally, we can calculate the percent by weight of acetic acid in the vinegar: percent by weight of acetic acid = (mass of acetic acid / mass of vinegar) × 100% percent by weight of acetic acid = (0.180 g / 5.54 g) × 100% = 3.25% The closest answer choice is C, 3.26%.

Vinegar Is a Solution of Acetic Acid,HC2H3O2 ,Dissolved in Water

Vinegar Is a Solution of Acetic Acid,HC₂H₃O₂ ,Dissolved in Water